Official Quant thread for CAT 2013

@DeAdLy said:
from what i read the question is start of fifth round?? "in a knock out match of 128 participants find how many candidates wud still be in contention just before the beginning of 5th round ?"so seehope you all got it..abi ofc main full explain nai kar paunga...If u or anybody else who didnt get it...can pm me, i will explain tonight

bhai pm kar dena nahi aaya samajh me....
@DeAdLy said:
from what i read the question is start of fifth round?? "in a knock out match of 128 participants find how many candidates wud still be in contention just before the beginning of 5th round ?"so seehope you all got it..abi ofc main full explain nai kar paunga...If u or anybody else who didnt get it...can pm me, i will explain tonight
haan to isme ulta conside nai krenge....you are taking last round as first round...ans should be 8..
@shinoda said:
in a knock out match of 128 participants find how many candidates wud still be in contention just before the beginning of 5th round ?
i think it should not be 5th round cos logically 5th round is the QF. guess typo hoga should have been 3rd round
@Jackson1 said:
haan to isme ulta conside nai krenge....you are taking last round as first round...ans should be 8..
i have considered as i wanted....
i agree to diagree with you
U are free to consider whatever u like
@DeAdLy said:
i have considered as i wanted....i agree to diagree with you U are free to consider whatever u like
bhai Darth Lightsabers
@vbhvgupta said:
bhai
arey nai re.. let there be peace
@chandrakant.k said:
too complicated method.. hence ended up with wrong answer.. has to be 35EDITED
sir can u explain it in detail as i am weak in functions?
@Pratiyush said:
sir can u explain it in detail as i am weak in functions?
where was this??:lookaround: i myself have forgot 😞
@chandrakant.k A function f is defined as f(n) = 6^n + 8^n for all integers n. Find the remainder when f(83) is divided by 49.,can u xplain me in detail
@Pratiyush said:
@chandrakant.kA function f is defined as f(n) = 6^n + 8^n for all integers n. Find the remainder when f(83) is divided by 49.,can u xplain me in detail
6^83+8^83 mod 49
= (7-1)^83 + (7+1)^83 mod 49
= (83*7 -1 + 83*7+1) mod 49
= 2*(84-1)*7 mod 49
= -2*7 mod 49
= 35 mod 49
@Pratiyush said:
@chandrakant.k
A function f is defined as f(n) = 6^n + 8^n for all integers n. Find the remainder when f(83) is divided by 49.
,can u xplain me in detail
f(83) = 6^83 + 8^83
E(49) = 42 (E stands for euler)
6^84 mod 49 = 1
=>6*6^83 mod 49 = 1
6*X(say) mod 49 = 1
X = 41
similarly for 8^83
8*8^83 mod 49 = 1
8*y mod 49 = 1
y = 43
now x+y = 41+43 = 84
84 mod 49 = -14 = 35
@vijay_chandola is there any formula to directly find it
E(49) = 42
=> 6^84 = 1 MOD (49)
=> 6*6^83 = 1 MOD (49)
=> 6N - 1 = 0 MOD (49)
=> N = -8
Similarly 8^84 = 1 MOD (49)
=> 8M - 1 = 0 MOD (49)
=> M = -6
Therefore (N + M) MOD (49) = -8 -6 MOD (49) = -14 MOD (49) = 35
@Pratiyush said:
@chandrakant.kA function f is defined as f(n) = 6^n + 8^n for all integers n. Find the remainder when f(83) is divided by 49.,can u xplain me in detail
35
The calendar in the cell phone of Mr.Donny has malfunctioned and he does not like paper calendars in his office nor does he like to see the dates on any other electronic equipment. His assistant sees Mr. Donny stuck in the quandary. To help him, he glances across Mr. Donny €˜s table and finds two different coloured dice but none of its faces have any numbers. He writes one number each on all the faces of both the dice so that Mr. Donny can set the dice each morning such that the top faces of the dice show the current date.
What should be the numbers on each die to allow Mr.Donny to see any date?
(Note: Single digits cannot be represented by just 1 die. On all days both dice must be used. So 9th would be 09).
@DeAdLy said:
i have considered as i wanted....i agree to diagree with you U are free to consider whatever u like
there'll be total 7 rounds and 5th round from the last wud actually be the 3rd round from the beginning.
so how u came to that conclusion is really confusing

@ishu1991

1st Dice - 0,1,2,3,4,5

2nd Dice - 0,1,2,6,7,8

@leotheking said:
@ishu19911st Dice - 0,1,2,3,4,52nd Dice - 0,1,2,6,7,8
for 9
@shinoda said:
there'll be total 7 rounds and 5th round from the last wud actually be the 3rd round from the beginning.
so how u came to that conclusion is really confusing
Whats the answer in the book u have taken this question from??
@ishu1991 said:
for 9
Inverted 6 can be considered as 9