The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?
The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?
Options: 12, 32, 42, 52 and 23
32 is the answer let number be a+10b a^2+b^2 =13 it is given
b+10a = a+10b-9 b-a = 1 put the value of b = a+1 in above equation
(i). When we divide, (8 )^32^32 by 9, we will get 1 as a remainder. (ii). In the case of, (4)^32^32 divided by 9, we see that 32^32 is not divisible by 3, and we get 1 as a remainder. So, 32^32 can be written as 3m+1. So, when (4)^3m+1 is divided by 9, we get... R{(4)^3m+1/9} = R{(4)^3m/9 * (4)^1/9} = R{64^m/9 * 4/9} = (1)^m * 4 = 4
so our final remainder will be, = Remainder in case(i) * Remainder in case (ii) = 1*4 = 4
The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?
Options: 12, 32, 42, 52 and 23
13 can be written in the terms of the sum of two square numbers only in two types... 13= (4+9) or (9+4) so number can be 23 or 32. when we substract 9 from both the numbers, we get 14 and 23 resp. so 32 is the answer.
a man sells chocolates that come in boxes. Either full boxes or half a box of chocolates can be bought from him. A customer comes and buys half the number of boxes the seller has plus half a box. A second customer comes and buys half the remaining number of boxes plus half a box. After this,the seller is left with no chocolates box. How many chocolates boxes did the seller have before the first customer came?
The sum of the squares of the digits constituting a positive two digit number is 13. If we subtract 9 from that number, we shall get a number written by the same digits in the reverse order. Find the number?
thanks for the explanation, also what about this question, i didn't get this one too.
Q . In an organizaation , the daily average wages of 20 illiterate employees is decreased from Rs. 25 to Rs. 10, thus the average salary of all the literate and illiterate employees is decreased by 10 per day. The no. of educated employees working in the organization are:
1. Find the last two digits of the following number: (201*202*203*204*246*247*248*249)^2
2. From a number M subtract 1. Take the reciprocal of the result to get the value of 'N'. Then which of the following is necessarily true? a. M^N b. M^N > 3 c. 1 d. 1
1. Find the last two digits of the following number: (201*202*203*204*246*247*248*249)^2
76?
Approach:
To find the last two digit of any numbers,take last 2 digits of each number and multiply
This way,the last two digit of 201*202*203*204*246*247*248*249 is 76
And 76^even always ends in 76 itself;)
2. From a number M subtract 1. Take the reciprocal of the result to get the value of 'N'. Then which of the following is necessarily true? a. M^N b. M^N > 3 c. 1 d. 1
Option C
Approach:
As N always be fraction,M^N takes positive values with maximum of 3
Q . In an organizaation , the daily average wages of 20 illiterate employees is decreased from Rs. 25 to Rs. 10, thus the average salary of all the literate and illiterate employees is decreased by 10 per day. The no. of educated employees working in the organization are:
10?
Total wages for 20 illiterate before decrease = 20*25 = 500
After decrease,it becomes 20*10 = 200
In total,Rs.300 is reduced which is also equal to 10/head
so,30 employee in total and 10 among them are educated
There are 4 sections in an exam paper.Each section has a maximum of 45 marks.Find he number of ways in which a student can qualify if the qualifying marks is 90
Guys pls explain d approach to solve dis I knw it's easy to solve through options but I want to knw d approach thru equations
Represent the number 1.25 as product of three positive factors so that the product of first factor by the square of second is equal to 5 if we have to get the lowest possible sum of three factors A)x1=2.25,x2=5 x3=0.2 B)x1=1.25,x2=4 x3=4.5 C)x1=1.25,x2=2 x3=0.5 D)x1=1.25,x2=4 x3=2 E)none of these
two alarm clocks ring their alarms at regular intervals of 50 seconds and 48 seconds. If they first beep together at 12 noon, at what time will they beep again for the first time?