1. how many 4 digit number divisible by 5 can be formed with digit 0,1,2,3,4,5,6 and 6?
a. 220
b. 588
c. 432
d. 216
e. 288
seven different objects must be divided among three people. in how many ways can this be done
*if one or two of them must get no objects? ans 381
*if at least one of them gets exactly one object? ans 1176
somebody explain...
Got ans for 1st part
Case I : Only 1 of them gets 0 objects;
So now we have to distribute 7(n) distinct object among 2 (r) different persons which can be done in r^n ways i.e. 2^7 ways which comes out to be 128....But two cases in which one of them gets zero or all seven have to be eliminated i.e. (0,7) & (7.0) distribution coz this violates our basic assumption (only one of them gets zero) ....thus actual way of distribution = 126
Now the person who does not get any object can be selected in 3 ways....And each combination can be arranged in 126 ways
=> Total no. of combinations = 126 * 3
Case II : Two of them get 0 objects;
It is pretty simple....One of them will get all the objects......Person who gets all all the objects can be selected in 3 ways (any one of the three)
Thus, Total no. of ways = 126*3 + 3
1. how many 4 digit number divisible by 5 can be formed with digit 0,1,2,3,4,5,6 and 6?
a. 220
b. 588
c. 432
d. 216
e. 288
Plz specify que. properly; Is repetition of digit is allowed or not???????????
If not alllowed :
Case I : No. ends with 5;
Thousand's digit can be selected in 5 ways (one of 1,2,3,4,6)
Hundreds digit can be selected in 5 ways (out of 0 and four digits remaining out of previous selection )
Ten's digit can be selected in 4 ways
Total no. of numbers = 5*5*4
Case II : No. ends with 0
Thousand's digit can be selected in 6 ways (one of 1,2,3,4.5,6)
Hundreds digit can be selected in 5 ways
And tens digit in 4 ways
Total no. of numbers = 6*5*4
=> Total nos. divisible by 5 = 5*5*4 + 6*5*4 = 11*20 = 220 ways
IF REPETITION IS ALLOWED
Thousand's digit in 6 ways
Hundreds digit in 7 ways
Tens digit in 7 ways
and units digit in 2 ways (5 or 0)
Total no. of numbers = 6*7*7*2 = 588 ways
1. how many 4 digit number divisible by 5 can be formed with digit 0,1,2,3,4,5,6 and 6?
a. 220
b. 588
c. 432
d. 216
e. 288
Cases:
_ _ _ _
When 0, is selected to be at the units place:
We can select the remaining 3 digits in 6c3 ways. and permute them in 3! factorial ways.
Therefore 6c3*3!
Case II) When 5 is at units place- and 0 is not selected 5c3 * 3!
When 5 is at units place ant 0 is selected - 5c2*(2!)^2
Total: 6c3*3!+ 5c3*3! +5c2*(2!)^2 =220
plz solve
1. A racetack is in form of a right triangle. The longer legs of track is 2 km more than the shorter leg (both these legs being on highway). The start and end points are also connected to each other through side road. The escort vehicle for the race took the side road and rode with speed of30 kmph and then covered the two intervals along the highway during the same time with a speed of 42 kmph. Find the length of racetrack.
a.14km
b. 10km
c. 24km
d. 36km
e. 30km
Find the 28383rd term of the series 123456789101112....
a) 3 b) 4 c) 9 d) 7
My answer is coming out as a) 3, but the answer is given as c) 9. :banghead:
Please help...
1. How many numbers between 200 and 1200 can be formed with the digits 0, 1, 2, 3 (repition of digits not allowed)?
a) 6
b) 8
c) 2
d) 14
e) 16
2. In above question, if repetition of digits is allowed, then how many numbers can be formed ?
a) 48
b) 63
c) 32
d) 14
e) 20
3. How many ways are there to choose four cards of differenr suits and different values from a desk of 52 cards ?
a) 13.12.11.10
b) 52c4
c) 13^4
d) 52.36.22.10
4. There are ten subjects in the school day at St. Vincent's High School, but the sixth standard students have only 5 periods in a day. In how many ways can we form a time-table for the day for the sixth standard students?
a) 5^10
b) 10^5
c) 252
d) 30,240
Find the 28383rd term of the series 123456789101112....
a) 3 b) 4 c) 9 d) 7
My answer is coming out as a) 3, but the answer is given as c) 9.
Please help...
Your answer is right...The book has lots of mistakes...ignore them
1. How many numbers between 200 and 1200 can be formed with the digits 0, 1, 2, 3 (repition of digits not allowed)?
d) 14
2. In above question, if repetition of digits is allowed, then how many numbers can be formed ?
b) 63
3. How many ways are there to choose four cards of differenr suits and different values from a desk of 52 cards ?
d) 52.36.22.10
4. There are ten subjects in the school day at St. Vincent's High School, but the sixth standard students have only 5 periods in a day. In how many ways can we form a time-table for the day for the sixth standard students?
b) 10^5
abhi.kamble SaysYour answer is right...The book has lots of mistakes...ignore them
Here's the link for solution....The answer is 9...
http://www.pagalguy.com/forum/quanti...ml#post1636356 (Quant by Arun Sharma)
plz solve
1. A racetack is in form of a right triangle. The longer legs of track is 2 km more than the shorter leg (both these legs being on highway). The start and end points are also connected to each other through side road. The escort vehicle for the race took the side road and rode with speed of30 kmph and then covered the two intervals along the highway during the same time with a speed of 42 kmph. Find the length of racetrack.
a.14km
b. 10km
c. 24km
d. 36km
e. 30km
length of race track = 24 km
so, option c).
the 2 highways are 6 and 8 km long and the side road is 10 km long.
length of race track = 24 km
so, option c).
the 2 highways are 6 and 8 km long and the side road is 10 km long.
The longer legs of track is 2 km more than the shorter leg
well according to u, roads are 6,8 and 10km long... But from the problem u can make out that its a right angled isoscles triangle...
I am getting mismatches in answers.....Plz provide the solution....
1. Find the area of quadrant of a circle whose circumference is 44cm.
My take : pi * r/2 + 2r = 44
=> r (11/7 + 2) = 44
=> r = 44 * (7/25)
=> Area = pi*r*r/4 = 12.3 * 12.3 * 3.14 / 4 = 118.7
Given ans. 38.5
2. A wooden box measures externally 10 cm long, 8 cm broad, 6 cm high. Thickness of wood is .5 cm . Find the volume of wood used.
My take : Vol. of wood = 2*(10*8*0.5 + 10*6*0.5 + 8*6*0.5) = 188
Given ans. = 150 
I am getting mismatches in answers.....Plz provide the solution....
1. Find the area of quadrant of a circle whose circumference is 44cm.
My take : pi * r/2 + 2r = 44
=> r (11/7 + 2) = 44
=> r = 44 * (7/25)
=> Area = pi*r*r/4 = 12.3 * 12.3 * 3.14 / 4 = 118.7
Given ans. 38.5
for 1 st
2*pi*r=44
r=7
pi*r^2=>154
=>154/4
=>38.5
2. A wooden box measures externally 10 cm long, 8 cm broad, 6 cm high. Thickness of wood is .5 cm . Find the volume of wood used.volume is lbh
=>10x8x0.5x2 + 5 x 8 x0.5x2 + 9 x 5 x 0.5 x 2
=165
Originally Posted by abhi.kamble
Your answer is right...The book has lots of mistakes...ignore them
Here's the link for solution....The answer is 9...
http://www.pagalguy.com/forum/quanti...ml#post1636356 (Quant by Arun Sharma)
Here is the link again
http://www.pagalguy.com/forum/quantitative-questions-and-answers/23813-quant-by-arun-sharma-167.html#post1636356
And the answer mentioned there is also 3. Quoting from the link
avinav2712 SaysAnswer should be a) 3.
d) 52.36.22.10
b) 10^5
1st 2 are correct.........bt ans for 3rd and 4th ques. is
3. a) 13.12.11.10
4. d) 30,240
as given in book......bt m also getting the same ans as yours......
for 1 st
2*pi*r=44
r=7
pi*r^2=>154
=>154/4
=>38.5
Feelin ShamefulInterpreted Quadrant as quarter
volume is lbh
=>10x8x0.5x2 + 5 x 8 x0.5x2 + 9 x 5 x 0.5 x 2
=165
Interpreted Quadrant as quarterCouldn't be more silly....forgot abt -1...
:banghead:
1) Circles are drawn with four vertices as the centre and radius equal to the side of a square. side of square is 2 sqrt 3. find the common area to all the four circles. ???
please give detailed solution
2) 6 circles of radius R touch externally each other and are placed in an equilateral triangle. the circles also touch the sides of the triangle. The area of the triangle is ?????
please give detailed solution
2) 6 circles of radius R touch externally each other and are placed in an equilateral triangle. the circles also touch the sides of the triangle. The area of the triangle is ?????
please give detailed solution
hey is the OA= (7*sqrt3+12)R^2
scan002 Sayshey is the OA= (7*sqrt3+12)R^2
yes ,,,, pls tell how did u get this ??? the approach