Official Quant thread for CAT 2013

@joyjitpal said:
in this case you got to divide by 4!as there are 4 groups having 3 each
But they are equal
@bs0409 said:
An ant is standing on the upper left corner of a 8 8 chess board, of which the four squares from the centre are removed. If the ant can only walk along the edges of the squares, and can only move down, or to the right, in how many different ways can it reach the lower right corner of the checkerboard?
40 hoga kya?
@Anuj07 said:
OE ?
what is the answer bhai?
@audiq7 said:
60? tuka hai... p&c; kuchh nahi aata....
CMAT prep kaise chal rahi hai ?
@bs0409 said:
An ant is standing on the upper left corner of a 8 8 chess board, of which the four squares from the centre are removed. If the ant can only walk along the edges of the squares, and can only move down, or to the right, in how many different ways can it reach the lower right corner of the checkerboard?
2*(8!/6!2!)^2 + 2*8*8+2 = 1698
@jyotipal

a)40320
b)4024
c)53940
d)55554
e)none of these

answer hai !! N i dont know ki kaise aya hai

@jyotipal

a)40320
b)4024
c)53940
d)55554
e)none of these

answer hai !! N i dont know ki kaise aya hai

@joyjitpal said:
40 hoga kya?
@vijay_chandola said:
2*(8!/6!2!)^2 + 2*8*8+2 = 1698

ANS is 7970
@Anuj07 said:
7^13+1 /6 ? Remainder
7^13 + 1 mod 6 = 1^13 mod 6 + 1 mod 6 = 1 + 1 mod 6 = 2 ?
@Anuj07 said:
@jyotipala)40320b)4024c)53940d)55554e)none of these answer hai !! N i dont know ki kaise aya hai
ye kis question ka answer hai

plz mention the question
@joyjitpal said:
ravi ,i think actual no of days should be 365 + 21 + 30 + 15 = 431we need to take the month april
oh...yes forgot !!
@Anuj07 said:
7^13+1 /6 ? Remainder
7 /6 ==> rem =1 so its 1^13 +1 /6 = 2/6 => rem = 2
@ravi.theja said:
oh...yes forgot !!
then what? dividing 431 by 31 i am not getting the answer

your method?
@joyjitpal said:
ye kis question ka answer haiplz mention the question
INDIA Wala bhai !! Number of words from letter india
@bs0409 said:

ANS is 7970
7970? 😲 :O
Solution h kya?
:neutral:
1)A & B are two trains start simultaneously from X & Y stations towards Y & X respectively with
constant speed 60 km/hr and 40 km/hr respectively. When they just crossed each other, speed of B
got reduced to 3/4 th of its original speed,due to which B took 2 hours more than A to reach its destination.
What is the distance between X and Y stations?
a.200 km
b. 170 km
c. 150 km
d. 180 km

@ravi.theja @bs0409
2)A and B are standing in a tunnel such that distance from the closer exit is 3/8 of the total length
of the tunnel. They saw a train approaching the nearer end of the tunnel and they start moving
towards opposite ends with constant speed. Both just about managed to miss the train. If the speed of
the train is 60 kmph what is the ratio of speed of A and B (speed of A & B are integers)?
(a) 2:1
(b) 3:1
(c) 1:1
(d) 4:1
@joyjitpal said:
1)A & B are two trains start simultaneously from X & Y stations towards Y & X respectively withconstant speed 60 km/hr and 40 km/hr respectively. When they just crossed each other, speed of Bgot reduced to 3/4 th of its original speed,due to which B took 2 hours more than A to reach its destination.What is the distance between X and Y stations?a.200 kmb. 170 kmc. 150 kmd. 180 km
Va = (D-x)/t
Vb = x/t
(D-x)/60 = x/40
D = 5x/2
put 150...all conditions are satisfied...hence 150??
@joyjitpal said:
2)A and B are standing in a tunnel such that distance from the closer exit is 3/8 of the total lengthof the tunnel. They saw a train approaching the nearer end of the tunnel and they start movingtowards opposite ends with constant speed. Both just about managed to miss the train. If the speed ofthe train is 60 kmph what is the ratio of speed of A and B (speed of A & B are integers)?(a) 2:1(b) 3:1(c) 1:1(d) 4:1
is it 3:1??
@Logrhythm said:
is it 3:1??
this is not right


what is your approach?
@Logrhythm said:
Va = (D-x)/tVb = x/t(D-x)/60 = x/40D = 5x/2put 150...all conditions are satisfied...hence 150??
this is ok