Quant by Arun Sharma

@ramirez said:
Q) The cost of manufacturing a car is made up of three items: cost of material, labour and overheads. In a year, the cost of these items were in the ratio 4:3:2. Next year, the cost of material rose by 10%, cost of labour increased by 8%, but the overheads reduced by 5%. Find the increase per cent in the price of the car. (ans is increase in price of car in percent = 44/9%)thanks in advance : )
old ratio 4:3:2
new ratio 1.1*4:1.08*3:.95*2
=>4.4:3.24:1.80
so change in cost is (4.4+3.24+1.90)-(4+3+2) = .54
%age change is .54*100/(4+3+2)=54/9=6%

@ramirez how u got 44/9%
@sonic_boom yeah i tried to solve exactly like you even i got 6% but the book mentions it as 44/9 %

may be the answer given is incorrect : ) thanks for being so helpful

@ein_ziel thanks : )

this was my approach increase in price=4*10+3*8-2*5=54
% increase in price over previous ratio =54/(4+3+2)
=54/9
=6%

@ramirez said:
may be the answer given is incorrect : ) thanks for being so helpful
yeah seems like printing mistake
@sonic_boom yeah it seems so : )
@sonic_boom : yes, Arun Sharma's book has many such mistakes .. incorrect answers ! :)
@ramirez said:
this was my approach increase in price=4*10+3*8-2*5=54% increase in price over previous ratio =54/(4+3+2) =54/9 =6%
yup thats correct...
@sonic_boom thanks : )
A trader uses a weight 920 g instead of 1 kg and sells the articles at the marked price which is 15% above the cost price..Find the profit percentage
@Raghu5jan said:
A trader uses a weight 920 g instead of 1 kg and sells the articles at the marked price which is 15% above the cost price..Find the profit percentage
25%?
@Raghu5jan said:
A trader uses a weight 920 g instead of 1 kg and sells the articles at the marked price which is 15% above the cost price..Find the profit percentage
Ans: 25%
Take values. CP of 1kg =100 say
CP of .92kg = Rs.92
MP =115
qty sold at 115 = 920g, cp of which is Rs.92

@Raghu5jan Let 1g=1 Re so he makes a profit of rs 80 on rs 920 worth article and also above that he has marked the price 15 % more so his final SP = 1.15 x (1000/920) x CP so his profit % = [1.15 x (1000/920) - 1] x 100 (sorry dnt feel like doing the calculations 😁 )
@Raghu5jan said:
A trader uses a weight 920 g instead of 1 kg and sells the articles at the marked price which is 15% above the cost price..Find the profit percentage
let 1000gm = Rs 1000 (since price is not given)
now profit when selling at selling price is 15% of 1000 = 150
and he sells 920gm instead of 1000gm or he sells item costing Rs 920 at 1150
so total profit is (150+80)/920= .25
25%
@sonic_boom said:
let 1000gm = Rs 1000 (since price is not given)now profit when selling at selling price is 15% of 1000 = 150and he sells 920gm instead of 1000gm or he sells item costing Rs 920 at 1150so total profit is (150+80)/920= .2525%
thanks dude 😃
@ramirez @Raghu5jan This can be solved in a easier way. Since the speed is reduced by 1/8, the time would increase by 1/7, which is equal to 15 min. hence the actual time taken is 15 * 7 min or 7/4 hrs. Multiply this by the speed (40) and u wud get the answer 70 km!!
Hey,can someone give me the link to download 'Quantitative Ability for Cat' by Arun Sharma ebook. Please I need it urgently.

Or can someone foward me the ebook at : [email protected]

Thanks in advance.


A cask contains 12 gallons of mixture of wine and water in the ratio 3:1. How much of the mixture must be drawn off and water substituted, so that wine and water in the cask become half and half. Thanks in advance 😃

12 Gallons of wine and water(3:1 ratio) => 9 gallons wine and 3 gallons water.

Say X gallons is withdrawn => 3X/4 gallons of wine and X/4 gallons of water.

Remaining : Wine => 9 - (3X/4) water => 3-(X/4)

Add X gallons of water => Wine = 9-(3X/4) water = 3 - (x/4) + x


9-(3x/4) = 3-(3x/4)

On solving this we get x=4.