Quant by Arun Sharma

What is the highest power of 54 that divides 31! exactly?
a)4 b)7 c)9....pls show d entire process.

the Problem is simple here it goes

54=2*3^3

therefore in short u need to find the maximum power of 3^3 that divides 31!

31! contains

31/3=10
10/3=3
3/3=1

therefore in 31 ! there are 3^14

so maximum 54 ^ would be 4 because if u divide it by 54^5 it will not completly divide
What is the highest power of 54 that divides 31! exactly?
a)4 b)7 c)9....pls show d entire process.

the Problem is simple here it goes

54=2*3^3

therefore in short u need to find the maximum power of 3^3 that divides 31!

31! contains

31/3=10
10/3=3
3/3=1

therefore in 31 ! there are 3^14

so maximum 54 ^ would be 4 because if u divide it by 54^5 it will not completly divide

snipped..........................guess i was sleeping while reading the quesion ...

puys need help .............

arun , bikas and chandan have total of 80 coins. arun triples the no. of coins that bikas and chandan have by giving them coins from his own collection. now, bikas repeats the same process and at the end he is left with 20 coins. how many coins he initially had.
a.)11 b.)10 c.)9 d.)7

please reply with approach

could you please xplain the logic a bit more...didnt understand h ebold part
also when we have already added (1+3+5...) to calculate distance till a particular mango why do we need to add the previous distances as in we add 1 thhen we again add 1+3 and for 3rd we again add 1+3+5..

in a nut shell i didnt get anyhthing...:banghead:


look he has to go n pick one mango n drop to basket which is kept nearby first mango. then he has to go to 2nd mango so he has to go (1+3) distance pick the mango come back to basket by covering (1+3) distance again.
So he has to go to each mango and come back.

Thanks
Ashish

:cheerio: By the way I dont know why he is doing this he can pick the basket n pick each mango ha ha :)
2ndApr2011 Says
snipped..........................guess i was sleeping while reading the quesion ...



I m getting the answer 5 and the 2nd condition given in the book is right becoz i m also thinking same condition....................

Is the answer right or any other??
I m getting the answer 5 and the 2nd condition given in the book is right becoz i m also thinking same condition....................

Is the answer right or any other??


The answer of this one is option a) ..the equation as given in the book is right ...do check it once ...i am sure u will get it 😃

hi,
please solve the following ques.
At a particular time in the 21st century there were seven bowlers in the indian cricket team's list of 16 players short listed to play the next world cup.Statisticians discovered that that if you looked at the number of wickets taken by any of the 7 bowlers of the current indian cricket team,the number of wickets taken by them had a strange property. the numbers were such that for any team selection of 11 players(having 1to 7 bowlers) by using the number of wickets taken by each bowler and attaching coefficients of+1,0,-1,to each value available and adding the resultant values,any number from 1 to 1093,both included could be formed. if we denote W1,W2,W3,W4,W5,W6,W7 as the seven values in ascending order,then what is the value of W1+2W2+3W3+4W4+5W5+6W6


Options
1) 2005

2)1995

3)1985

4) NONE OF THE ABOVE

the Problem is simple here it goes

54=2*3^3

therefore in short u need to find the maximum power of 3^3 that divides 31!

31! contains

31/3=10
10/3=3
3/3=1

therefore in 31 ! there are 3^14

so maximum 54 ^ would be 4 because if u divide it by 54^5 it will not completly divide


can u pls explain the last line how 4 and 5 came after 3^14
tarkamal Says
can u pls explain the last line how 4 and 5 came after 3^14

veere sun ... vekh

54 whech teri maximum kinniyan power hai 3 diyan 3

and 31! whech 14

so now if u multiply 3power with 5 = total become 15 .. that will cause 1 poer of 3 remain left in the denominator if u divide

31!/54^5

so answer is

puys reposting it please help .............

arun , bikas and chandan have total of 80 coins. arun triples the no. of coins that bikas and chandan have by giving them coins from his own collection. now, bikas repeats the same process and at the end he is left with 20 coins. how many coins he initially had.
a.)11 b.)10 c.)9 d.)7

please reply with approach

A tank of 425 litres capacity has been filled with water through two pipes, the first pipe having been opened 5hrs longer than the second. If the first pipe were open as long as the second, and the second pipe was open as long as the first pipe was open, the the first pipe would deliver half the amount of water delivered by the second pipe; if the two pipes were open simultaneously, the tank would be filled up in 17 hrs, How long was the second pipe open?

a)10hrs
b)12 hrs
c)15hrs
d)18hrs

pls post your approach

puys pls solve this too.......
puys reposting it please help .............

arun , bikas and chandan have total of 80 coins. arun triples the no. of coins that bikas and chandan have by giving them coins from his own collection. now, bikas repeats the same process and at the end he is left with 20 coins. how many coins he initially had.
a.)11 b.)10 c.)9 d.)7

please reply with approach

i would say question is incomplete in such questions gennerally u have 3 steps .. and if i take take 2 step operation then 20 must be with vikas so

if u Divide the amount

A+C=60 as B=20

A/C should be multiple of 3

and here question ends we cant find exact value but we can find the minium value of each step

A B C
X 20 60-X
X/3 20+X*2/3X + 60-X*2/3(60-X) (60-X)/3


this is max i can tell u
pallavi70 Says
puys pls solve this too.......

This iS easy 1

My approach if it comes in Exam

Biggest hint in question collectively it takes 17 hours when operate simuntaneously so that is possible in only 1 case (15,20)

so answer is 15

BUt Question is WRONG
here is my approach

pipe 1 X+5 hours
pipe 2 X hrs

now question is saying X+5 % of X is 50% of X(X+5)

in other way suppose it is 20 & 15
suppose P1 thaat take 20 hours will operate for 15 then it must fill tank 75% of tank

and if the P2 tank that take 15 hours operate for 20

it will fill 133 1/3%
so this question is wrong

The selling price of two bicycles are Rs.600 and Rs.900.On first a man loses 20%.At what profit% should he sell the 2nd bicycle to neutralise the loss?
a)30% b)40% c)23%.
pls do show d entire process.

Puys please solve this one also , i am not getting the solution for this :

A tank in Gauri Apartments is full of water is fitted with pumps of equal capacity . Besides it is also fitted with a certain number of inlet pipes which are always kept open. When the tank is full , 10 pumps of equal capacity empty the tank in 12 hrs , while 15 pumps of the same capacity empty the tank in 6 hrs . In how much time would 25 pumps of the same capacity empty the tank , if the tank is initially full ? (All the pipes pouring water into the tank are always open )

a) 3 hrs b) 5/2 hrs c) 4 hrs d) 7/2 hrs

Answer is option d as given in the book but i am getting as 3 hrs

The selling price of two bicycles are Rs.600 and Rs.900.On first a man loses 20%.At what profit% should he sell the 2nd bicycle to neutralise the loss?
a)30% b)40% c)23%.
pls do show d entire process.


By selling for 600, he incurs a loss of 20%, thus 600 is 80% of the Cost Price. which by solving gives us the cost price as Rs.750 and the Loss of Rs.150.

Now, to recover the loss of Rs.150 by selling it for Rs.900 means that the cost of the 2nd Bicycle was (900-150)=Rs.750.
A profit of Rs.150 over a C.P. of Rs.750 is 20%...

Let me know if I have gone wrong anywhere with this!
The selling price of two bicycles are Rs.600 and Rs.900.On first a man loses 20%.At what profit% should he sell the 2nd bicycle to neutralise the loss?
a)30% b)40% c)23%.


opzzz

In a game, the 1st person tosses a coin. If the outcome is head, he throws a die and the result is recorded as his score and he gets one more chance to toss the coin. If the outcome is tail then the next person gets a chace to toss the coin. What is theprobability that a person scores 35 points after 6 tosses in this game?

1) (1/32)(1/6)^5

2) (1/32)(1/6)^6

3) (1/64) (1/6)^6

4) (1/64) (1/6)^5

Is there some other book for the solutions of the block review tests...?
Just the answer key is given not the solutions..:(