HELP !
In the table tennis the first player to score 21 points win.Service alternates between two players every five points.A player can score points both during his service and his opponent service.raj beats anil 21-16 in a game.24 of the 37 point played were won by the player serving. Who served first?
options
A)RAJ
B)ANIL
C)INDETERMINATE
For a candidate to be selected at a junior management position in a company, he must
be a Mechanical Engineer or have a diloma from ITI with at least 60% marks.
have secured at least 60% marks in the selection test.
have scored at least 50% marks in the interview.
be not less than 23 years of age and not more than 30 years of age on 1.10.2012.
have completed course on CFM.
If the candidate satisfies all conditions expect C, but has cleared the course of NCFM, his/her case should be referred to the HR head.
If the candidate satisfies all conditions expect D, but has two years of work experience in the mechanical industry, his/her case should be referred to the General Manager.
Based on the above information, decide the course of action.
Mark option:
(1) If the candidate is to be selected
(2) If the candidate is to be rejected
(3) If the case to be referred to the General Manager.
(4) If the case to be referred to the HR head
Akshay got 62% marks in the selection test and scored 51% in the interview. He has an ITI diploma with 65% marks. His date of birth is 23rd September 1982. He has completed his course on CFM and has 3.5 years of work experience in company XYZ, which is one of the biggest mechanical companies of the country. He has also cleared the course of NCFM.
1) 1 2) 2 3) 3 4) 4
be a Mechanical Engineer or have a diloma from ITI with at least 60% marks.
have secured at least 60% marks in the selection test.
have scored at least 50% marks in the interview.
be not less than 23 years of age and not more than 30 years of age on 1.10.2012.
have completed course on CFM.
If the candidate satisfies all conditions expect C, but has cleared the course of NCFM, his/her case should be referred to the HR head.
If the candidate satisfies all conditions expect D, but has two years of work experience in the mechanical industry, his/her case should be referred to the General Manager.
Based on the above information, decide the course of action.
Mark option:
(1) If the candidate is to be selected
(2) If the candidate is to be rejected
(3) If the case to be referred to the General Manager.
(4) If the case to be referred to the HR head
Akshay got 62% marks in the selection test and scored 51% in the interview. He has an ITI diploma with 65% marks. His date of birth is 23rd September 1982. He has completed his course on CFM and has 3.5 years of work experience in company XYZ, which is one of the biggest mechanical companies of the country. He has also cleared the course of NCFM.
1) 1 2) 2 3) 3 4) 4
@IIM-A2013 said:A motorboat moves from point A to point B and back again. Both points being located on the river bank. If the speed of the boat in still water is doubled, then the trip from A to B and back again would take 20% of the original time . The ratio of the actual sped of motorboat to the speed of river is?a (3/2)^1/2 b (3^1/2)/3 c 2/3 d 3/2
Let speed of boat b and speed of river r.
t=d/b+r + d/b-r
0.2t=d/2b+r + d/2b-r
Divide both the equations:
b/r=(2/3)^1/2 .Hence option a
@sbharadwaj said:Q. A, B and C work together to complete some work. A takes thrice the time taken by the other two to complete the same work whereas B takes 6 times the time taken by the other two to complete the same. What part of the work was completed by C?a)17/28b)1/4c)17/56d)4/7Plz solve
1/a=1/3 * (1/b + 1/c)
1/b =1/6 * (1/a +1/c)
Solving both the equations:
17c=4b
Also 1/a+1/b+1/c=1
1/3*(4/17c + 1/c) + 4/17c + 1/c =1
c=17/28
If x= √3/2 then what is the value of (1+x)/(1+√(1+x))+(1-x)/(1-√(1-x))
A)√3/2
B)√3
C)0
D)1
A)√3/2
B)√3
C)0
D)1
@pankaj1988 said:If x= √3/2 then what is the value of (1+x)/(1+√(1+x))+(1-x)/(1-√(1-x))
A)√3/2
B)√3
C)0
D)1
1+x +(1+x)^3/2 +1-x-(1-x)^3/2
2+[(1+x)^1/2-(1-x)^1/2][1+x +1-x +(1-x^2)^1/2]
2+[(1+x)^1/2-(1-x)^1/2][2+(1-3/4)^1/2]
2+[(1+x)^1/2-(1-x)^1/2][2+1/2]
bhai ye to 2 se bada aa rha h
are the options correct?
@Subhashdec2 said:1+x +(1+x)^3/2 +1-x-(1-x)^3/22+[(1+x)^1/2-(1-x)^1/2][1+x +1-x +(1-x^2)^1/2]2+[(1+x)^1/2-(1-x)^1/2][2+(1-3/4)^1/2]2+[(1+x)^1/2-(1-x)^1/2][2+1/2]bhai ye to 2 se bada aa rha hare the options correct?
I took the question from CGL thread. Even I was trying but couldn't
@pankaj1988
Shld be 1..
(1+x)/(1 + _/(1+x)) + (1-x)/(1 - _/(1-x))
=>(1+x)(1 - _/(1+x))/(1 - (1 +x)) + (1-x)(1 + _/(1-x))/(1 - (1-x))..[Rationalizing]
=> (1+x)(1 - _/(1+x))/(-x) + (1-x)(1 + _/(1-x))/(x)
=>1/x*[(1+x)(1 - _/(1+x)) + (1-x)(1 + _/(1-x))]
=>1/x*[(1-x) + (1-x)^(3/2) - (1+x) - (1+x)^(3/2)]
=>1/x*[(1-x)^(3/2) - (1+x)^(3/2) - 2x]
=>2/(_/3)[ 1- (_/3)/2]^(3/2) - (1 + (_/3)/2)^(3/2)] - 2
=>1/(_/6)[(2 - _/3)^(3/2)] - (2 + _/3)^(3/2)] - 2
=>1/(_/6)[{(0.268)^3}^(1/2) - {(3.732)^3}^(1/2)] - 2
=>1/_/6[ 7.348] - 2
=>2.9999 - 2
=>1[Approximately]
PS: Nt to exaggerate..bt from Step 7 i used a Calculator.. 
Pata nahi aur kaise hoga.. 
Pata nahi aur kaise hoga.. @vbhvgupta said:
Akshay got 62% marks in the selection test and scored 51% in the interview. He has an ITI diploma with 65% marks. His date of birth is 23rd September 1982. He has completed his course on CFM and has 3.5 years of work experience in company XYZ, which is one of the biggest mechanical companies of the country. He has also cleared the course of NCFM.1) 1 2) 2 3) 3 4) 4
ans 1?
there is no age issue. he is 29 years X months old which is perfectly fine.
there is no age issue. he is 29 years X months old which is perfectly fine.
Hi Puys.
I am stuck at this. Please help
How many integer values of x and y are such that 4x + 7y =3.
while |x|
I resolved till
x = -8, -15, -22 ....
y = 5,8,13,......
How to calculate the number of numbers !!????????????????
@ananyboss said:Hi Puys.I am stuck at this. Please helpHow many integer values of x and y are such that 4x + 7y =3.while |x|I resolved tillx = -8, -15, -22 ....y = 5,8,13,......How to calculate the number of numbers !!????????????????
And AP will be formed for x with Common Difference = - 7 and 7.
For y, AP will be formed with CD = 4 or - 4.
X will be the limiting factor, its CD being higher.
1. When x = + ive.
x = [ 6, 13, ... , 496 ] => 71 Terms.
2. When x = - ive.
x = [ -1, -8, ... -498 ] => 72 Terms.
So, Total = 71 + 72 = 143 terms.
@ananyboss said:Hi Puys.I am stuck at this. Please helpHow many integer values of x and y are such that 4x + 7y =3.while |x|I resolved tillx = -8, -15, -22 ....y = 5,8,13,......How to calculate the number of numbers !!????????????????
you should get
x=...-8,-1,6,13,20...
y=...-3,1,5,9....
so clearly the common difference of x is greater and there will be lesser total values possible for x. clearly the question states |x| -500>xfirst consider the negative half of the number line
x=-1,-8,-15,-22...
its an A.P with C.D=7 also we know that 70*7=490 so there wil be min 70 numbers. but 497 is also possible as well as 1(because the A.P starts from 7 in the case considered) so totally there are 72 terms
Now consider the positive half of the number line
x=6,13,20... here again you can see that the C.D is 7 also from the general A.P this A.P has each term-1 so like above you will get a min of 70 terms but in this A.P the 70th term wil be 489. so you can see there can be one more term so totally 71 terms
Hence a total of 143 terms. Is the answer right?
x=...-8,-1,6,13,20...
y=...-3,1,5,9....
so clearly the common difference of x is greater and there will be lesser total values possible for x. clearly the question states |x| -500>xfirst consider the negative half of the number line
x=-1,-8,-15,-22...
its an A.P with C.D=7 also we know that 70*7=490 so there wil be min 70 numbers. but 497 is also possible as well as 1(because the A.P starts from 7 in the case considered) so totally there are 72 terms
Now consider the positive half of the number line
x=6,13,20... here again you can see that the C.D is 7 also from the general A.P this A.P has each term-1 so like above you will get a min of 70 terms but in this A.P the 70th term wil be 489. so you can see there can be one more term so totally 71 terms
Hence a total of 143 terms. Is the answer right?
@iLoveTorres said:you should get x=...-8,-1,6,13,20...y=...-3,1,5,9....so clearly the common difference of x is greater and there will be lesser total values possible for x. clearly the question states |x| -500>xfirst consider the negative half of the number linex=-1,-8,-15,-22...its an A.P with C.D=7 also we know that 70*7=490 so there wil be min 70 numbers. but 497 is also possible as well as 1(because the A.P starts from 7 in the case considered) so totally there are 72 termsNow consider the positive half of the number linex=6,13,20... here again you can see that the C.D is 7 also from the general A.P this A.P has each term-1 so like above you will get a min of 70 terms but in this A.P the 70th term wil be 489. so you can see there can be one more term so totally 71 termsHence a total of 143 terms. Is the answer right?
Answer is 144. Your concept is right ! you might have missed one number somewhere! Thanks
@ananyboss said:Answer is 144. Your concept is right ! you might have missed one number somewhere! Thanks
Nope. 143 it should be. :|
@pankaj1988 said:If x= √3/2 then what is the value of (1+x)/(1+√(1+x))+(1-x)/(1-√(1-x))A)√3/2B)√3C)0D)1
you can substitute 1 in the equation as (3^1/2)/2 ~= 1.
you wil get
((1+1)/(1+(2)^1/2))+((1-1)/(1-(2)^1/2))
2/1+(2)^1/2
rationalizing
2*(1-(2)^1/2)/(1)^2-(2^1/2)^2
2-2(2^1/2)/-1
~= 2.828-2=.828 this is close to 1. hence answer should be D
you wil get
((1+1)/(1+(2)^1/2))+((1-1)/(1-(2)^1/2))
2/1+(2)^1/2
rationalizing
2*(1-(2)^1/2)/(1)^2-(2^1/2)^2
2-2(2^1/2)/-1
~= 2.828-2=.828 this is close to 1. hence answer should be D
In a no. system the product of 44 and 11 has been written as 1034.The no. 3111 of this system ,when converted to decimal no. system will become? (Ref:CAT-2001)
1.406
2.1086
3.213
4.691
@Pratiyush
Shld be 406..
(44)n= 4n + 4.. (11)n = n + 1... (1034)n = n^3 + 3n + 4
=>(4n + 4)(n + 1) = n^3 + 3n + 4
=>4n^2 + 4n + 4n + 4 = n^3 + 3n + 4
=>n^2 - 4n - 5= 0
=>(n + 1)(n - 5) = 0
=>n=5..Dismissing, n=-1..
Thus, (3111)n = 3*5^3 + 1*5^2 + 1*5 + 1= 406..
@pyashraj said:@PratiyushShld be 406..(44)n= 4n + 4.. (11)n = n + 1... (1034)n = n^3 + 3n + 4=>(4n + 4)(n + 1) = n^3 + 3n + 4=>4n^2 + 4n + 4n + 4 = n^3 + 3n + 4=>n^2 - 4n - 5= 0=>(n + 1)(n - 5) = 0=>n=5..Dismissing, n=-1..Thus, (3111)n = 3*5^3 + 1*5^2 + 1*5 + 1= 406..
(1034)n = n^3 + 3n + 4 this part is not clear....i dont think it is correct as you cannot write 1034 in this form