these type of question are always solved by this at we will use 1,3,9,27 as 27+9+3+1=40 so we will be able to weigh all weight up to 40 ex: 3-1=2kg and if 41 kg has to be done then we require 1,3,9,27,81 weights ...
i have taken time in it using cosine , give me some piece of advice
Puys ...i guess this is easy ..but i m unable to do it 😞
Number Systems - LOD 1 ..question - 55
Q. 55) If 2
a) 6
b) 7
c) 8
d) 4
e) none of these
ans is 4..as per arun sharma...plz help
Puys ...i guess this is easy ..but i m unable to do it 😞
Number Systems - LOD 1 ..question - 55
Q. 55) If 2
a) 6
b) 7
c) 8
d) 4
e) none of these
ans is 4..as per arun sharma...plz help
I thk its approximately 7, as the highest value of x can be 3.999+2.999/2.001-1.001 which ~7 but I may be wrong
EagleMenace SaysI thk its approximately 7, as the highest value of x can be 3.999+2.999/2.001-1.001 which ~7 but I may be wrong
I applied the same logic bro...in this case either the arun sharma's option is wrong or we are wrong :)
Not sure...
I applied the same logic bro...in this case either the arun sharma's option is wrong or we are wrong :)
Not sure...
Answer is 7 for sure. Arun Sharma has a lot of wrong answers. In cases where you feel your approach is right, consult someone else before relying on Arun Sharma's answers.
What is the sum of the digits of the decimal form of the product 2^999 * 5^1001?
options 1) 2
2) 4
3) 5
4) 7
5) 10
What is the sum of the digits of the decimal form of the product 2^999 * 5^1001?
options 1) 2
2) 4
3) 5
4) 7
5) 10
consider this like 2^n x 5^(n+2)
take n=1, =>250 sum is 7
another random trail to be sure
n=3, =>2^3 x 5^5 =>25000 sum is 7
Aliter
u know that 2^n x 5^n would give n zeroes, so in this problem u have (2^999x5^999)x5^2
=>25 followed by 999 zeroes..
Hence its always 7
For what relation between b and c is the number abcacb divisible by 7,if b>c?
a) b+c=7
b) b=c+7
c) 2bc=7
d) c=7b
Progressions : LOD 1- Q. no. 29
Q. The sum of the first four terms of an AP is 28 and the sum of the first eight terms of the same AP is 88. Find the sum of the first 16 terms of the AP ?
a) 346
b) 340
c) 304
d) 268
e) none of these
Sounds easy but could not understand the solution give in AS. 😞
Progressions : LOD 1- Q. no. 29take the equations, 14=2a+3d, 22=2a+7d
Q. The sum of the first four terms of an AP is 28 and the sum of the first eight terms of the same AP is 88. Find the sum of the first 16 terms of the AP ?
a) 346
b) 340
c) 304
d) 268
e) none of these
Sounds easy but could not understand the solution give in AS. :(
d=2 and a=4
For what relation between b and c is the number abcacb divisible by 7,if b>c?
a) b+c=7
b) b=c+7
c) 2bc=7
d) c=7b
My take option b) b= c+7
explanation: let b=8 so c=1 as 8=1+7
now let a=6 and put the values in abcacb i.e. 681618
now to check if this number is divisible by 7 or not check if difference of 681-618 is divisible by 7 or not. yes it is ...as 681-618 = 63...so answer is b=c+7..
please confirm
Please help...
The numeber of circles that can be drawn out of 10 points of which 7 are collinear is
1) 130 2) 85 3) 45 4) 72 5) can not be determined
Please help...
The numeber of circles that can be drawn out of 10 points of which 7 are collinear is
1) 130 2) 85 3) 45 4) 72 5) can not be determined
this question asked no of times go through this here - http://www.pagalguy.com/forum/quantitative-questions-and-answers/23813-quant-by-arun-sharma-285.html#post2292327
My take option b) b= c+7
explanation: let b=8 so c=1 as 8=1+7
now let a=6 and put the values in abcacb i.e. 681618
now to check if this number is divisible by 7 or not check if difference of 681-618 is divisible by 7 or not. yes it is ...as 681-618 = 63...so answer is b=c+7..
please confirm
Hi, Is this a method to check divisibility by 7 i.e. take the 1st half & subtract it with 2nd half..or is it just in this case??
Kindly revert.
Regards,
Dhairyesh.
abhi.kamble SaysYour answer is right...The book has lots of mistakes...ignore them
can u please show the complete solution to this question
thanx
For what relation between b and c is the number abcacb divisible by 7,if b>c?
a) b+c=7
b) b=c+7
c) 2bc=7
d) c=7b
according to me it can solve in this way...There is a rule of divisiblity of 7.Take the number and multiply each digit beginning on the right hand side (ones) by 1, 3, 2, 6, 4, 5. Repeat this sequence as necessary
1a+3b+2c+6a+4c+5b is divisible by 7.
so 7a+8b+6c is divisible by 7.
then we write it as 7a+7b+7c+b-c
so b-c is divisible by 7.
which is one option .i.e. (b).
how many integer values of x and y satisfy the expression 4x+7y=3 where mod x
my answer
y=3-4x/7
case 1 : when x is positive : result : y is negative
values satisfying are : (6,13, 20.....993)
apply L=a+(n-1)d
993-6=(n-1)*7
987/7=n-1
142=n
Now case 2 : when x is negative : result y is positive
values satisfying are : (1,8,15....995)
applying L=(n-1)d+a
995-1=(n-1)*7
n=143
total no of integer values satisfying the expression 143+142=285
answer given in book 284.
Am i missing something??
Hi,
I have a doubt in the following :
-The price of sugar is reduced by 25% but inspite of the decrease,Aayush ends up increasing his expenditure on sugar by 20%.What is the percentage change in his monthly consumption of sugar?
Kindly explain.
Hi,
I have a doubt in the following :
-The price of sugar is reduced by 25% but inspite of the decrease,Aayush ends up increasing his expenditure on sugar by 20%.What is the percentage change in his monthly consumption of sugar?
Kindly explain.
Its 60% increase...
Take the initial price is 20rs per kg ..And he spends 100rs,So its 5kg...
Now there is 25% decrease in the price,so its 15 per kg now..And now he spends 120rs and its 8kg now..So its 60%...:o:o:o