tatts an awesome solution...thx
Thatts gr8
Hi,
Please help me in solving the below progression problem. Many thanks.:)
If 3 positive real numbers x,y,z are in AP such that xyz = 4, then what will be the minimum value of y?
1)2^1/3
2)2^2/3
3)2^1/4
4)2^3/4
^ -> power.
Hi,
Please help me in solving the below progression problem. Many thanks.:)
If 3 positive real numbers x,y,z are in AP such that xyz = 4, then what will be the minimum value of y?
1)2^1/3
2)2^2/3
3)2^1/4
4)2^3/4
^ -> power.
x,y and z are in AP
so, 2y = x+z
Now by
AM>= GM
so,(x+y+z)/3 >= cube root (x*y*z)
So,3y/3>=cube root(x*y*z)
=>y>=4^1/3
=>y>= 2^2/3
So,minimum value of y = 2^2/3
a 5 digit no. formed using digits 1, 3, 5, 7, 9. without repeating any one of them. what is the sum of such possible nmbrs.???
1.6666600
2.6666660
3.6666666
4.none
no clue hw to solv dis. plz help...
Dont know whats the shortest sol for it. But I managed the answer after some time by trying combinations and adding em up..
Hi puys please help me solving questions on time n work.
Q) A,B,C working together completed a job in 10 days. However, C only worked for the first three days when 37/100 of the job was done. Also, the work done by A in 5 days is equal to the work done by B in 4 days. How many days would be required by the fastest worker to complete the entire work?
Answer : 20 days
Q) It takes six days for three women and two men working together to complete a work. Three men would do the same work five days sooner than nine women. How many times does the output of a man exceed that of a women?
Answer : 6 times
Q) Each of A, B, and C need a certain unique time to do a certain work. C needs 1 hour less than a to complete the work. Working together, they require 30 minutes to complete 50% of the job. The work also gets completed if A and B start working together and A leaves after 1hour and B works for a further 3hours. How much work does C do per hour?
Answer: 50%
Q) Two pipes A and B can fill up a half full tank in 1.2 hours. The tank was initially empty. Pipe B was kept open for half the time required by pipe A to fill the tank by itself. Then, pipe A was kept open for as much time as was required by pipe B to fill up 1/3 of the tank by itself. It was found that the tank was 5/6 full. The least time in which any of the pipes can fill the tank fully is?
Answer: 4 hoours
I wouldd really appreciate if you could explain me through fraction method because by percentage method I am not at all comfortable with.
Thanks in advance
Sushil
a 5 digit no. formed using digits 1, 3, 5, 7, 9. without repeating any one of them. what is the sum of such possible nmbrs.???
1.6666600
2.6666660
3.6666666
4.none
no clue hw to solv dis. plz help...
Dere is a direct formula to solve such a prob where one has to find sum of all possible combinations of numbers:
When n distinct digits r used to form all n-digit combinations,the sum of all the combinations=
(n-1)! x (Sum of n digits) X (1111...n times)
Hi puys please help me solving questions on time n work.
Q) It takes six days for three women and two men working together to complete a work. Three men would do the same work five days sooner than nine women. How many times does the output of a man exceed that of a women?
Answer : 6 times
I wouldd really appreciate if you could explain me through fraction method because by percentage method I am not at all comfortable with.
Thanks in advance
Sushil
Let a man does M units of work in a day and a woman does W units in a day.
So,in 1 day,2 men wud finish 2M units of work.In 6 days,2 men wud finish 12M units of work.
Similarly,3 women wud finish 18W units of work in 6 days.
Hence total work=(12M+18W)
Now,as said in Q,(12M+18W) work wil done by 3 men in (12M+18W)/3M days.....and by 9 women in (12M+18W)/9W days.....
Given dat women take 5 more days dan men
Hence...{(12M+18W)/9W}-{(12M+18W)/3M}=5.....
Solve the above and get M/W ratio as 6:cheerio:
Hi puys please help me solving questions on time n work.
Q) Each of A, B, and C need a certain unique time to do a certain work. C needs 1 hour less than a to complete the work. Working together, they require 30 minutes to complete 50% of the job. The work also gets completed if A and B start working together and A leaves after 1hour and B works for a further 3hours. How much work does C do per hour?
Answer: 50%
I wouldd really appreciate if you could explain me through fraction method because by percentage method I am not at all comfortable with.
Thanks in advance
Sushil
Suppose A takes A hrs,B takes B hrs.C wud take (A-1) hrs...
Work done by A in 1/2 hrs=1/2A,B=1/2B,C=1/2(A-1)....
Hence (1/2A)+(1/2B)+{1/2(A-1)}=1/2.......(1)
Also,wen A n B work,A works for 1 hr and B for 4 hrs..
Hence...(1/A)+(4/B)=1....(2)
Solve (2) and get 1/B in terms of A..Put values of 1/B and 1/C in (1) and solve,u vl get a quadratic equation..Solve it and A=3 hrs
C=A-1 hrs= 2 hrs...Hence in 1 hr,C does 1/2 of work or 50%:cheerio:
P.S-rest of the 2 questions baad me solve karunga..its Novel tym!!!!
The number of positive integral solution of abc = 30 is
i) 27 ii) 81 iii)243
please xplain !!!!
The number of positive integral solution of abc = 30 is
i) 27 ii) 81 iii)243
please xplain !!!!
a = 2^x1*3^y1*5^z1
b = 2^x2*3^y2*5^z2
c = 2^x3*3^y3*5^z3
=> x1 + x2 + x3 = 1 (3 ways),
y1 + y2 + y3 = 1 (3 ways),
z1 + z2 + z3 = 1 (3 ways)
=> 3*3*3 = 27 ways
@ chillfactor
but the book says ans is c i.e 243
@ chillfactor
but the book says ans is c i.e 243
I think it can not be 243, solution in the book is incorrect.
i came up with same ans !!! but books says diff ans , so i got confused!!!!
thanxx !!!! hey can u xplain this question
A conference attended by 200 delegates is held in a hall. The hall has 7 doors,marked A,B,......,G. At each door,an entry book is kept and the delegates entering through that door sign in it in the order in which they enter . If each delegate is free to enter any time and through any door he likes, how many different sets of seven lista would arise in all ? (Assume that every person signs only at his first entry)
i) 206C6 ii) 199P5 iii) 199C5 iv) 206P6
(Ans is 206P6)
how is ans 206P6 ??
A conference attended by 200 delegates is held in a hall. The hall has 7 doors,marked A,B,......,G. At each door,an entry book is kept and the delegates entering through that door sign in it in the order in which they enter . If each delegate is free to enter any time and through any door he likes, how many different sets of seven lista would arise in all ? (Assume that every person signs only at his first entry)
If x(i) denotes the number of delegates entering through door 'i', then
x(1) + x(2) + x(3) + ... + x(7) = 200
=> Number of ways = C(206, 200)
But since order in which they enter is also of importance, we need to multiply by 200!
=> Total no of different sets if seven lists = C(206, 200)*200! = P(206, 200)
I think answer should be P(206, 200) and not P(206, 6)
ya i guess it should b p(206,200)!!!
How many factors does 16! have??
Hi,
Please help me in solving the below progression problem. Many thanks.:)
If 3 positive real numbers x,y,z are in AP such that xyz = 4, then what will be the minimum value of y?
1)2^1/3
2)2^2/3
3)2^1/4
4)2^3/4
^ -> power.
dear. Go through options. Lyf would become much more rasy.
@ chillfactor
but the book says ans is c i.e 243
the book isn't wrong. I'm sure it can't be 27 coz 30 has 8 factors. Hence it can be arranged in much more way. Don't no the ans.
hi the answer is 220.
_ _ _ 0 ->no. Of ways 6*5*4*1= 120
_ _ _ 5 -> no. Of ways 5*5*4*1= 100 coz 0 cannot be at the beginning.
Cheers
???? Why havnt u included the repetion...i think reptition of numbers is allowed.....and with that my ans is 448
is it correct??????