Official Quant thread for CAT 2013

MBA CAT 2024
17126
A SUM IS DISTRIBUTED AMONG CERTAIN NUMBER OF PERSONS. SECOND PERSON GETS ONE RUPEE MORE THAN THE FIRST, THIRD PERSON GETS TWO RUPEE MORE THAN THE SECOND, FOURTH PERSON GETS THREE RUPEES MORE THAN THE THIRD AND SO ON. IF THE FIRST PERSON GETS ONE RUPEE AND THE LAST PERSON GETS 67 RUPEES. FIND THE NUMBER OF PERSON ?

a)12
b)10
c)14
d)18
17127
@bs0409 said:
A SUM IS DISTRIBUTED AMONG CERTAIN NUMBER OF PERSONS. SECOND PERSON GETS ONE RUPEE MORE THAN THE FIRST, THIRD PERSON GETS TWO RUPEE MORE THAN THE SECOND, FOURTH PERSON GETS THREE RUPEES MORE THAN THE THIRD AND SO ON. IF THE FIRST PERSON GETS ONE RUPEE AND THE LAST PERSON GETS 67 RUPEES. FIND THE NUMBER OF PERSON ?a)12b)10c)14d)18
a1 = a ; a2 = a+1 ; a3 = a+1+2 ; a4 = a+1+2+3 ...

an -1 = a + n(n+1)/2 given a =1 ==> n(n+1)/2 = 67-1 = 66 ==> n = 11 ., so no.of persons = 12
17128
@bs0409 said:
A SUM IS DISTRIBUTED AMONG CERTAIN NUMBER OF PERSONS. SECOND PERSON GETS ONE RUPEE MORE THAN THE FIRST, THIRD PERSON GETS TWO RUPEE MORE THAN THE SECOND, FOURTH PERSON GETS THREE RUPEES MORE THAN THE THIRD AND SO ON. IF THE FIRST PERSON GETS ONE RUPEE AND THE LAST PERSON GETS 67 RUPEES. FIND THE NUMBER OF PERSON ?a)12b)10c)14d)18
12?
a=1
a,a+1,a+3,a+6,a+10,a+15,a+21,a+28,a+36,a+45,a+55,a+66
17129
are questions of bayes theorem in probability being asked in cat ????
17130
@bs0409 said:
A SUM IS DISTRIBUTED AMONG CERTAIN NUMBER OF PERSONS. SECOND PERSON GETS ONE RUPEE MORE THAN THE FIRST, THIRD PERSON GETS TWO RUPEE MORE THAN THE SECOND, FOURTH PERSON GETS THREE RUPEES MORE THAN THE THIRD AND SO ON. IF THE FIRST PERSON GETS ONE RUPEE AND THE LAST PERSON GETS 67 RUPEES. FIND THE NUMBER OF PERSON ?a)12b)10c)14d)18
12
17131
@VISHAL.SHARMA20 said:
Tilak went to a book shop. He bought a book worth Rs 125. He had notes in the denominations of Rs 5, Rs 10 and Rs 50 only. In how many ways can he pay the bill?a) 25b) 22c) 23d) 24
24
17132

q1. A sealed cylindrical drum of radius r is 9% filled with paint. if the drum is tilted to rest on its side,the fraction fraction of its curved surface area(not counting the flat sides)that will be under the paint is

a) less than 1/12

b)greater than 1/4

c)between 1/6 and 1/4

d)between 1/12 and 1/6


q2. a ball is fitted into the mouth of an open cone whose base radius is equal to that of ball .how far could the ball definitely go inside the cone?????

a)half the ball

b)less than half the ball

c)more than half the ball

d)1/4 of the ball

17133

what will be the remainder 1!*1+2*2!+3*3!+4!*4+......19*19! divided by 64??????????
asked in elitmus paper on 20th jan 2013 😁 :P



17134
@getupsid said:
q1. A sealed cylindrical drum of radius r is 9% filled with paint. if the drum is tilted to rest on its side,the fraction fraction of its curved surface area(not counting the flat sides)that will be under the paint is a) less than 1/12b)greater than 1/4c)between 1/6 and 1/4d)between 1/12 and 1/6

a. less than 1/12

17135
@legion20 said:
what will be the remainder 1!*1+2!*2+3!*3+4!*4+......19*19! divided by 64??????????asked in elitmus paper on 20th jan 2013
its like dat :P
17136

@shattereddream said:
a. less than 1/12
any explanation !!!!!!!!
17137
@legion20 said:
its like dat
63 is the answer
17138
@legion20 said:
what will be the remainder 1!*1+2*2!+3*3!+4!*4+......19*19! divided by 64??????????asked in elitmus paper on 20th jan 2013
(n + 1)! - n!
2! - 1! + 3! - 2! +.................20! - 19! mod 64
20! - 1! mod 64
(-1) mod 64 = 63
17139
@legion20 said:
what will be the remainder 1!*1+2*2!+3*3!+4!*4+......19*19! divided by 64??????????asked in elitmus paper on 20th jan 2013
(2-1)* 1 ! + (3-1)*2! +.......(20-1)*19! = 2! -1! + 3! - 2! +......20! - 19! / 64 = 20! -1 /64 ..so rem is -1 +64 = 63
17140

hatts off to pg guys dam good yes it is the answer :)


17141
@legion20 said:
what will be the remainder 1!*1+2*2!+3*3!+4!*4+......19*19! divided by 64??????????asked in elitmus paper on 20th jan 2013
1*1! + 2*2! + 3*3! + ... n*n! = {n!(n+1)} - 1
so our number is -> (19!*20 - 1)%64
or (19!*20 - 1)%2^6
power of 2 in 19! is more than 6...hence it divides 19!*20
so remainder is -1 or 63...
17142
What is the minimum number of square marbles required to tile a floor of length 5 metres 78 cm and width 3 metres 74 cm?
176
187
54043
748
249
17143
a,b,c,d,e are prime numbers,not necessarily consecutive.
a
a+b+c+d+e=350
find a.
17144
@deepkarg said:
What is the minimum number of square marbles required to tile a floor of length 5 metres 78 cm and width 3 metres 74 cm?
176
187
54043
748
249

length=578cm
width=374cm
side of the required square marble=hcf(578,374)=34
No. of squares required=(578*374)/(34*34)=187
17145
@deepkarg said:
What is the minimum number of square marbles required to tile a floor of length 5 metres 78 cm and width 3 metres 74 cm?17618754043748249
HCF(578 , 374) = 34

no. sq. tiles = 578*374/34*34 = 187