i bought 10 pens ,14 pencils,4 erasers. my frend bought 12 pens, 28 pencils, 8 erasers. He paid half more than what i paid. How much percentage of my amount i paid corresponds to pens?
1st equation: 10P + 14p + 4E = 160 (can assume any value, I assumed total as 160)
2nd equation: 12P + 28p + 8E = 240 (160 x 1.5 = 240)
1st x 2 = 20P + 28p + 8E = 320
Subtracting 2nd from this equation,
8P = 80 P = 10
Thus, putting in the 1st equation, the cost of pens is 10P = 10 x 10 = 100
Thus, %age is 100/160 = 62.5 %
Hope you understood.
10P + 14p + 4E = 1 (since i paid 1,my friend paid 1.5 times of mine) (1)
12P + 28p + 8E = 1.5 (2)
Now, (1)* 2 gives 20P + 28P + 8E =2 (3)
Now (3) - (2) gives 8P = 0.5 10P = 0.5 * 10/8 = 0.625 (in fractions) = 62.5 %
PS : Another method which might be useful for some other scenarios
My approach is - let the 5 numbers be a>b>c>d>e. So a+b = 29 a+c=23 a+d=18 a+e=16. So b+c = 15. But 2a+b+c=52, so b+c=52-2a(Even).But we have taken b+c= 15. So we need to look back at the equations. We assumed that a+d > b+c here which is not true. SO a+d So I took b+c =18 and solved for all 5 numbers.
2. A train takes 2 h less for a journey of 300 kms if its speed is increased by 5 kmph over its usual speed? What is the usual speed? A:25 3. A plane left half an hour later than the sheduled time in order to reach its destination 1500 kms away in time,it had to increase its speed by 33.33 percent over the usual speed. Find increased speed A:248 ...this is difference tht i posted...ANS REQUIRED is 998~1000 4. A person traveelled a distance of 200 kms btw two cities by a car overing the first quarter at a const speed of 40 km/h and the remng three quarter at a const speed of x km/h. I f the avg speed of person fpr entire journey wast 53.33 what is the value of x A:60
5. In a 100 m race shyam runs at 1.66 m/s. If hsyam gives sujit a start of 4m and still beats him by 12 seconds, what is sujits speed A:1.32 m/s
6. At a game, A gives B 15 pts in 60 ,A gives 6 20 pts in 60 . Hw mch does B gives C in 90 NOT CLEAR
7. In a 500 m race the ratio of speed of two runners a and b is 3:4. If A has a start of 140 m, A wins by? A:20m Plz Post OA
6) A : B = 45 : 15 A : C = 40 : 20 B : C = 15/45 * 40/20 = 2 : 3 = 36 : 54 (out of 90)
i hav a doubt in time n work: LOD 2, ques 5: A finishes 6/7th of the work in 2z hours, B works twice as fast n complestes d remaining work.For how long did B work?
i hav a doubt in time n work: LOD 2, ques 5: A finishes 6/7th of the work in 2z hours, B works twice as fast n complestes d remaining work.For how long did B work?
Since A finishes 6/7th of the work, B needs to finish 1/7th of the work. To finish this at A's speed, it will take 2z/6 = z/3 hrs. Since B works twice as fast, the time taken by him would be z/6 hrs.
I have got a doubt In a solved example of Number systems.. Prob 1.19- Find what maximum value of n will the expression 10200!/ 504^n be an integer?? sol:- in the shortcut process it is mentioned that as 504=2^3 * 3^2 * 7 and 7>3*2 that is why the numbers of 7s will be less than 2*3 & 3*2 .. pls explain it ...
I have got a doubt In a solved example of Number systems.. Prob 1.19- Find what maximum value of n will the expression 10200!/ 504^n be an integer?? sol:- in the shortcut process it is mentioned that as 504=2^3 * 3^2 * 7 and 7>3*2 that is why the numbers of 7s will be less than 2*3 & 3*2 .. pls explain it ...
Exponent of 2 in 10200! = 10192 Exponent of 2^3 in 10200! = 3397 Exponent of 3 in 10200! = 5094 Exponent of 3^2 in 10200! = 2547 Exponent of 7 in 10200! = 1698
Thus Exponent of 504 in 10200! = min(3397,2547,1698 ) = 1698
hey puys, I have a doubt in Arun sharma`s profit and loss level 2 difficulty problem...
A driver of a autorickshaw makes a profit of 20% on every trip when he carries 3 passengers and the price of petrol is Rs30 a litre. Find the percentage profit for the same journey if he goes for 4 passengers/trip and the price petrol is reduced to 24 a trip? (Assume that revenue/passenger is the same in both cases).. 1)33.33 2)65.66 3)100 4)data inadequate
hey puys, I have a doubt in Arun sharma`s profit and loss level 2 difficulty problem...
A driver of a autorickshaw makes a profit of 20% on every trip when he carries 3 passengers and the price of petrol is Rs30 a litre. Find the percentage profit for the same journey if he goes for 4 passengers/trip and the price petrol is reduced to 24 a trip? (Assume that revenue/passenger is the same in both cases).. 1)33.33 2)65.66 3)100 4)data inadequate
I Dont where I am going wrong answer is 100%.
Pretty simple actually. Let the distance to be covered can be travelled by the auto in one litre of petrol.
Thus, if the price of petrol is Rs. 30 and he makes a profit of 20%, i.e. he gets Rs. 36 from 3 passengers, i.e. 36/3 = Rs. 12 per passenger
Now, price of petrol becomes Rs. 24 and he takes 4 passengers.
Pretty simple actually. Let the distance to be covered can be travelled by the auto in one litre of petrol.
Thus, if the price of petrol is Rs. 30 and he makes a profit of 20%, i.e. he gets Rs. 36 from 3 passengers, i.e. 36/3 = Rs. 12 per passenger
Now, price of petrol becomes Rs. 24 and he takes 4 passengers.
Thus, his income = 4 x 12 = Rs. 48
Thus, 48/24 = 2, i.e. 100% profit :)
eheh that was pretty simple.. Wonder i have to work even harder...:-(
I took 2Rs per passenger since the profit he got was 6Rs... And got this problem completely messed.. But its revenue here so it also includes entire income.. Thx avinav2712
eheh that was pretty simple.. Wonder i have to work even harder...:-(
I took 2Rs per passenger since the profit he got was 6Rs... And got this problem completely messed.. But its revenue here so it also includes entire income.. Thx avinav2712
