Q. There's a natural number that becomes equal to the square of a natural number when 100 is added to it and to the square of another natural number when 169 is added to it. Find the number.
learn2like SaysQ. There's a natural number that becomes equal to the square of a natural number when 100 is added to it and to the square of another natural number when 169 is added to it. Find the number.
This has already been solved here:
http://www.pagalguy.com/forum/quantitative-questions-and-answers/43728-number-system-ii-12.html#post1646863
learn2like SaysQ. There's a natural number that becomes equal to the square of a natural number when 100 is added to it and to the square of another natural number when 169 is added to it. Find the number.
N+100 = a^2
N + 169 = b^2
b^2 - a^2 = 69 = > (b+a)(b-a) = 23*3
we get b = 13 and a = 10. or b = 35 and a = 34
we get N = 1056
Someone please answer my questions:
Q11)a number xy is multiplied by another no ab and the result comes as pqr, where r=2y, q=2(x+y) and p=2x where x,y11
13
31
22
Q12) denotes the greatest integer value just below x and {x} its fractional value. The sum of ^3 and{x}^2 is -7.91. find x.
-2.03
-1.97
-2.97
-1.7
Thanks.
1)
take x = y = 1
p = q = r = even no
pqr = XQX form which can be 242 , 484 ....
so 22 will only satisfy
2)
solve by options
-1.7 = -2 + .3
-2 ^ 3 + .3 ^2 = -8 + .09 = 7.91 so ans option d
Thanks.
Someone please answer my questions:
Q11)a number xy is multiplied by another no ab and the result comes as pqr, where r=2y, q=2(x+y) and p=2x where x,y11
13
31
22
(10x+y)*(10a+b)= 100ax+10(ay+bx)+by
= 100p + 10q + r
hence on solving ab=22
Someone please answer my questions:
Q12) denotes the greatest integer value just below x and {x} its fractional value. The sum of ^3 and{x}^2 is -7.91. find x.
-2.03
-1.97
-2.97
-1.7
Thanks.
As the number is negative then ^ 3 must be negative as {x} ^2 cant be negative. The nearest integer for -7.91 is -8. Hence the integral part is () -2. Hence the number must be -1.ab... type. Now we need 0.09 for {x}2. Hence {x} must be 0.3. Hence the number is -1.7.
Tell me if this helps.
had a few doubts in no. system frm arun sharma:
1.(32^32^32)/9 leaves a remainder of :
a.4 B.7 c.1 d.2
2.find the gcd of no.s 2n+13 and n+7
a.1 b.2 c.3 d.4 e.5
3.remiander of 2^2+22^2+222^2.....(222.........49twos)^2 divided by 9:
4.N=202 X 20002 X 200000002 X2000....(31 zereoz)2. find sum of digits of multiplication:
a.112 b.160 c.144 d.cant be determined
had a few doubts in no. system frm arun sharma:
2.find the gcd of no.s 2n+13 and n+7
a.1 b.2 c.3 d.4 e.5
answer. a. 1
4.N=202 X 20002 X 200000002 X2000....(31 zereoz)2. find sum of digits of multiplication:
a.112 b.160 c.144 d.cant be determined
what do u mean by sum of digits of multiplication plz xplain
crushkiller Sayswhat do u mean by sum of digits of multiplication plz xplain :shocked:
It means that you need to find the sum of digits of the result that you get after multiplying.
Like 4x9 = 36, sum of digits is 9
had a few doubts in no. system frm arun sharma:
2.find the gcd of no.s 2n+13 and n+7
a.1 b.2 c.3 d.4 e.5
2n+13 = 2 ( n+7) - 1
If we put x + 7 = y then we need to find out GCD of y and 2y-1 which should be 1.
Hi guys i need help for the following questions:
1) 2 planes are moving along circle of circumference 1.2 km with constant speed. when they move in different directions they meet every 15 secs and when they move in same direction one plane overtakes other every 60 secs. find the speed of the slower plane
1) 0.04km/s 2) 0.03 km/s 3) 0.05 km/s 4) 0.02 km/s
2) karim leaves ellora on a bicycle,havinng travelled 1.5 hrs at 16 km/h, he makes a stop for 1.5 hr and then pedals on with same speed.4 hrs after karim started his friend rahim leaves ellora on motorcycle and rides with a speed of 28 km/h in same direction of karim.what distance will they cover before rahim overtakes karim.
1) 88 km 2)90.33 km 3) 93.33 km 4) none of these
Hi guys i need help for the following questions:
2) karim leaves ellora on a bicycle,havinng travelled 1.5 hrs at 16 km/h, he makes a stop for 1.5 hr and then pedals on with same speed.4 hrs after karim started his friend rahim leaves ellora on motorcycle and rides with a speed of 28 km/h in same direction of karim.what distance will they cover before rahim overtakes karim.
1) 88 km 2)90.33 km 3) 93.33 km 4) none of these
When Rahim starts, distance travelled by Karim is
16*1.5+0*1.5+1*16= 40km
If Rahim catches him after time t then
16*t + 40 = 28*t
=> t = 40/12
Hence distance travelled by Rahim = 28*40/12 = 280/3 = 93.33
Ans is 3) 93.33
Hi guys i need help for the following questions:
1) 2 planes are moving along circle of circumference 1.2 km with constant speed. when they move in different directions they meet every 15 secs and when they move in same direction one plane overtakes other every 60 secs. find the speed of the slower plane
1) 0.04km/s 2) 0.03 km/s 3) 0.05 km/s 4) 0.02 km/s
Suppose v1 and v2 are the speeds with v1 > v2 in Km/s
given,
(v1+v2) * 15 = 1.2
(v1-v2) * 60 = 1.2
hence
v1 + v2 = 4 ( v1-v2)
=> v1 = (5/3) v2
Hence [ (5/3) v2 - v2 ] * 60= 1.2
=> (2/3) v2 * 60 = 1.2
=> v2 = 1.2/40 = 0.03km/s
Hence 2) 0.03 km/s is the answer
1.(32^32^32)/9 leaves a remainder of :
a.4 B.7 c.1 d.2
Ans d.2
32^32^32 = (2^5)^32^32/9 leaves a remainder of 2.
is it necessary to do ny book e.g. arun sharma?? i mean are the time material mock cats and simcats suffice, for the the prep 4 quantz?
Hi All,
I have a question related to Time and Speed topic of Arun sharma. The question is in LOD-2. Question number being 33.
Questn: Ravi caught a train for home earlier than usual yesterday.His wife picks him up everyday. But yesterday, he set out on foot to meet his wife on the way.He reached home 12 mins earlier than he would if he had waited for his wife at station.The car travels at uniform speed which is 5 times Ravi's speed on foot. Ravi reached home at 6 o ' clock. At what time would he have reached home if his wife, forewarned of his plan, had met him at station.
Plz provide the explanation for the same.
Hi All,
I have a question related to Time and Speed topic of Arun sharma. The question is in LOD-2. Question number being 33.
Questn: Ravi caught a train for home earlier than usual yesterday.His wife picks him up everyday. But yesterday, he set out on foot to meet his wife on the way.He reached home 12 mins earlier than he would if he had waited for his wife at station.The car travels at uniform speed which is 5 times Ravi's speed on foot. Ravi reached home at 6 o ' clock. At what time would he have reached home if his wife, forewarned of his plan, had met him at station.
Plz provide the explanation for the same.
Suppose speed of Ravi is v and he walked for time t mins.
speed of Ravi's wife = 5v.
from first condition ravi saved 12 mins by walking. it means that if he has covered distance d then his wife would have covered 2d (going from the meeting point to the station and coming back) in 12 mins.
hence (2 * v * t)/ 5v = 12 mins => t = 30 mins.
It means ravi has walked for 30 mins. this distance can be covered by his wife in car in 30/5 = 6 mins.
hence if his wife was at station when ravi arrived, they could have saved 30-6 = 24 mins and he could have reached by 5:36 o'clock.
what is the write answer.
q1. one side of the staircase is to be closed in by rectangular planks from the floor to each step. the width of each plank is 9 inches and their height are successively 6 inch, 12 inches, 18 inches and so on. there are 24 planks required in total. find the area in square feet.
a)112.5 b)107 c)118.5 d) none of these
ans a
q2. the sum of the first n terms of the AP is equal to half the sum of the next n terms of he same progression. find the ratio of the sum of the first 3n terms of the progression to the sum of its 1st n terms
a) 5 b)6 c)7 d)8 e)9
ans d
q3. a sq. has a side of 40 cm. another sq. is formed by joining the mid-points of the sides of the given sq. and this process is repeated infinitely. find the perimetre of all the squares thus formed.
a) 160(1 + sqrt2) b) 160(2 + sqrt2) c)160(2 - sqrt 2) d) 160(1-sqrt2) e) 160(3 - sqrt2)
ans b
q2. the sum of the first n terms of the AP is equal to half the sum of the next n terms of he same progression. find the ratio of the sum of the first 3n terms of the progression to the sum of its 1st n terms
a) 5 b)6 c)7 d)8 e)9
ans d
I am getting 6 as the answer.