In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?
(A) 1(B) 2(C) 3(D) 4(E) 6
@bs0409 said:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
Always, 3.
Given any triangle, we can make 3 parallelograms of which the triangle is half, by rotating the triangle by 180 degrees around the midpoint of each side...
regards
scrabbler
Given any triangle, we can make 3 parallelograms of which the triangle is half, by rotating the triangle by 180 degrees around the midpoint of each side...
regards
scrabbler
@jashholmes said:In what ratio should a shopkeeper mix almonds costing Rs 58 per kg with almonds costing Rs 66 per kg, such that by selling them at 75 per kg, the shopkeeper makes a profit of 25%???
75/1.25 = 60
So ratio = (66-60) / (60-58) = 3:1
So ratio = (66-60) / (60-58) = 3:1
@bs0409 said:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3?
The avarage age of group decreased by 3 years when a person 56 years old was replaced by another 20 years old . How would the average age have changed, if he were replaced by 2 persons of 32 years each instead???
@bs0409 said:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3 parallelograms are possible.
@scrabbler said:Always, 3.Given any triangle, we can make 3 parallelograms of which the triangle is half, by rotating the triangle by 180 degrees around the midpoint of each side...regardsscrabbler
@mailtoankit said:3?
@catahead said:3 parallelograms are possible.
OA-3
There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?
(1)28 (2) 25 (3)22 (4)16 (5) 15
@bs0409 said:OA-3There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?(1)28 (2) 25 (3)22 (4)16 (5) 15
I think 25. Trying to prove it!
regards
scrabbler
@bs0409 said:OA-3There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?(1)28 (2) 25 (3)22 (4)16 (5) 15
is the answer 15?
A bartender stole champagne frm a bottle that contained 50% of spirit and he replaced what he had stolen with champagne having 20% spirit. The bottle then contain only 25% spirit.How much of the bottle did he steal?
1>80% 2>83.33% 3>85.71% 4>88.88%
@maroof10 said:A bartender stole champagne frm a bottle that contained 50% of spirit and he replaced what he had stolen with champagne having 20% spirit. The bottle then contain only 25% spirit.How much of the bottle did he steal?1>80% 2>83.33% 3>85.71% 4>88.88%
ans 2?
@bs0409 said:OA-3There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?(1)28 (2) 25 (3)22 (4)16 (5) 15
Shud be 25
@bs0409 said:OA-3There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?(1)28 (2) 25 (3)22 (4)16 (5) 15
OK trying to explain my logic, was trying to do it orally and tried the follwowing....Here goes nothing....
There are some n consecutive numbers and one of them (say k) is removed. When divided by n-1, the answer is (something)/24. Is it too much to assume that n-1 = 24 and hence n is 25?
So, then, 25 numbers averaging either 32 (in which case k 33 to lower the average)
If the average of the 25 numbers is 32, then removing 32 will leave the average same. Average increases by 7/24 so total increased by 7 so we must have removed k = 32 - 7 = 25.
If the average is 33 then we must have reduced average by 17/24 so reduced total by 17 so k must be 33 + 17 = 50
Hence possible answers 25 and 50 and I will stick to my original pick of 25.
OA pliss?
regards
scrabbler
@maroof10 said:A bartender stole champagne frm a bottle that contained 50% of spirit and he replaced what he had stolen with champagne having 20% spirit. The bottle then contain only 25% spirit.How much of the bottle did he steal?1>80% 2>83.33% 3>85.71% 4>88.88%
ans 2?
@maroof10 said:A bartender stole champagne frm a bottle that contained 50% of spirit and he replaced what he had stolen with champagne having 20% spirit. The bottle then contain only 25% spirit.How much of the bottle did he steal?1>80% 2>83.33% 3>85.71% 4>88.88%
5/6 or 83.33?
Same logic 20........50
......................25
Difference - 5 : 25 or 1 : 5 hence ratio 5 : 1 and hence 1/6th was left.
regards
scrabbler
Same logic 20........50
......................25
Difference - 5 : 25 or 1 : 5 hence ratio 5 : 1 and hence 1/6th was left.
regards
scrabbler
@iLoveTorres said:is the answer 15?
@catahead said:Shud be 25
@scrabbler said:OK trying to explain my logic, was trying to do it orally and tried the follwowing....Here goes nothing....There are some n consecutive numbers and one of them (say k) is removed. When divided by n-1, the answer is (something)/24. Is it too much to assume that n-1 = 24 and hence n is 25?So, then, 25 numbers averaging either 32 (in which case k 33 to lower the average)If the average of the 25 numbers is 32, then removing 32 will leave the average same. Average increases by 7/24 so total increased by 7 so we must have removed k = 32 - 7 = 25.If the average is 33 then we must have reduced average by 17/24 so reduced total by 17 so k must be 33 + 17 = 50Hence possible answers 25 and 50 and I will stick to my original pick of 25.OA pliss?regardsscrabbler
OA-25.........
a,b,c are positive real numbers and a^2+b^2+C^2=48
find the maximum value of a+b+c???
@bs0409 said:OA-25.........a,b,c are positive real numbers and a^2+b^2+C^2=48find the maximum value of a+b+c???
ans 12?
@bs0409 said:OA-25.........a,b,c are positive real numbers and a^2+b^2+C^2=48find the maximum value of a+b+c???
48*3 >= (a+b+c)^2
(a+b+c) =
How long is the side of the largest equilateral triangle that can be inscribed in a square whose side has length 1?
A. 1
B. √5/2
C. 3√5/4
D. 2-√3
E. √(8-4√3)
Please show your approach.