Quant by Arun Sharma

MBA CAT 2024
5386

four sisters S ,T ,U ,V playing a game such that the loser doubles the money of each of the other player.they played four games and each sister lost one game in alphabetical order .At the end of fourth game each sister had Rs32.

a)who started with lowest amount?
b)who started with highest amount?
c)what was the amountwith "U" at the end of second game?
d)how many rupees did "S" start with?
5387

Find the number of zeros in 1^1 X 2^2 X 3^3...........X 98^98 X 99^99 X 100^100?

please explain...

5388

@[592869:amannarang7] the answer is 1300

5389
@amannarang7 said: Find the number of zeros in 1^1 X 2^2 X 3^3...........X 98^98 X 99^99 X 100^100? please explain...
We look for highest power of 5s in the given expression.

The terms contributing 5s are: 5^5, 10^10, 15^15, .... ,100^100

=> (5 + 10 + 15 + ... + 100) + (25 + 50 + 75 + 100) ---> Second bracket term contains extra contributions from terms like 25^25, 50^50.... which are composed of 2 powers of 5

Total = 1050 + 250 = 1300
5390

@[592869:amannarang7] in order to find the number of zeroa, we will calculate number of pairs of (5*2). since number of 2's will always be greater than number of 2's in such cases. so calculate the number of 5's. this is done like this:-
5 +10+15+20+ (25+25) + 30+35+40+45+ (50+50) +55+60+65+70+ (75+75) 80+85+90+95+ (100+100) = 1300

5391
@rohitnkali said: which is the least number that must b subtracted from 1856 so that remainder when divided by 7,12,16 will same remainder four. pls do rply me with the answers
176
5392

A passenger train left town alpha for town beta. At the same time a goods train left beta for alpha. The speed of each train is constant throughout the whole trip. Two hours after the trains met, they were 450 km apart. The passenger train arrived at the place of destination 16 hours after their meeting and goods train, 25 hours after their meting. How long did it take the passenger train to make the whole trip.?

5393

@[576399:pushpita121] 36 hrs goods train 45hrs .. respective speeds 125 and 100 kmph


A x 16 = B x t
B x 25 = A x t

where A,B speeds of the trains ... t time taken for them to meet initially At and Bt would we distances travelled by the respective trains before meeeting and also the distances to be travelled by the other train after meeting from these eqns A/B can be found and rest of the problem is straight forward
5394

hiii can you give the detailed sol plz..

5395
Time and Work Questions

Q.1 Two pipes A and B can fill up a half tank in 1.2 hours.The tank was initially empty. Pipe B was kept open for half the time required by pipe A to fill the tank by itself.Then, pipe A was kept for as much time as was required by pipe B to fill up 1/3 of the tank by itself.It was found that the tank then was 5/6 full.The least time in which any of the pipes can fill the tank fully is
a.> 4.8 hrs b.> 4 hrs c.> 3.6 hrs d.> 6 hrs

Q.2 Two men and a women are entrusted with a task. The second man needs three hours more to cope with the job than the second man and the woman would need working together. The first man, working alone, would need as much time as the second man and the woman working together. The first man, working alone, would spend eight hours less than the double period of time the second man would spend working alone. How much time would the two men and the women need to complete the task if they all worked together?
5396
@rohitnkali said: which is the least number that must b subtracted from 1856 so that remainder when divided by 7,12,16 will same remainder four. pls do rply me with the answers
answer is 172??
5397
@yashasvi5 said: Time and Work Questions Q.1 Two pipes A and B can fill up a half tank in 1.2 hours.The tank was initially empty. Pipe B was kept open for half the time required by pipe A to fill the tank by itself.Then, pipe A was kept for as much time as was required by pipe B to fill up 1/3 of the tank by itself.It was found that the tank then was 5/6 full.The least time in which any of the pipes can fill the tank fully isa.> 4.8 hrs b.> 4 hrs c.> 3.6 hrs d.> 6 hrs Q.2 Two men and a women are entrusted with a task. The second man needs three hours more to cope with the job than the second man and the woman would need working together. The first man, working alone, would need as much time as the second man and the woman working together. The first man, working alone, would spend eight hours less than the double period of time the second man would spend working alone. How much time would the two men and the women need to complete the task if they all worked together?

1/A+1/B=1/2.4=5/12

A/2B+B/3A=5/6

Solving these two ,which took some time..
got A=24/5 , then B=24/5
A=4 then B=6
So least time will be 4 hours

5398
@rohitnkali said: four sisters S ,T ,U ,V playing a game such that the loser doubles the money of each of the other player.they played four games and each sister lost one game in alphabetical order .At the end of fourth game each sister had Rs32.a)who started with lowest amount?b)who started with highest amount?c)what was the amountwith "U" at the end of second game?d)how many rupees did "S" start with?
S T U V

end of 4th round 32 32 32 32

beg of 4th round 16 16 16 80


end of 3rd round 16 16 16 80

beg of 3rd round 8 8 72 40


end of 2nd round 8 8 72 40

beg of 2nd round 4 68 36 20


end of 1st round 4 68 36 20

beg of 1st round 66 34 18 10



S lost in first round ,followed by T,U and V

A)V started with lowest amount
B)S started with highest amt
C)72
D)66

Hope im right ..but this would be the way to proceed(from last step and building up towards first step)









5399

the petrol price shot up by 7% as a result of the hike in the price of crudes. the price of petrol before hike was Rs 28 per litre. Vawal travels 2400 km every month and his car gives a mileage of 18 kms to a litre. find da increase in da expenditure that vawal has to incur due to the increase in the price of the petrol.

Rs 270
Rs 276
Rs 262
Rs 272
need solution... plz help!!
5400
@swahamohapatra said:the petrol price shot up by 7% as a result of the hike in the price of crudes. the price of petrol before hike was Rs 28 per litre. Vawal travels 2400 km every month and his car gives a mileage of 18 kms to a litre. find da increase in da expenditure that vawal has to incur due to the increase in the price of the petrol.Rs 270Rs 276Rs 262Rs 272need solution... plz help!!
price of petrol initially=28
price of petrol after hike=28*107/100
Petrol reqd every month =2400/18 =400/3
increase in expenditure= (400/3)*28*107/100 - (400/3)*28
Approximately 262
5401

i have some questions in ratio nd proportion..

1) if (a^2+c^2)/(a+c)= (b^2+c^2)/(b+c)=k and a not =b then which of the following is equal to k?
A) a+c
B) b+c
C) a+b
D) a-c

2) if (p+q)/r=(q+r)/p=(p+r)/q=k then find the sum of all the possible values of k?

3) the ratio of the prices of tea last year and this year is 5:6. the ratio of the prices of coffee last year and this year is 7:8. the sum of the prices of a kg of tea and a kg of coffee this year is Rs.48. find the prices of tea(in rupees) last year if it was 20/21 of the price of coffee last year.

5402
@dreamonfire said: i have some questions in ratio nd proportion.. 1) if (a^2+c^2)/(a+c)= (b^2+c^2)/(b+c)=k and a not =b then which of the following is equal to k?A) a+cB) b+cC) a+bD) a-c 2) if (p+q)/r=(q+r)/p=(p+r)/q=k then find the sum of all the possible values of k? 3) the ratio of the prices of tea last year and this year is 5:6. the ratio of the prices of coffee last year and this year is 7:8. the sum of the prices of a kg of tea and a kg of coffee this year is Rs.48. find the prices of tea(in rupees) last year if it was 20/21 of the price of coffee last year.
1)
Given the ratios, multiply the second ratio by -1 and add to the first ratio, and this result will also be equal to k. By this method, I am getting k = a+b

2)
Add up all the ratios, the result will be equal to k, and that value is 2, given p+q+r not equal to 0.
If p+q+r = 0, then k = -1, so sum of all possible values = 2 + (-1) = 1

3) let the prices last year be 5x, 7y and this year be 6x, 8y. So, from the last line, we get 3x = 4y. From the third line, we get 3x+4y = 24 => x =4, y = 3, and hence the ans = 5x = 20.
5403

@[592846:YouMadFellow] thanku..i got it!! =D

5404

ques..

what is the remainder..33^34^35/7..?
5405
@jainakshay92 said: ques..what is the remainder..33^34^35/7..?
Is the answer = 2 ?