Quant by Arun Sharma

do tell the other solution also .....

guys i hav just strtd wid my CAT prep n m extremely weak at quant...please help my out..my doubts may be too easy for u guys to solve..here is a question from arun sharma
arjit being a party animal wants to hold as many parties as possible among his 20 frnds. howevr,his father has warned him that he will be financing his parties under the following conditions only:
a)the invitees hav to b among his 20 best frnds
b)he cant call the same set of frnds to a party more than once
c) the number of invites to evry party hav to be the same

given thse constraints arjit wants to hold the maximum number of parties.how many frnds shud he invite to each party?:-(

1) Circles are drawn with four vertices as the centre and radius equal to the side of a square. side of square is 2 sqrt 3. find the common area to all the four circles. ???

please give detailed solution


2) 6 circles of radius R touch externally each other and are placed in an equilateral triangle. the circles also touch the sides of the triangle. The area of the triangle is ?????

please give detailed solution
guys i hav just strtd wid my CAT prep n m extremely weak at quant...please help my out..my doubts may be too easy for u guys to solve..here is a question from arun sharma
arjit being a party animal wants to hold as many parties as possible among his 20 frnds. howevr,his father has warned him that he will be financing his parties under the following conditions only:
a)the invitees hav to b among his 20 best frnds
b)he cant call the same set of frnds to a party more than once
c) the number of invites to evry party hav to be the same

given thse constraints arjit wants to hold the maximum number of parties.how many frnds shud he invite to each party?:-(


Since for each party the no participants are same, u have select n friends out of 20 friend which gives the max value... So no of ways u select n friends out of 20 is the answer...So i tried different combos, u get max for 20c10....
PLEASE AVAIL THE LINK to download the book "QUANT BY ARUN SHARMA":-(
arshdeep_kapoor Says
PLEASE AVAIL THE LINK to download the book "QUANT BY ARUN SHARMA":-(


buddy, no copy righted materials here @ PG.. I would suggest to buy the book its worth every penny
1) Circles are drawn with four vertices as the centre and radius equal to the side of a square. side of square is 2 sqrt 3. find the common area to all the four circles. ???

please give detailed solution


2) 6 circles of radius R touch externally each other and are placed in an equilateral triangle. the circles also touch the sides of the triangle. The area of the triangle is ?????

please give detailed solution


I do not know how to get the exact answer but I can tell you the approach that can give you the answer if you use the options

1) Draw the figure. I wish I could paste it but it's too complex. You would get a symmetrical figure with two regions (like intersecting circles) along the two diagonal of the inside square. Now area of two quadrants of the circle mentioned - (minus) the area of the square will give you the are of one such region (the region formed when two circles intersect externally). Approx 1/3rd of this would be the answer. Change the options from pie to decimal and if none of these is given, like it is, move ahead. I am sorry but this is the best way to do this type of question.

2) The options for this question are very far apart. Just calculate the area of the equilateral triangle that would be formed by joining the center of the circles and assume R as 1. Only one option will remain. Try it, again this can be done approximation only.

I hope some1 else posts a precise solution.

I'd recommend you to go through the different types of problems given in 'Quantum CAT' by Sarvesh Kumar Verma. It helps a great deal in familiarizing one with newer puzzles and advanced questions, simple thumb rules and whole array of useful shortcuts. :):)

hi Scan002... how did u get that ans ???
please share ur solution ???

Hi,

There is a question in ARUN SHARMA, section Geometry - LOD 2, question no. 13, infact this question appeared last year's cat with slightly different data.

I could not find the answers though i slogged 😞 please help guys...
as per arun sharma answers is option a i.e. (sqrt 2 -1 )

Hi,

There is a question in ARUN SHARMA, section Geometry - LOD 2, question no. 13, infact this question appeared last year's cat with slightly different data.

I could not find the answers though i slogged 😞 please help guys...
as per arun sharma answers is option a i.e. (sqrt 2 -1 )



Please let me know guys if you need figure for this question.....i assumed that all of us have a copy of arun sharma
scan002 Says
hey is the OA= (7*sqrt3+12)R^2



can you please explain the solution too ?

not evryone has Arun Sharma book, so post the question to get the solution...

EagleMenace Says
not evryone has Arun Sharma book, so post the question to get the solution...



Yup will that soon....However , is it enough if i complete arun sharma for quants or other prep resources are required too ?
EagleMenace Says
not evryone has Arun Sharma book, so post the question to get the solution...


Here is the the question:

Q. 13 LOD-2 Geometry
If ABC is a quarter and a cirlce is inscribed in it and if AB = 1cm , find the radius of the smaller circle.

I m not sure how to provide you fig. here...i hope u guys can draw the pic by yourself...

Please help

1. The number of circles that can be drawn out of 10 points of which
7 are collinear is
a) 130
b) 85
c) 45
d) 72
e) CBD
2. A dices is rolled six times. one, two, three, four, five, and six
appears on consecutive throws of dices. How many ways are possible
of having 1 before 6?
a) 120
b) 360
c) 240
d) 380
e) 280
3. The number of permutation of the letters a, b, c, d, e, f, g such that
niether the pattern 'beg' nor pattern 'acd' occurs is
a) 4806
b) 420
c) 2408
d) 140
e) None of these
4. In an examination, the maximum marks for each of the three papers
is 50 each. The maximum marks for the forth paper is 100. Find the
number of ways with which a student can score 60% marks in
aggregate.
a) 3,30,850
b) 2,33,551
c) 1,10,551
d) 2,20,800
e) None of these

1) we need 3 non collinear points to draw a circle... there are three cases

case 1 - 2 collinear and one non collinear
7c2x3c1=63

case 2 - from 2 non collinear and one collinear point
3c2x7c1=21

case3- from 3 non collinear points
3c3=1
total 85 ways...

2)first choose two places for one and six.. This can be done in 6c2 ways... Out these two positions u can arange them in just one way...=> - - 1- - 6 or any other selection

remaining 4 dies can be arranged in 4! ways...
=>6c2x4!=360

3)total no of ways u can arrange them is 7!

no of ways when combo beg appears is 5!

no of ways when combo acd appears is 5!

no of ways `acd` and `beg` appears is 3!

=>7!-5!x2-3!
=>4794 =>someone please confirm this.. my ans not in options could well be a mistake in arun shamra

4)I have tried many times but couldn`t get the answer given


3. The number of permutation of the letters a, b, c, d, e, f, g such that
niether the pattern 'beg' nor pattern 'acd' occurs is
a) 4806
b) 420
c) 2408
d) 140
e) None of these

Its 7!-((2*5!)+3!)=4806:D:D
Ganu02 Says
Its 7!-((2*5!)+3!)=4806:D:D


hi Ganu02, pls re-calculate.. That is what I have done too.. Answer is coming out to be 4794
EagleMenace Says
hi Ganu02, pls re-calculate.. That is what I have done too.. Answer is coming out to be 4794

hey a typing mistake..You got to add that 3!..
when taking the first pattern acd its 5! and for second pattern beg its 5!...
But in these both pattern we deduce the same six sequence twice...So it is
7!-(2*5!)+3!=4806...