i have a problem in d question:
Find the greatest number of 4 digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainders resp.
answer is 9893.
i couldn't understand the point of remainders. I calculated the greatest number divisible by these numbers, i.e. 9900.Can anyone explain how to procede further ?
i have a problem in d question:
Find the greatest number of 4 digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainders resp.
answer is 9893.
i couldn't understand the point of remainders. I calculated the greatest number divisible by these numbers, i.e. 9900.Can anyone explain how to procede further ?
Since the negative remainders are same The number will be of the form LCM (10, 11, 15, and 22)* x-7 LCM=330 Largest four digit number of the form 330x-7 =330*30-7 =9893 Hope it solves your doubt
Hi.you see in the above question the difference "a" between divisor and the remainder is always the same.so the ans to your ques will be "LCM of all the divisors -a"
Abhinav007_jain SaysHi.you see in the above question the difference "a" between divisor and the remainder is always the same.so the ans to your ques will be "LCM of all the divisors -a"
but i wanted to ask what if a question arises in which this difference "a" is not same always. How will we solve such question ?
hi abhay
read the sol'n u have given, couldnt understand it completely, can u help me wid it??????
saru421 Saysbut i wanted to ask what if a question arises in which this difference "a" is not same always. How will we solve such question ?
Then you need to use chinese remainder theorem
Another question i m not able to solve:
Find the greatest number which will divide 215, 167 and 135 so as to leave the same remainder in each case.
Answer is 16.
Another question i m not able to solve:
Find the greatest number which will divide 215, 167 and 135 so as to leave the same remainder in each case.
Answer is 16.
Its the HCF of (215-167),(167-135),(215-135)
HCF of (32,48,80)
= 16.
i thinkit should be 6 and not 4. check it out again.
Probably u are missing sth
i thinkit should be 6 and not 4. check it out again.
Probably u are missing sth
Which question you are refering to?? plz make it a point to quote whichever post you are refeing to, its troublesome to locate otherwise..!
Its the HCF of (215-167),(167-135),(215-135)
HCF of (32,48,80)
= 16.
hi Shivani
Could u explain the sol'n u have given for the above problem
hi.shivani SaysWhich question you are refering to?? plz make it a point to quote whichever post you are refeing to, its troublesome to locate otherwise..!
referin to
remainder wen 25^102/17?
what should be the answer?
even i wanted to ask if u could please explain this solution.
Its the HCF of (215-167),(167-135),(215-135)
HCF of (32,48,80)
= 16.
even i wanted to ask if u could plz explain this solution.
referin to
remainder wen 25^102/17?
what should be the answer?
8^102/17 2^306/17 (2^4)^76*2^2/17 =(-1)^76*4 hence remainder is 4
referin to
remainder wen 25^102/17?
What should be the answer?
25^102/17
=^102/17
=8^102/17
e(17)=16
8^102/17
=2^306/17
=(2^16)^19.2^2/17
= 1.4/17
=4
Doubts....
1)Find the 28383rd term of the series :123456789101112....
Options: 3,4,9,7....I m getting 3 as answer while the ans is 9...
2)M is a two digit number which has the property that:the product of factorials of its digit>sum of factorials of its digits.How many values of M exist?
Options:56,64,63,none of these...
I am getting 64 as ans while the book says its 63...
3)Define a number K such that it is the sum of the squares of the first M natural numbers(i.e. K=1^2 +2^2 +..+M^2) where MOptions:10,11,12,None of these...
I got the 1st one but the other 2 seems to be out of reach
Ans1 9.
I got the 1st one but the other 2 seems to be out of reach
Ans1 9.
Ans1. 9
Ans2. 63
Did not get the 3rd one. if anybody gets it, please do post the answer
Now try to solve this:(it's interesting)
In how many ways one or more of 5 different letters be posted to 4 different letter boxes?
I will post the answer later..
Good luck!!
4^5 Ways in total. and 4^5-1 ways if the letters have to be posted in the wrong boxes
I am doing this book currently.
So how does this thread work? I post my question, or I check whether its been answered already?? 