Chapter Percentages, Ques no. 46 LOD1:
In an exam, 80% students passed in physics, 70% in chemistry while 15% failed in both the subjects. If 325 students passed in both the subjects, find the total number of students who appeared in both the exam.
a)500
b)400
c)300
d)600
Ans: a
My question is how to get the percentage of students who passed in both the subjects ? TIA
@sonic_boom said: Chapter Percentages, Ques no. 46 LOD1: In an exam, 80% students passed in physics, 70% in chemistry while 15% failed in both the subjects. If 325 students passed in both the subjects, find the total number of students who appeared in both the exam. a)500 b)400 c)300 d)600Ans: aMy question is how to get the percentage of students who passed in both the subjects ? TIA 325/500
@arumugadas may b i quoted my question wrong.
(% of student passed in both) x (total students) = 325
how do i get % of student who pased in both
(% of student passed in both) x (total students) = 325
how do i get % of student who pased in both
@sonic_boom said: @arumugadas may b i quoted my question wrong. (% of student passed in both) x (total students) = 325 how do i get % of student who pased in both 325/500 * 100= 65% passed in both
(400+interest for one yr)+400 = 808
Find value of
(2^Log 3 7 - 7^ log 3 2) ?
(2^Log 3 7 - 7^ log 3 2) ?
Alligations - Q 23
There are two kinds of alloys of the tin and copper. The first alloy contains tin and copper such that 93.33% of it is tin. In the second alloy there is 86.66% tin. What weight of the first alloy should be mixed with some weight of second alloy so as to make a 50 kg mass containing 90% of tin?
@pandeyn said: Alligations - Q 23There are two kinds of alloys of the tin and copper. The first alloy contains tin and copper such that 93.33% of it is tin. In the second alloy there is 86.66% tin. What weight of the first alloy should be mixed with some weight of second alloy so as to make a 50 kg mass containing 90% of tin?
Got it done using options. Earlier I thought question is incomplete because of word "some". :)
plz solve dis one.....................
A pedestrian left point A for a walk , going with the speed of 5 km/h .When the pedestrian was at a distance of 6 km from A, a cyclist followed him ,starting from A and cycling at a speed 9 km/h higher than that of of the pedestrian.When the cyclist overtook the pedestrian , they turned back and returned to A together at the speed of 4 km/h.At what speed will the time spent by the pedestrian on his journey from A to A be the least
a 5
b 6
c.6.1
d 5.5
a 5
b 6
c.6.1
d 5.5
@Rshmi05 said:plz solve dis one.....................
A pedestrian left point A for a walk , going with the speed of 5 km/h .When the pedestrian was at a distance of 6 km from A, a cyclist followed him ,starting from A and cycling at a speed 9 km/h higher than that of of the pedestrian.When the cyclist overtook the pedestrian , they turned back and returned to A together at the speed of 4 km/h.At what speed will the time spent by the pedestrian on his journey from A to A be the least a 5 b 6 c.6.1 d 5.5
1. Firstly while covering '6 kms' from point A the pedestrian spends 72 minutes or 6/5 hrs.
2. Then cyclist travelling at 14km/hr (9 more than speed of pedestrian) will be able to catch the pedestrian after 40 minutes or 2/3hrs. (which is 6kms/9kmphr)
3. Total distance covered by the cyclist till it reaches the pedestrian is 14*(2/3) = 28/3 Kms.
4. Now time taken by both of them to reach point at at 4km/hr will be= ((28/3)/4) = 7/3hrs.
So the total time spent by the pedestrian will be (6/5)+(2/3)+(7/3) = 31/5 =6.2 hrs.
minimum time spent should not be equal to or greater than 6.2, so among the option the answer should be 6.1.
A dishonest milkman purchased milk at Rs.10 per litre & mixed 5 litres of water in it.By selling the ,mixture at the rate of Rs.10 per litre he earns a profit of 25%.The quantity of amount of mixture he had was ?
@AbhiCAT2012 The total mixture was 25 litres out of which 20 litres were milk and 5 litres of water.
@
If he is making 25 percent profit by selling the mixture at Rs10/l then he selling 800ml of milk and 200ml of water in the mixture.
So the ratio of milk to water in the misture is 4:1.
If water is 5ls then milk is 20ls and thus the mixture is 25 ls.
@techsurge
@techsurge said: Could anyone help me with this. Its from Arun Sharma's Probability LOD 3Probabilities that Rajesh passes in Maths, Physics and Chemistry are m, p and c respectively. Of theses subjects, Rajesh has a 75% chance of passing , in at least two and 40% chance of passing in exactly two. Find which of the following is true?a) p+m+c =19/20 b)p+m+c = 27/20 c)pmc = 1/20 d)pmc =1/8I did not get even using the hintThe answer is "b" I dont understand what "p+m+c" exactly representsthanx in advance
The answer is actually pmc=1/10. The options are incorrect in your editon of book. You can get answer from here
http://www.pagalguy.com/forums/quantitative-ability-and-di/probability-question-t-5738/p-107858?page=5
http://www.pagalguy.com/forums/quantitative-ability-and-di/probability-question-t-5738/p-107858?page=5
@abhinavsing3103 said:minimum time spent should not be equal to or greater than 6.2, so among the option the answer should be 6.1.
is your answer 6.1 hrs?
Isnt the Qn asking "At which of the following SPEEDs time taken will be least?"
Chapter : Probability : LOD 3 : A problem in maths solved by A,B ,C .P(A)=1/2;P(B)=1/3;P(C)=1/4.What is the prob of the prob being solved? Please help