Thanks for the reply:). Actually when i read the question i feel that its not clearly mentioned dat the %change in yrs 96 - 98 is 5%.
"the growth rate of the population was 10% last year and 5 % the year prior to it, the only exception being 1999 "
Can you help me understand if i m wrong. (it wud not have been confusing for me if: "the growth rate of the population was 10% last year and 5 % the yearsprior to it, the only exception being 1999 " ).
absolutely! even i feel that it should have been years....
absolutely! even i feel that it should have been years....
ur absolutely right ..................it should be years insted of year................
ur 2nd question related to CI and SI has been solved ....................I have also solved that but there is not a proper way to solve it..................by assuming,amount-100.........it can be solved otherwise there is a way that.......................
for same time and same rate..............the CI and SI will be equal for 1st year.................for 2nd yr .......if CI is given ,then SI will be nearest value to it........................
Guys, I could not get few questions mentioned below. These are from Number System, Please let me know if anyone of you could solve it...
1) What will be least possible number of planks, if three pieces of timber 42m, 49m and 63m long have to be divided into planks of same length? (a) 7 (b) 8 (c) 22 (d) None of above
2) Find the number of divisors of 1080 excluding the throughout divisors, which are perfect square. (a) 28 (b) 29 (c) 30 (d) 31
3) Find the sum of divisors of 544 which are perfect square (a) 32 (b) 64 (c) 42 (d) 21
4) Find the maximum value of n such that 42*57*92*91*52*62*63*64*65*66*67 is perfectly divisible by 42^n
Please let me know the approach... Thanks in advance ... Answers given.... 1 : C 2 : A 3 : D 4 : B
Guys, I could not get few questions mentioned below. These are from Number System, Please let me know if anyone of you could solve it...
1) What will be least possible number of planks, if three pieces of timber 42m, 49m and 63m long have to be divided into planks of same length? (a) 7 (b) 8 (c) 22 (d) None of above
2) Find the number of divisors of 1080 excluding the throughout divisors, which are perfect square. (a) 28 (b) 29 (c) 30 (d) 31
3) Find the sum of divisors of 544 which are perfect square (a) 32 (b) 64 (c) 42 (d) 21
4) Find the maximum value of n such that 42*57*92*91*52*62*63*64*65*66*67 is perfectly divisible by 42^n
Please let me know the approach... Thanks in advance ... Answers given.... 1 : C 2 : A 3 : D 4 : B
Pravin
Hi pravin.......................... 1)the HCF of 42,49 and 63 is 7................so number of planks will be (42/7)+(49/7)+(63/7)=22
2)1080= 5^1* 2^3* 3^3 \ \ \ total number of divisors=(1+1)*(1+3)*(1+3)=32 number of perfect squares=(5^0+5^1)*(2^0+2^1+2^2+2^3)*(3^0+3^1+3^2+3^3)--->so 3 perfect squares and 36(by combination of perfect squares) also. so number of divisors excluding perfect squares=32-4=28
3)544=2^5*17^1
Total sum=(2^0+2^1+2^2+2^3+2^4+2^5)*(17^0+17^1)=(1+4+16)*(1)=21
4)last question options are not available yet ..............answer will be 3 is this correct?
42=7*3*2 find total number of 7's=3(42,91,63) no. of 3's and 2's>no. of 7's
so answer should be 3 definitely.................................
LOD 1 ques 46 chapter 5 in an exam 80% students passed in physics. 70% in chemistry while 15% failled in both the subjects. if 325 students passed in boh the subjects. find the total number of students who appeared in the examination.
In this problem (and problems similar to these) I get confused in the language of the problem ....like in the above question when they say that "15% students failed in both the subjects" does it mean the total students failed or do they mean the students in common from the two subjects who failed ?? ..similarly for the statement "325 students passed in both the subjects" While getting the solution , the approach puys have taken is to take 325 as the common students passed in both the subjects and 15% as the total students who failed in both the subjects ...even though they have been introduced in the same way in the problem ...can anyone please solve my doubt
this is quest no. 31 on page 72... i have few more question similar to this (32,33 and 35)..so please letme knw the basic approach to solve these kind of questions
56/225...the method shown by ThinkAce is perfect...
hey! could anyone solve this for me?! in an examination, there are 4 sections ; each section of 45 marks. Find the no. of ways in which a student can qualify if the qualifying marks is 90.
Let the marks scored in d 4 secs be a,b,c,d a+b+c+d=90 No. of solns =C(93,3) But the marks cannnot be>45.So we'll have to remove those cases. Let us 1st cosider the case where a>45 a=46+x where x>=0 So, 46+x+b+c+d=90 x+b+c+d=44 No of solns=C(47,3) Similar solns will be dere 4 b,c,d
u r really confusing..................it means that those students which are not passed in any subjects,are 15%. so................. n(AUB)=n(A)+n(B)-n(A@B) suppose,total nnumber of students are x,then........... n(AUB)=0.8x+0.7x-325-------------------(1) while n(AUB)--->those students who are passed in either physics or chemistry
now, it is given that,15% students are failed x-n(AUB)=0.15x------------------(2) now calculate and u will get 500 is answer correct ??I think it should be correct 100% surity.............
if u read the question then u will get ................
total 71 numbers ,total result=71*48 now,59 numbers result=59*46 now,last 11 means..............we are not including 59th result and results start from 60th result and now we have to calculate the result from last end means(from 71th)................so there will be only 11 numbers while from 59th to 71th ............there are 12 numbers................. so................the 60th result will be =71*48-59*46-11*52=122
Hi pravin.......................... 1)the HCF of 42,49 and 63 is 7................so number of planks will be (42/7)+(49/7)+(63/7)=22
2)1080= 5^1* 2^3* 3^3 \ \ \ total number of divisors=(1+1)*(1+3)*(1+3)=32 number of perfect squares=(5^0+5^1)*(2^0+2^1+2^2+2^3)*(3^0+3^1+3^2+3^3)--->so 3 perfect squares and 36(by combination of perfect squares) also. so number of divisors excluding perfect squares=32-4=28
3)544=2^5*17^1
Total sum=(2^0+2^1+2^2+2^3+2^4+2^5)*(17^0+17^1)=(1+4+16)*(1)=21
4)last question options are not available yet ..............answer will be 3 is this correct?
42=7*3*2 find total number of 7's=3(42,91,63) no. of 3's and 2's>no. of 7's
so answer should be 3 definitely.................................
Thanx man. For 4th 3 is correct answer, I forgot to put the options there.... :cheerio:
A ship sails out to a mark at hte rate of 15KM per hour and sails back at the rate of 20km per hour. what is the average rate of sailing?
1) 16.85 km 2)17.14 km 3) 17.85 km 4) 18 km
A batsman makes a score of 270 runs in the 87th innings and thus increases his avg by a certain number or runs thats is a whole number. Find the posssible values of the new avg.?
A ship sails out to a mark at hte rate of 15KM per hour and sails back at the rate of 20km per hour. what is the average rate of sailing?
1) 16.85 km 2)17.14 km 3) 17.85 km 4) 18 km
A batsman makes a score of 270 runs in the 87th innings and thus increases his avg by a certain number or runs thats is a whole number. Find the posssible values of the new avg.?
1)98 2)184 3)12 d)all of these
For the first question, I think the formula to be used is 2ab/(a+B)
For the second one, I checked for 98... /86, It gave an integral solution, I was abt to mark 1) but then I checked for 12 and it gave one as well. So, no need to check for 184 and thus the answer--All of these.
Is the answer is 400.? It simply as 2 years at 2% the debt amount is 808 So you can pay it by 400 paying each month.
yes it is..
but i gn get one thing is 808 the total amount as in (I + P) ?? i mean how did u arrive at 400 and y would it be paid each month?? can u pls show step bt step approach to this question.. i guess i am confusing a lot with the concepts....
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