@meenu05 said:Please solve it .
@naveenkrs said:x = 10, -10
@meenu05 said:@naveenkrs explanation please .
The number of straight line miles traveled downriver in one hour by Lucy's boat is approximated within a linear range by 3n + 4, where n represents her fuel consumption in units/hr. Suppose that traveling x miles requires k hours at a fuel rate of 7 units/hr, but that increasing her fuel consumption by 5 units/hr would allow her to travel 40% further in 1 fewer hour. How far would she travel in k hours at a fuel rate of 10 units/hr?
@saurav.kgp said:what is the ans of this question? Find the value of x^3 if x^2+x+1=0.
x = cube roots of unity 
so 1+w+w^2 = 0 (property of cube roots of unity)
so w^3 = 1
@bs0409 said:x^2+x+1=0 has imaginary roots only. No real roots....a,b,c,d,e-primea is min and e is maxa+b+c+d+e=350Find a
a = 2
rest are odd primes of the form 2k+1 so that b+c+d+e = 2m+4, a has to be even to make the sum 350 (even)
@pirateiim478
Shld be 272..
Given, St line Mile = 3n + 4 in 1 hour..
Now, x = k*(21 + 4), or, x = 25k...(i)
Again, 1.4x = (k-1)(12*3 + 4)
=>35k = 40k - 40 [From Eqn (i)]
=>k = 8..
Thus, Straight Miles = k*(30 + 4) = 8*34 = 272 Units..
@pirateiim478 said:The number of straight line miles traveled downriver in one hour by Lucy's boat is approximated within a linear range by 3n + 4, where n represents her fuel consumption in units/hr. Suppose that traveling x miles requires k hours at a fuel rate of 7 units/hr, but that increasing her fuel consumption by 5 units/hr would allow her to travel 40% further in 1 fewer hour. How far would she travel in k hours at a fuel rate of 10 units/hr?
272 miles
@jain4444 said:there are two containers A and B filled with oil with different prices and their volumes are 140litres and 60 litres resp. equal quantities are drawn from both A and Bin such a manner that the oil drawn from A is oured into B and the oil drawn from B is poured in A. the price per litre becomes equal in both A and B. how much oil is drawn from each A and B? 42 , 30 , 32 , CBD
An approach without equations, oral solution: The two oils must be in the same ratio in both cans at the end. But since no oil is wasted, this must be the same as the original ratio i.e. 140 : 60 or 7 : 3. Hence in the 60 litre vessel, 42 : 18 and in the 140 litre one, 98 : 42, which can be done by shifting 42 from the 140 to the 60 and vice versa.
Not sure if this will always work.
regards
scrabbler
Not sure if this will always work.
regards
scrabbler
@bs0409 said:No. of times a digit occurs in 'n' digit number in base b=b^(n-1)+(n-1)*(b-1)*b^(n-2)here b=2n=3,4,5,6So ans=8+20+48+112+1=189
how many whole numbers between 100 and 800 contain the digit 2 ??
In how many of the distinct permutations of the letters in MISSISSIPPI do the four I's not come together?
@swapnil4ever2u Ans 214
Total Numbers-> 7*10*10 =700
Numbers Which do not contain 2 =6*9*9=486
700-486 =214
EDITED @swapnil4ever2u
Total Numbers-> 7*10*10 =700
Numbers Which do not contain 2 =6*9*9=486
700-486 =214
EDITED @swapnil4ever2u
@veertamizhan said:In how many of the distinct permutations of the letters in MISSISSIPPI do the four I's not come together?
MISSISSIPPI
We have 1 M
4 I
4 S
2 P
Now total No. of Arrangement =11!/4!4!2!
cases where 4 I's Come together (take 4 I as one unit) 8!/4!2!
Ans 11!/4!4!2! - 8!/4!2!
We have 1 M
4 I
4 S
2 P
Now total No. of Arrangement =11!/4!4!2!
cases where 4 I's Come together (take 4 I as one unit) 8!/4!2!
Ans 11!/4!4!2! - 8!/4!2!
@Faruq said:@swapnil4ever2uAns 314 ??
sry yaar .. not in the options .. plz check .. although 214 is in the options ..
@swapnil4ever2u said:how many whole numbers between 100 and 800 contain the digit 2 ??
1ab -> 10+10 = 20
2ab -> 100
3ab -> 20
4ab -> 20
5ab -> 20
6ab -> 20
7ab -> 20
but we need to minus 6, as in ever xab case where x != 2 the x22 case is counted twice...
so, 20*6 + 100 - 6 = 214...
A certain pair of used shoes can be repaired for $12.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $28.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?
I don't have OA :(
so we needed to discuss
Please provide approach
@Logrhythm what am i doing wrong !! i am trying by that formula for 3 digit.. then subtracting the ones in 1-99, 801-899, 900-999.. (total 19*3) if u could try like that ..
@swapnil4ever2u said:@Logrhythm what am i doing wrong !! i am trying by that formula for 3 digit.. then subtracting the ones in 1-99, 801-899, 900-999.. (total 19*3) if u could try like that ..
edited 20*3
@gudda1122 said:A certain pair of used shoes can be repaired for $12.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $28.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?I don't have OA so we needed to discussPlease provide approach
avg cost per year of repaired shoe = 12.50
avg cost per year of a new shoe = 14
so, (14-12.5)/12.5 = 0.12 or 12% ??
@swapnil4ever2u said:@Logrhythm what am i doing wrong !! i am trying by that formula for 3 digit.. then subtracting the ones in 1-99, 801-899, 900-999.. (total 19*3) if u could try like that ..
bhai i am not a big fan of formulas but i guess you are referring to the formula BS bhai has given??
but bhai wo formula toh was for number of times a digit occurs in any base...
@Logrhythm said:avg cost per year of repaired shoe = 12.50avg cost per year of a new shoe = 14so, (14-12.5)/12.5 = 0.12 or 12% ??
but bhai we should also consider$ 28 while calculating Avg cost of repaired shoe
28+12.5=40.5/3=13.5
(.5*100)/13.5=3.70%
actually i am bit confused in this :(
@gudda1122 said:but bhai we should also consider$ 28 while calculating Avg cost of repaired shoe 28+12.5=40.5/3=13.5(.5*100)/13.5=3.70%actually i am bit confused in this
I guess you are right....karni padegi wo wali cost bhi consider... 
@Logrhythm are yaar.. shi bol rha h .. main v bas avai cross check kr rha tha .. pta nhi kahan dhyan tha.. 