A can do a piece of work in 20 days.he works at it for 5 days and then B finishes it in 10 more days.In how many days will A and B together finish this work.
A's 5 days work=5/20=1/4
So 3/4th of work left
3/4*1/10=3/40??
wat next..im unable to proceed
Pls explain in detail with steps
thanks in advance
A's work=5/20
B's work=3/40
(A+B)'s work=10/40+3/40=13/40
So for one day it is 13/40,so it takes 4 days...:sneaky::sneaky:
Raju can do a piece of work in 10 days,Vicky in 12 days and Tinku in 15 days.They all start the work together,but Raju leaves after 2 days and Vicky leaves 3 days before the work is completed.In how many days the work is completed.
a.5 days
b.6 days
c.7 days
d.8 days
i solved using this way:
R+V+T 2 day's work=1/10+1/12+1/15=15/60=2(1/4)
remaining work=1/2
V's 3 day's work=3/12=1/4
so now the remaining work=1-(1/2+1/4)=1/4
V+T's 1 day work=1/12+1/15=9/60=3/20
so the remaining work is finished in=20/3*1/4=5/3
but the given answer is 7
pls tell me wer am wrong?
Raju can do a piece of work in 10 days,Vicky in 12 days and Tinku in 15 days.They all start the work together,but Raju leaves after 2 days and Vicky leaves 3 days before the work is completed.In how many days the work is completed.
a.5 days
b.6 days
c.7 days
d.8 days
i solved using this way:
R+V+T 2 day's work=1/10+1/12+1/15=15/60=2(1/4)
remaining work=1/2
V's 3 day's work=3/12=1/4
so now the remaining work=1-(1/2+1/4)=1/4
V+T's 1 day work=1/12+1/15=9/60=3/20
so the remaining work is finished in=20/3*1/4=5/3
but the given answer is 7
pls tell me wer am wrong?
kittu12 Saysthe given answer is 8 days
Raju can do a piece of work in 10 days,Vicky in 12 days and Tinku in 15 days.They all start the work together,but Raju leaves after 2 days and Vicky leaves 3 days before the work is completed.In how many days the work is completed.
a.5 days
b.6 days
c.7 days
d.8 days
i solved using this way:
R+V+T 2 day's work=1/10+1/12+1/15=15/60=2(1/4)
remaining work=1/2
V's 3 day's work=3/12=1/4
so now the remaining work=1-(1/2+1/4)=1/4
V+T's 1 day work=1/12+1/15=9/60=3/20
so the remaining work is finished in=20/3*1/4=5/3
but the given answer is 7
pls tell me wer am wrong?
A can do a piece of work in 20 days.he works at it for 5 days and then B finishes it in 10 more days.In how many days will A and B together finish this work.
A's 5 days work=5/20=1/4
So 3/4th of work left
3/4*1/10=3/40??
wat next..im unable to proceed
Pls explain in detail with steps
thanks in advance
A's work=5/20
B's work=3/40
(A+B)'s work=10/40+3/40=13/40
So for one day it is 13/40,so it takes 4 days...:sneaky::sneaky:
If harmonic mean between two positive numbers is to the inverse of their geometric mean as 12:13; then the numbers could be in ratio
a)12:13
B)13:12
c)4:9
d)2:3
corrected the question
and suja bhai
1+4/7+(9/7^2)+(16/7^3)......
ye series kaise karte the??
1 month mein sab bhul gaya hu :-(
Let total work be 200 units...
A takes 20 days to finish the work so he does 10 unit of work in one day...
In 5 days A completed 50 unit of work
Work left = 150 unit
Now B takes 10 days to finish 150 unit of work, so B does 15 unit of work in one day.
So together A and B do 15+10 = 25 unit of work in one day.
So to finish 200 units of work they will take 8 days..
Hope it is clear....
kittu12 Saysthanks alot dude..could u pls tell me what mistake i made in the proceeding which i used to solve the same problem
A's 5 days work=5/20=1/4
So 3/4th of work left
3/4*1/10=3/40??
wat next..im unable to proceed
Pls explain in detail with steps
thanks in advance
15 men can do a piece of work in 210 days. But at the end of every 10 days 15 additional men are employed, in how many days will it be finished
the answer is 55
In a fort there was sufficient food for 200 soldiers for 31 days. After 27 days 120 soldiers left the front . For how many extra days will the rest of the food last for the remaining soldiers?
the ans is 10 days
pls explain in detail with steps
15 men can do a piece of work in 210 days. But at the end of every 10 days 15 additional men are employed, in how many days will it be finished
the answer is 55
In a fort there was sufficient food for 200 soldiers for 31 days. After 27 days 120 soldiers left the front . For how many extra days will the rest of the food last for the remaining soldiers?
the ans is 10 days
pls explain in detail with steps
But at the
In a fort there was sufficient food for 200 soldiers for 31 days. After 27 days 120 soldiers left the front . For how many extra days will the rest of the food last for the remaining soldiers?
the ans is 10 days
pls explain in detail with steps
There are two pipes in a tank. Pipe A is for filling the tank and Pipe B is for emptying the tank. If A can fill the tank in 10 hours and B can empty the tank in 15 hours then find how many hours will it take to completely fill a half empty tank
the answer is 33.33
pls explain i detail with steps
There are two pipes in a tank. Pipe A is for filling the tank and Pipe B is for emptying the tank. If A can fill the tank in 10 hours and B can empty the tank in 15 hours then find how many hours will it take to completely fill a half empty tank
the answer is 33.33
pls explain i detail with steps
There are two pipes in a tank. Pipe A is for filling the tank and Pipe B is for emptying the tank. If A can fill the tank in 10 hours and B can empty the tank in 15 hours then find how many hours will it take to completely fill a half empty tank
the answer is 33.33
pls explain i detail with steps
15 men can do a piece of work in 210 days. But at the end of every 10 days 15 additional men are employed, in how many days will it be finished
the answer is 55
correct answer of this question is 15.....
@thinkace bhai kindly solve above posted question
15 men can do a peice of work...and correct me if i have done some mistake...it will be great help
Abbot can do some work in 10 days, Bill can do it in 20 days and Clinton can do it in 40 days. They start working in turns with Abbot starting to work on the first day followed by Bill on the 2nd day and by Clinton on the 3rd day and again by Abbot on the fourth day and so ontill the work is completed fully.find the time to complete the work fully..
friends i always get confused while solving such alternate sums..pls explain in detail so that i may not find difficulty in solving such problems..if possible pls gimme me some tricks to solve such problems
thanks in advance
I think it should be 60 days
Total amount of work = 15*210
Now, work happens in slots of 10 days like:
10*15 + 10*30 + 10*45 + 10*60 + ..
=> 15*210 = 10*15*(1+2+3+4+..)
=> 21 = 1 + 2 + 3 + 4 + .... + n
=> n = 6
=> Days needed 6*10 = 60
There are three Taps A, B and C in a tank. They can fill the tank in 10 hrs, 20 hrs and 25 hrs respectively. At first, all of them are opened simultaneously.then after 2 hours,tap C is closed and A and B are kept running.After the 4th hour,tap B is also closed.the remaining work is done by Tap A alone.Find the percentage of the work done by tap A by itself.
pls explain in details with steps
Abbot can do some work in 10 days, Bill can do it in 20 days and Clinton can do it in 40 days. They start working in turns with Abbot starting to work on the first day followed by Bill on the 2nd day and by Clinton on the 3rd day and again by Abbot on the fourth day and so ontill the work is completed fully.find the time to complete the work fully..
friends i always get confused while solving such alternate sums..pls explain in detail so that i may not find difficulty in solving such problems..if possible pls gimme me some tricks to solve such problems
thanks in advance