Quant by Arun Sharma

hemant89 Says
can you please explain the last two question in more detail. I didn't get it.


9x+100a+10b+c/10=A1

9x+100c+10b+a/10=A2

now it is given that average increased by 29.7

so A2=A1+29.7
solving c-a will come out to be 3.

hence 3 is the answer.
hemant89 Says
Please just don't just give the answer, i'v answer key in my book too.


ok,sorry buddy......
I will remember it from next time!!:grin:

BTW explanation for both the questions had already been given by ZIDDI ARMAN bhai.:grin:

A ques 4 all...

Q- How many ordered triple (a,b,c) are there such that LCM (a,b)= 1000; LCM (b,c)= 2000; LCM (c,a)= 2000 ?



Options are :
a) 45 b) 70 c) 85 d) 90

The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?

Options: 12, 32, 42, 52 and 23

The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?

Options: 12, 32, 42, 52 and 23



32 is the answer
let number be a+10b
a^2+b^2 =13 it is given

b+10a = a+10b-9
b-a = 1
put the value of b = a+1 in above equation

u will get number 32...
Hey puys can you clear the concept of mine for this 2 Ques..

1. 32^32^32/9 will leave remainder; choices 4 7 1 2
2. 32^32^32/7 will leave remainder: choices 4 2 1 3 5

(32)^32^32
=> (8^32^32) * (4^32^32)

(i). When we divide, (8 )^32^32 by 9, we will get 1 as a remainder.
(ii). In the case of, (4)^32^32 divided by 9, we see that 32^32 is not divisible by 3, and we get 1 as a remainder.
So, 32^32 can be written as 3m+1.
So, when (4)^3m+1 is divided by 9, we get...
R{(4)^3m+1/9}
= R{(4)^3m/9 * (4)^1/9}
= R{64^m/9 * 4/9}
= (1)^m * 4
= 4

so our final remainder will be,
= Remainder in case(i) * Remainder in case (ii)
= 1*4
= 4
The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?

Options: 12, 32, 42, 52 and 23

13 can be written in the terms of the sum of two square numbers only in two types...
13= (4+9) or (9+4)
so number can be 23 or 32.
when we substract 9 from both the numbers, we get 14 and 23 resp.
so 32 is the answer.
NITISH NEGI Says
a man sells chocolates that come in boxes. Either full boxes or half a box of chocolates can be bought from him. A customer comes and buys half the number of boxes the seller has plus half a box. A second customer comes and buys half the remaining number of boxes plus half a box. After this,the seller is left with no chocolates box. How many chocolates boxes did the seller have before the first customer came?

X=(X+1)/2 + (1/2) + ((X-1)/4)

which gives us X=3
is 3 the answer?
The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?

Options: 12, 32, 42, 52 and 23


32 hoga bhai....
9x+100a+10b+c/10=A1

9x+100c+10b+a/10=A2

now it is given that average increased by 29.7

so A2=A1+29.7
solving c-a will come out to be 3.

hence 3 is the answer.

thanks for the explanation, also what about this question, i didn't get this one too.

Q . In an organizaation , the daily average wages of 20 illiterate employees is decreased from Rs. 25 to Rs. 10, thus the average salary of all the literate and illiterate employees is decreased by 10 per day. The no. of educated employees working in the organization are:

1. Find the last two digits of the following number:
(201*202*203*204*246*247*248*249)^2

2. From a number M subtract 1. Take the reciprocal of the result to get the value of 'N'. Then which of the following is necessarily true?
a. M^N b. M^N > 3
c. 1 d. 1

1. Find the last two digits of the following number:
(201*202*203*204*246*247*248*249)^2



76?

Approach:

To find the last two digit of any numbers,take last 2 digits of each number and multiply

This way,the last two digit of 201*202*203*204*246*247*248*249 is 76

And 76^even always ends in 76 itself;)



2. From a number M subtract 1. Take the reciprocal of the result to get the value of 'N'. Then which of the following is necessarily true?
a. M^N b. M^N > 3
c. 1 d. 1

Option C

Approach:

As N always be fraction,M^N takes positive values with maximum of 3

Q . In an organizaation , the daily average wages of 20 illiterate employees is decreased from Rs. 25 to Rs. 10, thus the average salary of all the literate and illiterate employees is decreased by 10 per day. The no. of educated employees working in the organization are:


10?

Total wages for 20 illiterate before decrease = 20*25 = 500

After decrease,it becomes 20*10 = 200

In total,Rs.300 is reduced which is also equal to 10/head

so,30 employee in total and 10 among them are educated

is answer 160

can nybdy explain the following problem with proper soln,,,

N=202*20002*200000002*200...2(15zeros) * 2000.......2(31zeros). sum of digit in this multiplication will be :
112; 160; 144; can't be determined??

############common u people ...solve the problem yar.. Estaller whr are you... waiting 4 the past 3-4 days to get the damn soln..of above problem..


is answer 160??

There is a question in PnC..

There are 4 sections in an exam paper.Each section has a maximum of 45 marks.Find he number of ways in which a student can qualify if the qualifying marks is 90

1. 36546
2. 6296
3. 64906
4. none of these

Guys pls explain d approach to solve dis I knw it's easy to solve through options but I want to knw d approach thru equations

Represent the number 1.25 as product of three positive factors so that the product of first factor by the square of second is equal to 5 if we have to get the lowest possible sum of three factors
A)x1=2.25,x2=5 x3=0.2
B)x1=1.25,x2=4 x3=4.5
C)x1=1.25,x2=2 x3=0.5
D)x1=1.25,x2=4 x3=2
E)none of these

Is the ans. 3 ?

Regards,
Never Back Down


yeah, the answer is 3 😃

two alarm clocks ring their alarms at regular intervals of 50 seconds and 48 seconds. If they first beep together at 12 noon, at what time will they beep again for the first time?

X=(X+1)/2 + (1/2) + ((X-1)/4)

which gives us X=3
is 3 the answer?


yeah, 3 is the answer.