Official Quant thread for CAT 2013

MBA CAT 2024
17466
@techgeek2050 said:
the work done by a man ,woman and a child are in the ratio 3:2:1. If daily wages for 20 men,30 women and 36 children amt to rs 78,what will b the wages of 15 men,21 women and 30 children for 18 weeks?
7371...
??

Convert all men and women into children...as in 20 men = 60 children
and 30 women = 60 children...
now daily wage for 1 child you'll get as 78/(60+60=36)
now for the final answer = 18*7*(15*3+21*2+30)*78/(156)
17467
@viewpt said:
329?
Yup 329 :)
17468
@saurav205 329 ...thoda sa farq hai ;)
17469
@TootaHuaDil said:
@saurav205 329 ...thoda sa farq hai
17470

pls pls pls when u post the answer post solution :banghead: :banghead: der is no point of unnecessary posts asking solution everytime.. the person puts the question here because either he wants a method or bcos he wants a better solution.. he knows the answer yar...

17471

@chandrakant.k
Question asked above,
no of ways of painting a decagon in blue?
17472
@VJ12 said:
@chandrakant.kQuestion asked above,no of ways of painting a decagon in blue?
i am too bad at cubes 😞 😞 please ask the people who have answered 😃
17473
@viewpt said:
Q: In how many ways one can paint a decagon with a blue color.??
2^10 - 1
17474
@chandrakant.k
Its not a cube. a normal decagon(polygon with 10sides). I think that was his question
@viewpt aap question deke chale gaye, sol bhi tho batao
17475
@VJ12 said:
@chandrakant.kIts not a cube. a normal decagon(polygon with 10sides). I think that was his question@viewptaap question deke chale gaye, sol bhi tho batao
i m sorry i also mean geometry 😞 😞 before CAT2k13 i will surely become better at tat 😃 till then give me some time 😃
17476
@Logrhythm said:
2^10 - 1
@VJ12 said:
@chandrakant.kIts not a cube. a normal decagon(polygon with 10sides). I think that was his question@viewptaap question deke chale gaye, sol bhi tho batao
a decagon has 10 sides...u hv 2 options for each side....either u can colour it or u dont hence 2^10 options....but minus for the case where you don't colour the decagon at all....hence 2^10 - 1

hope it is clear now... :)
17477
If 999abc= def132,
then what will be a+b+c+d+e+f ?

P.S : The answer is not 33
17478
@MANJULNEOGI said:
If 999abc= def132, then what will be a+b+c+d+e+f ?P.S : The answer is not 33
(1000-1)*abc = 132*def
1000abc = 132*def + abc
so a=8,b=6 and c=8
=> 868000 - 868 = def*132
=> def = 867...
so a+b+c+d+e+f = 8+6+8+8+6+7 = 43...
17479
In how many ways can the letters of the word PERMUTATIONS be arranged if there are always 4 letters between P and S?
17480
@veertamizhan

Shld be 10!*7

PERMUTATIONS: P, E, R, M, U, A, I, O, N ans S appear 1 times & T appears 2..

Case(i): P_ _ _ _S_ _ _ _ _ _ = 10!/2!*2
Case(ii):_ P_ _ _ _S_ _ _ _ _= 10!/2!*2
Case(iii): _ _P_ _ _ _S_ _ _ _= 10!/2!*2
Case(iv):_ _ _P_ _ _ _S_ _ _ = 10!/2!*2
Case(v):_ _ _ _P_ _ _ _S_ _ = 10!/2!*2
Case(vi):_ _ _ _ _P_ _ _ _S_ = 10!/2!*2
Case(vii):_ _ _ _ _ _P_ _ _ _S= 10!/2!*2
17481
Two series A (a1, a2, a3, ....an) and B (b1, b2, b3, ....bn) are in A.P. such that an- bn = n - 1, where an stands for the nth term of the series A, and bn for the nth term of the series B. It is also known that a6 = b8. Find the value of a101- b121.
17482
The answer is 50.....Can anyone explain?????
17483
@garry1337 said:
Two series A (a1, a2, a3, ....an) and B (b1, b2, b3, ....bn) are in A.P. such that an- bn = n - 1, where an stands for the nth term of the series A, and bn for the nth term of the series B. It is also known that a6 = b8. Find the value of a101- b121.
ans is 50??
17484

@garry1337 said:
The answer is 50.....Can anyone explain?????
yes,

let B series be.. b1=b,b2=b+d, b3=b+2d ... and so on

it is given a6=b8
also, an-bn=n-1

a6-b6=5
b8-b6=5
or b+7d- b-5d=5
d=5/2

now a101-b101=100
or a101= 100+b101

substitute this in what we have to find..
100+b101-b121
100+ b + 100*5/2 - b -120*5/2
350-300=50
17485
@pyashraj what is the *2 for? S---P?