@vbhvgupta said:Q4
12 days :
x(x-2)*3/4 = (x-10)(x+7)
x= 20
x(x-2) = (x+10)*a
a= 12 days..
@saurav205 said:at the request of@DeAdLy :A positive integer is written on each faces of a cube. At each corner (vertex) of the cube, the product of the numbers on the faces that meet at the corner is written. The sum of the numbers written at all the corners is 2431. Find the sum of the numbers written on all the faces of the cube?OA by midnight courtesy Test Funda sorry if this question has already been posted by someone else...
I guess it should be 41....
Let the numbers on the faces of the cube be denoted by a,b,c,d,e and f...
abe+bce+abf+bcf+aed+cde+afd+cfd = 2431
(a+c)(b+d)(e+f) = 11*13*17
so, (a+c)+(b+d)(e+f) = 11+13+17 = 41...
@vbhvgupta said:Q 5
no of man days required=990
let the no of days be n
44+43+42+.....+(44-n+1)=990
n/2(88-n+1)=990
n/2(89-n)=990
n(89-n)=1980
n=45
@Logrhythm said:I guess it should be 41....Let the numbers on the faces of the cube be denoted by a,b,c,d,e and f... abe+bce+abf+bcf+aed+cde+afd+cfd = 2431(a+c)(b+d)(e+f) = 11*13*17so, (a+c)+(b+d)(e+f) = 11+13+17 = 41...
yea...m getting the same....but OA by mid night ..when TF will post the answer...
plz help
if a:b=c:d,and e:f=g:h,then (ae+bf):(ae-bf)= ?ANS: (cg+dh)/(cg-dh)
plz help
if a:b=c:d,and e:f=g:h,then (ae+bf) : (ae-bf)= ?
if a:b=c:d,and e:f=g:h,then (ae+bf) : (ae-bf)= ?
ANS: (cg+dh)/(cg-dh)
@shirish1987 said:A and B together can do a piece of work in 80 days. B and C can do it in 120 days. All the three started their work together on the first day, but A bunked on every odd numbered day and C bunked on every even numbered day. How long did the work last?(A)88 days(B)90 days(C)96 days(D)98 days
Is it 96 days??
Let the total work be 240 units...
even days -> A+B work => 3 units of work is done..
odd days -> B+C work => 2 units of work is done..
so on 2 consecutive days 5 units is completed
240/5 = 48..
therefore, total days = 48*2 = 96...
@ani6 said:plz helpif a:b=c:d,and e:f=g:h,then (ae+bf) : (ae-bf)= ?ANS: (cg+dh)/(cg-dh)
a/b = c/d and e/f = g/h --> ae/bf = cg/dh
applying componendo and dividendo on both sides we get the desired proof...
@ani6 said:plz helpif a:b=c:d,and e:f=g:h,then (ae+bf)ae-bf)= ?ANS: (cg+dh)/(cg-dh)
u actually don't have do it with variables....i mean this is how i do it..
a/b = c/d
2/4 = 3/6
and e/f = g/h
1/3 = 2/6
so, (ae+bf)/(ae-bf) = 7/5...
now u hv the options...one of which would be (cg+dh)/(cg-dh) which after putting the values comes out to be 7/5 and hence is our answer...
@ani6 said:plz helpif a:b=c:d,and e:f=g:h,then (ae+bf) : (ae-bf)= ?ANS: (cg+dh)/(cg-dh)
u actually don't have do it with variables....i mean this is how i do it..
a/b = c/d
2/4 = 3/6
and e/f = g/h
1/3 = 2/6
so, (ae+bf)/(ae-bf) = 7/5...
now u hv the options...one of which would be (cg+dh)/(cg-dh) which after putting the values comes out to be 7/5 and hence is our answer...
a/b = c/d
2/4 = 3/6
and e/f = g/h
1/3 = 2/6
so, (ae+bf)/(ae-bf) = 7/5...
now u hv the options...one of which would be (cg+dh)/(cg-dh) which after putting the values comes out to be 7/5 and hence is our answer...
@shirish1987 said:A and B together can do a piece of work in 80 days. B and C can do it in 120 days. All the three started their work together on the first day, but A bunked on every odd numbered day and C bunked on every even numbered day. How long did the work last?(A)88 days(B)90 days(C)96 days(D)98 days
96 days ??
taking 2 days as a pair..
so 1st day b and c work
2nd day a and b work
so by the end of the 2nd day
1/80+1/120 = 1/48
so for every 2 days 1/48th of the work is done ,
to complete 100% of the work 48 pairs required , in total 48*2=96 days...
@ani6 said:plz helpif a:b=c:d,and e:f=g:h,then (ae+bf)ae-bf)= ?ANS: (cg+dh)/(cg-dh)
u actually don't have do it with variables....i mean this is how i do it..
a/b = c/d
2/4 = 3/6
and e/f = g/h
1/3 = 2/6
so, (ae+bf)/(ae-bf) = 7/5...
now u hv the options...one of which would be (cg+dh)/(cg-dh) which after putting the values comes out to be 7/5 and hence is our answer...
@iampg said:Among 4 people A,B,C and D, A takes thrice as much as B to complete a piece of work. B takes thrice as much time as C and C takes thrice as much time as D to complete the same work. One group of three of the 4 men can complete the work in 13 days while another group of three can do so in 31 days. Which is the group that takes 13 days?a) A,B,D b)B,C,D c)A,C,D d)A,B,C
a
677 has exactly 5 digits when converted into base 'n' from the decimal system. What is the minimum possible value of 'n'?
iPuys,plz solve this ques
:Q. Brass is an alloy of copper & zinc .Bronze is an alloy containing 80% of copper,4 % of zinc and 16% of tin.A fused mass of brass & bronze is found to contain 74% of copper ,16% of zinc,and 10% of tin.The ratio of copper to zinc in Brass is :a)64% & 36% b)33% & 67% c)50% & 75% d)35% & 65% e)none of these
@mbajamesbond said:677 has exactly 5 digits when converted into base 'n' from the decimal system. What is the minimum possible value of 'n'?
n= 4??
@Logrhythm said:Is it 96 days??Let the total work be 240 units...even days -> A+B work => 3 units of work is done..odd days -> B+C work => 2 units of work is done..so on 2 consecutive days 5 units is completed240/5 = 48..therefore, total days = 48*2 = 96...
yes 96 days is correct
