Official Quant thread for CAT 2013

MBA CAT 2024
17306
@Logrhythm said:
bhai i dnt knw if this is a trick question but CBD hona chaiye...coz 10Pm of the same day nahi likha...10PM konse dinn ka...if same day ka hai toh aese nikaal lenge ki 1 hr mein 6 mins ka gap hai...
gud observation, but I think it will be for th same day 10PM
17307
@joyjitpal said:
nopes
answer b9:00P hain na???
17308
@junefever said:
answer b9:00P hain na???
yup
17309
@joyjitpal said:
3)Sangeeta and Swati bought two wristwatches from Jamshedpur Electronics at 11.40 A.M. IST.After purchasing they found that when 60 minutes elapses on a correct clock (IST), Sangeeta'swristwatch registers 62 minutes whereas Swati's wristwatch registers 56 minutes. Later in the daySangeeta's wristwatch reads 10 P.M., then the time on Swati's wristwatch is:a.8:40 PMb. 9:00 PMc. 9:20d. 9:40 PMe. Cannot be calculated.
b. 9.00 PM

Consider both clocks set at 11.40 AM IST. When Sangeeta's clock shows 10 PM, It means 620 min after 11.40 AM according to Sangeeta's clock. But 62 min of her clock equals 60 min in actual.
Hence 620 min in her watch = 600 min actual = 10 hr actual
Hence actual time is 9.40 PM
Swati's watch looses 4 min per actual hour
Hence her watch looses 40 min in 10 hrs
Hence at actual 9.40 PM her watch will show 9.00PM
17310
@Logrhythm

Va/Vb = 180/300-8Vb

isme 3:1 daal dia ... Vb 30 aya => Va = 90

ab back track se kya matlab hai ??

x= 300/Vb -8 hai
and x = 180/Va

dono me X = 2 aya

ab aur kha tak back track krna hai ...
17311
@joyjitpal said:
solution me tha ,isi liye


ye to fir galat baat hai
17312
@joyjitpal said:
3)Sangeeta and Swati bought two wristwatches from Jamshedpur Electronics at 11.40 A.M. IST.After purchasing they found that when 60 minutes elapses on a correct clock (IST), Sangeeta'swristwatch registers 62 minutes whereas Swati's wristwatch registers 56 minutes. Later in the daySangeeta's wristwatch reads 10 P.M., then the time on Swati's wristwatch is:a.8:40 PMb. 9:00 PMc. 9:20d. 9:40 PMe. Cannot be calculated.
9:00 pm?

62 mins ----> 60 mins
620 mins -----> 620*60/62 = 600 mins (IST)---->9:40 pm

60 mins ----> 56 mins
600 mins ----> 56*600/60 = 560 mins----->9:40 - 40 mins = 9:00 pm
17313
@mailtoankit said:
9:00 pm?62 mins ----> 60 mins620 mins -----> 620*60/62 = 600 mins (IST)---->9:40 pm60 mins ----> 56 mins600 mins ----> 56*600/60 = 560 mins----->9:40 - 40 mins = 9:00 pm
17314

a,b,c are positive real numbers and a^2+b^2+C^2=48
then find the maximum value of a+b+c???

17315
@bs0409 said:
a,b,c are positive real numbers and a^2+b^2+C^2=48then find the maximum value of a+b+c???
12
17316
@bs0409 said:
a,b,c are positive real numbers and a^2+b^2+C^2=48then find the maximum value of a+b+c???
12?
17317
@bs0409 said:
a,b,c are positive real numbers and a^2+b^2+C^2=48then find the maximum value of a+b+c???
12?
a = b = c
3a^2 = 48
a^2 = 16 ----> a = 4
a =b= c = 4
a + b + c = 12...
17318
There are 12 intermediate stations between two places A and B. In how many ways can a train
be made to stop at 4 of these 12 intermediate stations provided no two of them are
consecutive?
a. 45 b. 126 c. 84 d. 168
17319
@joyjitpal said:
12
@adwaitjw said:
12?
@mailtoankit said:
12?
a = b = c
3a^2 = 48
a^2 = 16 ----> a = 4
a =b= c = 4
a + b + c = 12...
OA=12............
Find the number of decimal numbers which are 3 digit numbers in base 7 but not 4 digit numbers in base 6??

17320
@bs0409 said:
OA=12............Find the number of decimal numbers which are 3 digit numbers in base 7 but not 4 digit numbers in base 6??
167 ?
17321
@joyjitpal said:
There are 12 intermediate stations between two places A and B. In how many ways can a trainbe made to stop at 4 of these 12 intermediate stations provided no two of them areconsecutive?a. 45 b. 126 c. 84 d. 168
A _ _ _ _ _ _ _ _ B

Ffix 8 station bw A & B.

Now we can select 4 station out of the remaining 9 positions.

So 9c4 = 126
17322
@bs0409 said:
OA=12............
Find the number of decimal numbers which are 3 digit numbers in base 7 but not 4 digit numbers in base 6??

three digit numbers in base 7 = [7^3, 7^4) = [343, 2401)
4 digit numbers in base 6 = [6^4, 6^5) = [1296, 7984)
==> required numbers = 343, 344......1295 = 953.
17323
@vijay_chandola said:
three digit numbers in base 7 = [7^3, 7^4) = [343, 2401)4 digit numbers in base 6 = [6^4, 6^5) = [1296, 7984)==> required numbers = 343, 344......1295 = 953.
Wont those be 4 digit n 5 digit no.s resp which u are mentioning?
17324
@vijay_chandola said:
three digit numbers in base 7 = [7^3, 7^4) = [343, 2401)4 digit numbers in base 6 = [6^4, 6^5) = [1296, 7984)==> required numbers = 343, 344......1295 = 953.
@adwaitjw said:
Wont those be 4 digit n 5 digit no.s resp which u are mentioning?
what is the formula
plz mention

i am confused
17325
@vijay_chandola said:
three digit numbers in base 7 = [7^3, 7^4) = [343, 2401)4 digit numbers in base 6 = [6^4, 6^5) = [1296, 7984)==> required numbers = 343, 344......1295 = 953.