Official Quant thread for CAT 2013

@vbhvgupta said:
@Subhashdec2@Logrhythm@scrabbler@anytomdickandharylast 2 non zero digit of factorial of any number??
last non zero we got a formula but for last two non zero digit , no idea
@amresh_maverick said:
last non zero we got a formula but for last two non zero digit , no idea
bhai wo hi bata do....
@vbhvgupta said:
bhai wo hi bata do....
http://www.pagalguy.com/news/ive-got-power-working-with-factorials-cat-2011-quant-a-17445
here it is written as 2a that is 2^a not 2a
@vbhvgupta said:
bhai wo hi bata do....
Here is the method to find the last non zero

R(n!) = Last Digit of [ 2^a x R(a!) x R(b!) ]

where n = 5a + b

Example: What is the rightmost non-zero digit of 25! ?

? R (25!) = Last Digit of [ 2^5 x R (5!) x R (0!) ]

? R (25!) = Last Digit of [ 2 x 2 x 1 ] = 4




Try to get this by lengthy approach . calculate all the powers of prime factors and take the product . u need to consider only the last digit .


@vbhvgupta said:
Q1
GP wala sum..
a/1-r = 32.
a = Sum of all the terms following it. Hence, a = 32 - a.
So, first term is 16
@vbhvgupta said:
Q3
gupta ji what is the ans ? unable to solve , I am getting 11/15 which is not in the option

detail soln , plz
@amresh_maverick said:
gupta ji what is the ans ? unable to solve , I am getting 11/15 which is not in the optiondetail soln , plz
yar ans is 4/5.
yar jo bhi hai approach to post karo..phir dekhte hai

Q4

@vbhvgupta said:
Q3
@amresh_maverick said:
gupta ji what is the ans ? unable to solve , I am getting 11/15 which is not in the option

detail soln , plz

let vivek work 60 units ram work 90 and bhuvan 150

Their rate are in the ratio 1:2:3

Vivek takes 12 days which means he does 5units of work per day

So ram does 10 units and bhuvan does 15units per day

so in 8 days vivek does = 5*8 = 40

ram = 10*8 = 80

bhanu = 15*8 = 120

total work done = 240

total work to be done = 150+90+60 = 300

so amount of work done = 240/30 = 4/5

will be great if someone can share some good study material for Permutation & comboinations, probablity...as in some slots these topics have ample weightage...

@vbhvgupta said:
yar ans is 4/5.yar jo bhi hai approach to post karo..phir dekhte hai
sorry , galti se mistake ho gaya . err in taking efficiencies

Ratio of eff : 1 : 2: 3
so ratio of time : 6 :3:2 let us take it 6t , 3t and 2t

Vivek did 2/10th of work in 12 days

work done by vivek in 1 day = 1/6t

so work done in 12 days = 12/6t = 2/10

t= 10


days taken by three : 60 30 20

work done in 8 days = (1/60 + 1/30 + 1/20) *8= 4/5





@vbhvgupta said:
Q4

alok can complete work in 40 days

which means he will complete half work in 20 days

so left is 1/2

1/3rd of the pay is lost

which means 1/6th of the work is not done

so 1/2 - 1/6 = 2/6 = 1/3 amount of work is done by sachin in 20 days

so to complete full work he would require 60 days 😃

@amresh_maverick bade bade logon se choti choti galtiya hoti raheti hai 😉 😉
Nikhil goes to school everyday at 4 p:m to pick up his children. On a saturday the school got over at 3 p:m and the children started walking towards home.Nikhil met them on their way back and all of them returned home 20 min earlier than the usual tym.How long did the children walk?
40
45
50
55
@amresh_maverick said:
sorry , galti se mistake ho gaya . err in taking efficienciesRatio of eff : 1 : 2: 3so ratio of time : 6 :3:2 let us take it 6t , 3t and 2tVivek did 2/10th of work in 12 dayswork done by vivek in 1 day = 1/6tso work done in 12 days = 12/6t = 2/10t= 10days taken by three : 60 30 20work done in 8 days = (1/60 + 1/30 + 1/20) *8= 4/5
yar yekaise aaya
Vivek did 2/10th of work in 12 days???
@vbhvgupta said:
yar yekaise aayaVivek did 2/10th of work in 12 days???
given in the question naa , ratio of work divided = 2:3:5

so work done by vivek = 2/10 and this is done in 12 days
@vbhvgupta said:
@Subhashdec2@Logrhythm@scrabbler@anytomdickandharylast 2 non zero digit of factorial of any number??

http://totalgadha.com/mod/forum/discuss.php?d=8392


Follow the link for detailed solution.

ATDH.
@raopradeep said:
Nikhil goes to school everyday at 4 p:m to pick up his children. On a saturday the school got over at 3 p:m and the children started walking towards home.Nikhil met them on their way back and all of them returned home 20 min earlier than the usual tym.How long did the children walk?
40
45
50
55
saturday 3 ko choda?? :sneaky:mera schol tho 1 ko chodtha tha 😁 :D
solution :
total time saved = 50 mins
so he saves 10mins while going and 10 while coming
so students must have walked 50 mins???
@chandrakant.k said:
@amresh_maverick bade bade logon se choti choti galtiya hoti raheti hai
gud sense of humor 😃
@anytomdickandhary said:
we will have to make account to access that content?