Quant by Arun Sharma

MBA CAT 2024
4081
neyati bhanot Says
same problem....

answer for second ques is 20......
a) 20
am i correct
4082
answer for second ques is 20......
a) 20
am i correct


its like take p=100 by this u can find r frm ci formula .... then take again by si formula u can get it as p=100,r u will take out frm ci n t is give

how did u do the first question i dint get it
4083
yes it is..

but i gn get one thing is 808 the total amount as in (I + P) ??
i mean how did u arrive at 400 and y would it be paid each month??
can u pls show step bt step approach to this question..
i guess i am confusing a lot with the concepts....


ok My mistake its per annum. I think I will make it more clear this time.
As total debt he has to pay 808rs. You can easily find out money before as how muuch amount of money will become 808 after 2 years with 2 %
the ans came as 808=p(102/100)(102/100)
p=808/1.04
p~=776

so first year he pay 400 rs. on amount 776+776(102/100)=791 after first year the amount he paid is 400 rs.
so approx.. 391 remains..391 will be taken as money for next year at 2 percent the amount so the amount will become 391+391(102/100)~=400

So with amount 400 he can pay the debit of 808rs

I hope this time you get it.
4084

one more question: The avg salary per head of all the employees of a company is rs 600.the avg salary of 120 officers is 4000.If the avg salary per head of the rest of employess is rs 560, find the total number of workers in the company.

1) 1020
2) 1032
3) 1050
4) 1068

4085
neyati bhanot Says
same problem....


Hi,
For first question I provided a solution in details.
And in second question we can assume the rate interest be 10%. Now if you try to solve

21=p(1.1*1.1)-p
21=.21p
p=100

so SI= (100*10*2)/2 = 20

So the answer is 20.

Thanks
Ashish
4086
one more question: The avg salary per head of all the employees of a company is rs 600.the avg salary of 120 officers is 4000.If the avg salary per head of the rest of employess is rs 560, find the total number of workers in the company.

1) 1020
2) 1032
3) 1050
4) 1068

this question has been discussed in pages 403-405
4087
ok My mistake its per annum. I think I will make it more clear this time.
As total debt he has to pay 808rs. You can easily find out money before as how muuch amount of money will become 808 after 2 years with 2 %
the ans came as 808=p(102/100)(102/100)
p=808/1.04
p~=776

so first year he pay 400 rs. on amount 776+776(102/100)=791 after first year the amount he paid is 400 rs.
so approx.. 391 remains..391 will be taken as money for next year at 2 percent the amount so the amount will become 391+391(102/100)~=400

So with amount 400 he can pay the debit of 808rs

I hope this time you get it.

I m not getting Ur explanation .Improve it dude.................
4088

A mixture of cement ,sand and gravel in the ratio of 1:2:4 by volume is required. A person wishes to measure out quantities by weight.He finds that the weight of one cubic foot of cement is 94 kg, of sand is 100 kg and gravel 110 kg. what should be the ratio of cement, sand and gravel by weight in order to give a proper mixture?

a)47:100:220
b)94:100:220
c)47:200:440
d)none of these

4089
A mixture of cement ,sand and gravel in the ratio of 1:2:4 by volume is required. A person wishes to measure out quantities by weight.He finds that the weight of one cubic foot of cement is 94 kg, of sand is 100 kg and gravel 110 kg. what should be the ratio of cement, sand and gravel by weight in order to give a proper mixture?

a)47:100:220
b)94:100:220
c)47:200:440
d)none of these


I think a) because this would mean, 1/2 Cubic Foot of Cement, 1 Cubic Foot of Sand and 2 Cubic Foot of Gravel.
Lemme know!
4090
abhinavrocker Says
I m not getting Ur explanation .Improve it dude.................


Hi abhinav,
Which part you did not get.
Its as simple as he is paying the full amount in two installments, of 400 each.
so the amount avail after first installment is the amount + interest you need to pay in 2nd installment.

If still its not clear let me know.
4091
A mixture of cement ,sand and gravel in the ratio of 1:2:4 by volume is required. A person wishes to measure out quantities by weight.He finds that the weight of one cubic foot of cement is 94 kg, of sand is 100 kg and gravel 110 kg. what should be the ratio of cement, sand and gravel by weight in order to give a proper mixture?

a)47:100:220
b)94:100:220
c)47:200:440
d)none of these


The answer choice 1 is correct.
Required volume ratio given as 1:2:4
One cubic foot also stand as volume.
So we can see 1cubic foot of cement weight =94
1cubic foot of sand=100
1cubic foot of gravel=110.
if I take the ration by volume i.e each of one cube --> C:S:G=94:100:110
the ratio we needed as 1:2:4
if first one is 94:2*100:4*110
divide by 2
we get as 47:100:220

Can we have the answer plz?
Thanks
Ashish
4092

As total debt he has to pay 808rs. You can easily find out money before as how muuch amount of money will become 808 after 2 years with 2 %
the ans came as 808=p(102/100)(102/100)
p=808/1.04
p~=776

so first year he pay 400 rs. on amount 776+776(102/100)=791 after first year the amount he paid is 400 rs.
so approx.. 391 remains..391 will be taken as money for next year at 2 percent the amount so the amount will become 391+391(102/100)~=400


How did u do this ??
776*102/100~=791

4093
As total debt he has to pay 808rs. You can easily find out money before as how muuch amount of money will become 808 after 2 years with 2 %
the ans came as 808=p(102/100)(102/100)
p=808/1.04
p~=776

so first year he pay 400 rs. on amount 776+776(102/100)=791 after first year the amount he paid is 400 rs.
so approx.. 391 remains..391 will be taken as money for next year at 2 percent the amount so the amount will become 391+391(102/100)~=400


How did u do this ??
776*102/100~=791


look if the principal is 776, n ROI is 2 %.so end of first year the amount he needs to pay is 776+2% of this amount which is 776+776(102/100)=791.This is for first year.
So after paying 400 the amount remaining is 391.for the 2nd year.

I hope its clear.I already mentioned it see bold.

Thanks
Ashish
4094

plz help me wid this ques from arun sharma geometry LOD2 Q22

PP' and QQ' are two direct common tangents to two circles intersecting at points A and B. the common chord on produced intersects PP' in R and QQ' in S. which of the followong is true?

1) RA^2 + BS^2 = AB^2
2) RS^2 = PP'^2 + AB^2
3) RS^2 = PP'^2 + QQ'^2
4) RS^2 = BS^2 + PP'^2

4095
look if the principal is 776, n ROI is 2 %.so end of first year the amount he needs to pay is 776+2% of this amount which is 776+776(102/100)=791.This is for first year.
So after paying 400 the amount remaining is 391.for the 2nd year.

I hope its clear.I already mentioned it see bold.

Thanks
Ashish



simply i can say that --------------------------
808*2*1/100=16.16 in a month ,he will hve to pay ................
so 1st year he pays=16.16*12=193.92
and similarly in second yr he pays...............193.92(becoz he will have to pay SI on debt)...............so total he will pay=398~=400(near to)
but u r taking compound interest which is differ ..............


Am i correct ??
4096
The following is a question from the Number Systems chapter - I know the answer given at the back of the book is incorrect - Just wanted to reconfirm:

A boy has a certain number of chocolates. He eats 1/3rd of them and 1 more in the morning and then 1/5th of the remaining and 4 more in the evening after which he is not left with any chocolates. How many chocolates did he have at the beginning

a) 12 b) 13 c) 15 d) none of the above.


suppose u have x chocolates.....................
then,condition 1st u have only.................2x/3
after it,u have only 2x/3-1
now.....................................condition 2nd........................
(2x/3-1)-(2x/3-1)/5....................after it the last statement........we get

(2x/3-1)-(2x/3-1)/5-4=0
->x=9..................
4097
simply i can say that --------------------------
808*2*1/100=16.16 in a month ,he will hve to pay ................
so 1st year he pays=16.16*12=193.92
and similarly in second yr he pays...............193.92(becoz he will have to pay SI on debt)...............so total he will pay=398~=400(near to)
but u r taking compound interest which is differ ..............


Am i correct ??


Hey abhinav. The total amount he need to pay is 808,not 400.
So Chk again.

Or any easy chk is paying 808 in 2 equal installments nearly goes to 808/2=404~400
No other option so close to it
Thanks
Ashish
4098

Consider quarter circles drawn in the first and third quadrants with origin as the centre and radius = 17 units. The number of the points with integer coordinates within the two quarter circles and on the boundaries is............?
?is there any simple method for this question?

4099

guyz help me out in the problem related to pipes and cisterns question do you have any trick then share it 😃

4100

can someone plz tell me d link for download of arun sharma solutions,,stuck wid some questions,dint get d solutions as well..plz help !!!!