hii...i m facing problem in averages question no: 29 LODIII.....:wow:
pungu Sayshii...i m facing problem in averages question no: 29 LODIII.....:wow:
kindly post the question....:|
a team of miners planed to mine 1800 tons of ore durinng a ceratain number of days.due to technical problem in one third of the planned number of days,team was able to achieve an output of 20 tons of ore less than the planned output,to make for this,team over achieved for rest of days by 20 tons.result was that team completed the task one day ahead of time.how many tons of ore did the team intitaly plan to ore per day.
a team of miners planed to mine 1800 tons of ore durinng a ceratain number of days.due to technical problem in one third of the planned number of days,team was able to achieve an output of 20 tons of ore less than the planned output,to make for this,team over achieved for rest of days by 20 tons.result was that team completed the task one day ahead of time.how many tons of ore did the team intitaly plan to ore per day.......
help me guyz...
i am also going to start from percentage so prepare for it .
Hi everybody...................
I am stucked in these question please solve these with explaination.....
Study the following tables and answer the questions that follows.
The tables are attached........
Question 1: Given this situation, the minimum number of days in which the company can launch a new toy going through all the stages is :
a) 40 days b)40.5 days c)45 days d)44 days
2:If A and C refuse to have anythiong to do with the manufacturing setup. The number of days by which the project will get delayed will be:
a) 5 days b) 4 days c) 3 days d) 6 days
Question 3: If each of the five work is equally valued at Rs 10000, maximum amount will be recieved by:
a) A b) C c) D d) E e) B
Question 4: In question 3 minimum amount will be recieved by:
a) A b) C c) D d) E e) B
Question 5: If C works at 90.909% efficiency during marketing and launch, who will be highest paid among all five:
a) A b) C c) D d) E e) B
Question 6: If the company decides that the first 4 works can be started simultaneously and the experts will be allocated to their respective work area only and a work will be done by a non-expert only if the work in his area of expertise is completed then the expert who will first be assisted in his work will be ( assume that marketing and launch can be done only after the first 4 are fully completed)
a) A b) C c) D d) E e) B
Question7: For question 6 , the minimum number of days in which the whole project will be completed ( assume everything is utilized efficiently all the time, and no-body is utilized in a work that he refuse to work upon)
a) 22.5 days b) 15 days c) 24.75 days d) 25.25 days
Question 8: For ouestion 6 , highest earning willbe for...
a) A b) both B and D c) C d) E e) can not be determined
question 9: If each of the workhas an equal payment of Rs. 10000 the lowest earning for the above situation will be for
a) A b) E c) C d) B e) can not be determined
Question 10: The value for the earning for the highest earning person,(If the data for question 6-9 is accurate) will be....
a) 19312.5 b) 13250 c) 12875 d)b e) Can not be determined
I am stucked in these question please solve these with explaination.....
Study the following tables and answer the questions that follows.
The tables are attached........
Question 1: Given this situation, the minimum number of days in which the company can launch a new toy going through all the stages is :
a) 40 days b)40.5 days c)45 days d)44 days
2:If A and C refuse to have anythiong to do with the manufacturing setup. The number of days by which the project will get delayed will be:
a) 5 days b) 4 days c) 3 days d) 6 days
Question 3: If each of the five work is equally valued at Rs 10000, maximum amount will be recieved by:
a) A b) C c) D d) E e) B
Question 4: In question 3 minimum amount will be recieved by:
a) A b) C c) D d) E e) B
Question 5: If C works at 90.909% efficiency during marketing and launch, who will be highest paid among all five:
a) A b) C c) D d) E e) B
Question 6: If the company decides that the first 4 works can be started simultaneously and the experts will be allocated to their respective work area only and a work will be done by a non-expert only if the work in his area of expertise is completed then the expert who will first be assisted in his work will be ( assume that marketing and launch can be done only after the first 4 are fully completed)
a) A b) C c) D d) E e) B
Question7: For question 6 , the minimum number of days in which the whole project will be completed ( assume everything is utilized efficiently all the time, and no-body is utilized in a work that he refuse to work upon)
a) 22.5 days b) 15 days c) 24.75 days d) 25.25 days
Question 8: For ouestion 6 , highest earning willbe for...
a) A b) both B and D c) C d) E e) can not be determined
question 9: If each of the workhas an equal payment of Rs. 10000 the lowest earning for the above situation will be for
a) A b) E c) C d) B e) can not be determined
Question 10: The value for the earning for the highest earning person,(If the data for question 6-9 is accurate) will be....
a) 19312.5 b) 13250 c) 12875 d)b e) Can not be determined
Ques) Sambhu beats Kalu by 30m or 10s. How much time was taken by Sambhu to complete a race 1200m?
a. 6.30min
b. 3.15 min
c. 12.10min
d. 2.5min ??
In this Question I applied the logic that, let two be racing with each other. So when Kalu starts he already covered 30m.. So uniformly his speed is 3m/s ahead of kalu. so to cover 1200m, it would require 1200/(3 * 60) minutes...
Is this concept correct??
Ques) Sambhu beats Kalu by 30m or 10s. How much time was taken by Sambhu to complete a race 1200m?
a. 6.30min
b. 3.15 min
c. 12.10min
d. 2.5min ??
In this Question I applied the logic that, let two be racing with each other. So when Kalu starts he already covered 30m.. So uniformly his speed is 3m/s ahead of kalu. so to cover 1200m, it would require 1200/(3 * 60) minutes...
Is this concept correct??
Here shambhu's speed will 30/10 = 3 m/s.
So shambhu will take 1200/3 = 400sec to cover the distance
Ques) Sambhu beats Kalu by 30m or 10s. How much time was taken by Sambhu to complete a race 1200m?
a. 6.30min
b. 3.15 min
c. 12.10min
d. 2.5min ??
In this Question I applied the logic that, let two be racing with each other. So when Kalu starts he already covered 30m.. So uniformly his speed is 3m/s ahead of kalu. so to cover 1200m, it would require 1200/(3 * 60) minutes...
Is this concept correct??
logic seems alright to me..........
plz help me wid this ques from arun sharma geometry LOD2 Q22
PP' and QQ' are two direct common tangents to two circles intersecting at points A and B. the common chord on produced intersects PP' in R and QQ' in S. which of the followong is true?
1) RA^2 + BS^2 = AB^2
2) RS^2 = PP'^2 + AB^2
3) RS^2 = PP'^2 + QQ'^2
4) RS^2 = BS^2 + PP'^2
Ques) Sambhu beats Kalu by 30m or 10s. How much time was taken by Sambhu to complete a race 1200m?
a. 6.30min
b. 3.15 min
c. 12.10min
d. 2.5min ??
In this Question I applied the logic that, let two be racing with each other. So when Kalu starts he already covered 30m.. So uniformly his speed is 3m/s ahead of kalu. so to cover 1200m, it would require 1200/(3 * 60) minutes...
Is this concept correct??
my take is option A....what's the answer given in book???????
Ques) Sambhu beats Kalu by 30m or 10s. How much time was taken by Sambhu to complete a race 1200m?
a. 6.30min
b. 3.15 min
c. 12.10min
d. 2.5min ??
In this Question I applied the logic that, let two be racing with each other. So when Kalu starts he already covered 30m.. So uniformly his speed is 3m/s ahead of kalu. so to cover 1200m, it would require 1200/(3 * 60) minutes...
Is this concept correct??
Acc to the problem when sambhu completes 1200m then kalu covers 1170m. so to complete 30m he takes 10s. so to cover 1200m he takes 400s. that means sambhu take 390s (he beats kalu by 10s,that is, he finishes 10s early). so answer should be 6 mins 30 secs.
:)
thanks buddy.
The answer is a. 6min 3333333333333333333333 seconds. 😛
if x= {(68^99)-(58^99)} divided by {+}, then which of the following holds true?
a) 0
plz help me guys..!!:::|::
if x= {(68^99)-(58^99)} divided by {+}, then which of the following holds true?
a) 0
plz help me guys..!
on a average,two litres of milk and 1 litre of water are mixed to make 1 kg of suda shrikhand of type A and 3 liters of milk and 2 litres of water are mixed to make 1 kg of suda shrikhand of type B.how many kilogram of each type was manufactured if it is known that 130 litres of milk and 80 liters of water is were used??
....
answer guyz
plz help me wid this ques from arun sharma geometry LOD2 Q22
PP' and QQ' are two direct common tangents to two circles intersecting at points A and B. the common chord on produced intersects PP' in R and QQ' in S. which of the followong is true?
1) RA^2 + BS^2 = AB^2
2) RS^2 = PP'^2 + AB^2
3) RS^2 = PP'^2 + QQ'^2
4) RS^2 = BS^2 + PP'^2
yaar please koi iska solution bhi bata do....
on a average,two litres of milk and 1 litre of water are mixed to make 1 kg of suda shrikhand of type A and 3 liters of milk and 2 litres of water are mixed to make 1 kg of suda shrikhand of type B.how many kilogram of each type was manufactured if it is known that 130 litres of milk and 80 liters of water is were used??
....
answer guyz
Let there be x kg of Type A and y kg of Type B
So, for type A, the milk consumed = 2x L and water consumed = x L.
For type B, the milk consumed = 3y L and water consumed = 2y L.
Total Milk consumed = 2x + 3y = 130
Total Water consumed = x + 2y = 80
Solve the 2 eqns. to get x = 20 kg and y = 30 kg.
Hope that helped.
if x= {(68^99)-(58^99)} divided by {+}, then which of the following holds true?
a) 0b) 0.5 c) 1 d) x>2
plz help me guys..!
(68^99)-(58^99)=(68-58 )(68^98+68^97*58+68^96*58^2+_____+58^98 )=10*(68^98+68^97*58+68^96*58^2+_____+58^98 )
Which when divided by {+} will leave a dividend of 10*(1+k)
=> x>2 i.e. Option 4)
Wuhu got myself arun sharma QA...Read few pages i must say that now i know why it has dominated mba entrances market.......
Will start block 1 today........and will try to be regular in this thread