Official Quant thread for CAT 2013

MBA CAT 2024
19226
The lowest platelet count in human blood is 50,000 . The leukemia reduces the platelet count in the blood and a dose of radiation has to be given if it falls under 10,000 . For a person suffering from leukemia the blood platelet out is taken every fortnight over a cycle of two months . 51000,44500,38250,32125... And the trend is continued in the same manner . When should the radiation dose be given ?







19227
@meenu05 said:
The lowest platelet count in human blood is 50,000 . The leukemia reduces the platelet count in the blood and a dose of radiation has to be given if it falls under 10,000 . For a person suffering from leukemia the blood platelet out is taken every fortnight over a cycle of two months . 51000,44500,38250,32125... And the trend is continued in the same manner . When should the radiation dose be given ?
after 4 months?
19228
@iLoveTorres

yes can you explain ?

19229
@meenu05 said:
@iLoveTorres yes can you explain ?
its an ap with d=-125.. look at the numbers you will be clear
19230
@ChirpiBird thanks..
19231
sorry i wasnt elaborate.. consider 51000-44500=6500,44500-38250=6250,38250-32125=6125... now consider 6500-6250=250 6250-6125=125

hope you are able to proceed from here
19232
A vessel is full of mixture of kerosene and petrol in which there is 18% kerosene. 8 litres are drawn off and then the vessel is filled with petrol.If the kerosene is now 15%,how much does the vessel hold?

plz suggest a quicker way to approach this problem..
19233
@maroof10 said:
A vessel is full of mixture of kerosene and petrol in which there is 18% kerosene. 8 litres are drawn off and then the vessel is filled with petrol.If the kerosene is now 15%,how much does the vessel hold? plz suggest a quicker way to approach this problem..
48 litres?
19234
@maroof10 said:
A vessel is full of mixture of kerosene and petrol in which there is 18% kerosene. 8 litres are drawn off and then the vessel is filled with petrol.If the kerosene is now 15%,how much does the vessel hold? plz suggest a quicker way to approach this problem..
let the quantity be V litres.
now kerosine is 0.18 V and petrol 0.82V
Keros/petrol = 9/41

8 litres are drawn so it will be drawn in the ratio of 9/41

.18V - 8*(9/50) =.15V

solve it
19235
@maroof10 said:
A vessel is full of mixture of kerosene and petrol in which there is 18% kerosene. 8 litres are drawn off and then the vessel is filled with petrol.If the kerosene is now 15%,how much does the vessel hold? plz suggest a quicker way to approach this problem..
look when 8 litres are drawn out 8*.82 litres of petrol is drawn out.. now you are replacing it with 8 litres of petrol. so 1.44 litres of petrol when added results in 3% change.. so 100% change would be when you add 48 litres. so this s the capacity
19236

In Triangle MNO, MN=MO and NO=4.5cm. P is a point on the side MO such that (NO)^2=(MO)*(PO). Find the length of NP.
A- 2.25 cm
B- 3 cm
C- 4 cm
D- 4.5 cm

Please show your approach 😁

19237
@DeAdLy said:
do explain...don't just post the answer
I wished to know the OA? I think I interpreted it wrongly...I took the 2/3 as the probability of "knowing the answer" instead of that of "finally getting it right"; I think the latter is more appropriate. I guess the right answer should be 5/6....someone else already solved it while I was updating my answer so I didn't post.

Probability of solving a question correct is 2/3. Also it is known that, if answer is not known then guess will be made. probability of guessing a question right is 1/4. so if we know that a question is answered & it is correctly answered. find the probability of him knowing the answer?

regards
scrabbler
19238
@maroof10 said:
A vessel is full of mixture of kerosene and petrol in which there is 18% kerosene. 8 litres are drawn off and then the vessel is filled with petrol.If the kerosene is now 15%,how much does the vessel hold? plz suggest a quicker way to approach this problem..
Kerosene was earlier 18% and is now 15% of same volume. So it has become 5/6 of earlier. So we must have removed 1/6th. So if 1/6 is 8 litres, volume is 48 litres!

regards
scrabbler
19239
@realslimshady said:
In Triangle MNO, MN=MO and NO=4.5cm. P is a point on the side MO such that (NO)^2=(MO)*(PO). Find the length of NP.A- 2.25 cmB- 3 cmC- 4 cmD- 4.5 cmPlease show your approach
4.5 only. Similar triangles.

From the given info, PO/NO = NO /MO. Also there is a common angle. So the two triangles MNO and NPO are similar. If MN = MO, then NP = NO and hence NP = 4.5 as well.

regards
scrabbler
19240
@maroof10 said:
A vessel is full of mixture of kerosene and petrol in which there is 18% kerosene. 8 litres are drawn off and then the vessel is filled with petrol.If the kerosene is now 15%,how much does the vessel hold? plz suggest a quicker way to approach this problem..
let the capacity of vessel be x
kerosene = .18x
petrol = .82x
ratio of kerosene and petrol = .18/.82

.18x - 8*.18/(.18 + .82) = .15x
x = 48 liters ?
19241
@scrabbler said:
4.5 only. Similar triangles.From the given info, PO/NO = NO /MO. Also there is a common angle. So the two triangles MNO and NPO are similar. If MN = MO, then NP = NO and hence NP = 4.5 as well.regardsscrabbler
bro how did you conclude PO/NO = NO/MO?
19242
Sunil and Ajay went to a pub and ordered two cocktails, each of which comprised of bear, vodka and wine in the ratio 2 : 1 : 2. Sunil, a regular boozer, fooled Ajay by drinking 17 ml from his drink and replacing the same quantity by soda. If after replacement, the percentage of wine in Ajay ₮â„Ēs glass was 30%, what was the quantity (in ml) of drink served in each cocktail?
A. 51 B. 68 C. 85 D. 40 E. Cannot be determined
19243
@scrabbler thanks....
19244
In what ratio should a shopkeeper mix almonds costing Rs 58 per kg with almonds costing Rs 66 per kg, such that by selling them at 75 per kg, the shopkeeper makes a profit of 10%???
19245
@iLoveTorres said:
bro how did you conclude PO/NO = NO/MO?
P is a point on the side MO such that (NO)^2=(MO)*(PO). Apply algebra! :)

regards
scrabbler