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Le solve kar.
A and b can do a work in 7 days. If a does twice as much as work as b in the given time, how long will a take to do the work.
@saurabhlumarrai said:Q-2:Find the solution:
@saurabhlumarrai said:a)[(2^1/2)-1]^2 a)2*[(2^1/2)-1]^2 a)[[(2^1/2)-1]^2]/2d)None of these
Koi iska bhi jawab bta do...
@vbhvgupta said:Le solve kar.A and b can do a work in 7 days. If a does twice as much as work as b in the given time, how long will a take to do the work.
7/2 days?
@vbhvgupta said:Le solve kar.A and b can do a work in 7 days. If a does twice as much as work as b in the given time, how long will a take to do the work.
21/2
yaar kuch naya topic churu karte hain..time & speed??
Successive Division Method:
Rule-wise the solution is correct, I think. But if 94 is divided by 6 the remainder is 4, NOT 5. Then what's wrong here? (I am just concerned about finding out the number, not the remainders asked in the question).
Rule-wise the solution is correct, I think. But if 94 is divided by 6 the remainder is 4, NOT 5. Then what's wrong here? (I am just concerned about finding out the number, not the remainders asked in the question).
@saurabhlumarrai said:a)[(2^1/2)-1]^2 a)2*[(2^1/2)-1]^2 a)[[(2^1/2)-1]^2]/2d)None of these
bhai i am getting [(2^1/2)-1]^4 as the answer
@aakhrijang said:Successive Division Method:Rule-wise the solution is correct, I think. But if 94 is divided by 6 the remainder is 4, NOT 5. Then what's wrong here? (I am just concerned about finding out the number, not the remainders asked in the question).
buddy its successive see 94/4 = 23 and remainder is 2 23/6 = 3 and remainder is 5 and now
3/7 = 0 remainder 3
2nd time u dont have to divide 94 by 6 as it is successive it shd be 23/6
@vbhvgupta said:Le solve kar.A and b can do a work in 7 days. If a does twice as much as work as b in the given time, how long will a take to do the work.
21/2
@aakhrijang said:Successive Division Method:Rule-wise the solution is correct, I think. But if 94 is divided by 6 the remainder is 4, NOT 5. Then what's wrong here? (I am just concerned about finding out the number, not the remainders asked in the question).
it is successive division which means if you take 10. Now when you divide it by 3 you get a remainder 1. Now when you divide it again by 2 you again get a remainder 1. here the logic is you divide the quotient not the number.
A number repeated 6n times is divisible b ATLEAST how many prime numbers???
AND HOW?
aaaaaa...6n times is divisible by how many prime nos?
@Virinder said:A number repeated 6n times is divisible b ATLEAST how many prime numbers???AND HOW?aaaaaa...6n times is divisible by how many prime nos?
ans 7,11,13 are the prime numbers it should surely be divisible by
@hatemonger said:@vbhvgupta for the time and work question is it right?? a and b can do work in 7 days...
han
@iLoveTorres - Partly right...
whats your approach btw?
Still more prime no.s it'll be divisible by...