Official Quant thread for CAT 2013

MBA CAT 2024
17506
@raopradeep said:
there are four distinct numbers such that first and last ones are equal.the first three are in A.P and last three are on G.P. find the common ratio of last three1-11/2-2
the 4 numbers are -2 1 -2 4

so common ration is -2
17507
@joyjitpal said:
the 4 numbers are -2 1 -2 4so common ration is -2
That satisfies the conditions how? The first three are not in AP AND the 1st and 4th are not equal.

-2, -1/2, 1, -2 might work. Or any multiple thereof.

regards
scrabbler
17508
@raopradeep said:
there are four distinct numbers such that first and last ones are equal.the first three are in A.P and last three are on G.P. find the common ratio of last three1-11/2-2
a , a+d , a+2d , a

(a+2d)^2 = a*(a +d)
ratio = a : d = 4 : -3

series is :- 4 , 1 , -2 , 4

required answer = -2
17509

How many numbers between 1 to 1000 are not divisible by 2,3 or 5?

@jain4444 _/\_ after long time!!

17510
@pirateiim478 said:
How many numbers between 1 to 1000 are not divisible by 2,3 or 5?

@jain4444 _/\_ after long time!!
1000*1/2*2/3*4/5=1000*4/15=800/3=266
17511
@pirateiim478 said:
How many numbers between 1 to 1000 are not divisible by 2,3 or 5?@jain4444 _/\_ after long time!!
267 ????
17512
A sequence 192, 360, 576 €Ś €Ś. is formed by multiplying the corresponding terms of two different Arithmetic Progressions. What is the eighth term of the sequence?
17513
@Faruq said:
A sequence 192, 360, 576 €Ś €Ś. is formed by multiplying the corresponding terms of two different Arithmetic Progressions. What is the eighth term of the sequence?
a1a2=192
(a1+d1)(a2+d2)=360
d1a2+d2a1+d1d2=168

(a1+2d1)(a2+2d2)=576
a1a2+2(d1a2+a1d2+d1d2)+2d1d2=576
2d1d2=576-192-336=48
d1d2=24

(a1+7d1)(a2+7d2)
192+7*168+42*24=
192+1176+1008=2376??
17514
@pirateiim478 said:
How many numbers between 1 to 1000 are not divisible by 2,3 or 5?@jain4444 _/\_ after long time!!
266?
17515
@Faruq said:
A sequence 192, 360, 576 €Ś €Ś. is formed by multiplying the corresponding terms of two different Arithmetic Progressions. What is the eighth term of the sequence?
2376 only
17516
@pirateiim478 said:
How many numbers between 1 to 1000 are not divisible by 2,3 or 5?@jain4444 _/\_ after long time!!
990*1/2*2/3*4/5 equals to 264

264 plus 2 equals to 266
17517
@pirateiim478 said:
How many numbers between 1 to 1000 are not divisible by 2,3 or 5?@jain4444 _/\_ after long time!!
284?...
17518

what will be the area of triangle if the length of three medians of a triangle is 9cm,12cm and 15cm???

17519
@joyjitpal said:
990*1/2*2/3*4/5 equals to 264264 plus 2 equals to 266
@@pirateiim478 OA kya hai?
17520
@Faruq said:
A sequence 192, 360, 576 €Ś €Ś. is formed by multiplying the corresponding terms of two different Arithmetic Progressions. What is the eighth term of the sequence?
a1*a2 = 192
(a1 + d1)(a2 + d2) = 360
a1d2 + a2d1 + d1d2 = 168

(a1 + 2d1)(a2 + 2d2) = 576
d1d2 = 24

(a1 + 7d1)(a2 + 7d2)---->a1a2 + 7a1d2 + 7a2d1 + 49d1d2
192 + 7(168 + 6*24 ) = 2376 ?
17521
@joyjitpal said:
990*1/2*2/3*4/5 equals to 264

264 plus 2 equals to 266
please tell how did you arrived at 990*1/2*2/3*4/5 part...?
17522
@shuaa said:
what will be the area of triangle if the length of three medians of a triangle is 9cm,12cm and 15cm???
504root2 hoga kya?
@shuaa
17523
@saurabhlumarrai said:
please tell how did you arrived at 990*1/2*2/3*4/5 part...?
i took the lcm of 2 ,3 and 5 to a nearest number to 1000 as 990

990*1/2*2/3*4/5

this gives me the numbers below 990 which are not divisible by 2 ,3 or 5

then i added 2 for 991 and 997
17524
@pirateiim478 said:
How many numbers between 1 to 1000 are not divisible by 2,3 or 5?@jain4444 _/\_ after long time!!
ans 397?
17525
@shuaa said:
what will be the area of triangle if the length of three medians of a triangle is 9cm,12cm and 15cm???
answer 72 hai kya...???