Quant by Arun Sharma

MBA CAT 2024
1354
What is the sum of all 5 digit numbers which can be formed with the digits 4,3,2,1,0 without repetition?

Have a try..Good luck..


first position can be occupied by 4,3,2,1

4*4*3*2*1 = 4*4! = 96 numbers

sum of these 96 number is

4!(1000+2000+3000 + 4000) + 3*3!(111+222+333+444)

24(10000) + 18(1110)

259980
1355
What is the sum of all 5 digit numbers which can be formed with the digits 4,3,2,1,0 without repetition?

Have a try..Good luck..

there is a short cut ...its 4! * ( 4+3+2+1) * (11111) = 240 * 11111 = 2666640.

pls tell me if this is the ans?
1356

Can someone explain ?

The infinite sequence a1, a2,, an, is such that a1 = 2, a2 = -3, a3 = 5, a4 = -1, and an = an-4 for n > 4. What is the sum of the first 97 terms of the sequence?
A. 72
B. 74
C. 75
D. 78
E. 80

1357
Can someone explain ?

The infinite sequence a1, a2,, an, is such that a1 = 2, a2 = -3, a3 = 5, a4 = -1, and an = an-4 for n > 4. What is the sum of the first 97 terms of the sequence?
A. 72
B. 74
C. 75
D. 78
E. 80

here a1=a5,a2=a6 and so on thus make groups of 4.
a1+a2+a3+a4=2-3+5-1=3

now u get 24 groups as we need to find the sum of 97 no.s so 3*24 and then a 2 that remains.
so ans is 72+2=74

24 from ..

hope m right...finally..
1358
here a1=a5,a2=a6 and so on thus make groups of 4.
a1+a2+a3+a4=2-3+5-1=4

now u get 24 groups as we need to find the sum of 97 no.s so 3*24 and then a 2 that remains.
so ans is 72+2=74

24 from ..

hope m right...finally..

I guess your answe is correct but coudlnt understand the method.First of all a1+a2+a3+a4=2-3+5-1 which equals 3 and not 4

Also if we make group of fours then 96/4 will 24 groups

so we will do 24*3 =72 and then we will have a97 left which is 2 so the total will be 72+2=74 so ur ans is correct but m not sure about the method
1359

Looks like you have edited your post 😐

1360
I guess your answe is correct but coudlnt understand the method.First of all a1+a2+a3+a4=2-3+5-1 which equals 3 and not 4

Also if we make group of fours then 96/4 will 24 groups

so we will do 24*3 =72 and then we will have a97 left which is 2 so the total will be 72+2=74 so ur ans is correct but m not sure about the method

ya corrected the 4...do u have any easier method?
1361

Doubts....
1)Find the 28383rd term of the series :123456789101112....
Options: 3,4,9,7....I m getting 3 as answer while the ans is 9...

2)M is a two digit number which has the property that:the product of factorials of its digit>sum of factorials of its digits.How many values of M exist?
Options:56,64,63,none of these...
I am getting 64 as ans while the book says its 63...

3)Define a number K such that it is the sum of the squares of the first M natural numbers(i.e. K=1^2 +2^2 +..+M^2) where MOptions:10,11,12,None of these...

1362

What is the remainder when 25^102 is divided by 17.?

There is no explanation for this in Arun Sharma-Quant book.

I tried but ended with a different answer. Can anybody help me out this.?

1363
What is the remainder when 25^102 is divided by 17.?

There is no explanation for this in Arun Sharma-Quant book.

I tried but ended with a different answer. Can anybody help me out this.?


Is the answer -> 4

Here is the explaination :

(25^102)/17
= (8^102)/17
= (64^51)/17
= 13*(13^50)/17
= 13*(169^25)/17
= 13*(16^25)/17
= 13*16*(256^12)/17
= 13*16*1
= 208/17
= 4
1364
there is a short cut ...its 4! * ( 4+3+2+1) * (11111) = 240 * 11111 = 2666640.

pls tell me if this is the ans?

This is wrong answer.. as you have also incorporated the numbers satrting with zero. Please check MaskedMenace's solution or substract the sum of all 4 digit numbers having no zeros..

Your approach will hold good if there is no zero's and all numbers are diifferent
1365

please send me the material too

1366
vikram.mukhi Says
please send me the material too [email protected]


dude pls remove your mail id from the post.....its against the rules of the forum.
you can PM to the person to whom you are addressing.
1368

Can anybody explain me the worked out example on page 324 (Geometry)..
--i think it will result in a cone but nt able to get the other two sides.

1369

also i wanted to ask about the same question (pg-324, solved geometry ques11.1) that why "volume" is being calculated here.. though the question asks for maximum possible area.. ??

1370
Can anybody explain me the worked out example on page 324 (Geometry)..
--i think it will result in a cone but nt able to get the other two sides.

i've problem with the same question
1371

i have a small doubt....problem 1.7 pg 7.... its written there that.. 123! can be written in the form of 4n...plz explain how?

1372
learn2like Says
i have a small doubt....problem 1.7 pg 7.... its written there that.. 123! can be written in the form of 4n...plz explain how?

Factorial of any no. greater than 4 will always have 4 in it. So even 5! can be written as 4n, where n is 30. Thus, 123! can also be written as 4n
1373

Oh...thanks a lot....

1374
learn2like Says
Oh...thanks a lot....

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