@Calvin4ever said:According to the question, the first guy puts 1 ball, the second guy puts 2 balls and so on , rite ? In case if only 1 ball was put each time, then the number of factors wud be enough!!
Yes. U are right. Didn't notice it.......
A question paper consist of 15 'true' or 'false' questions.In how many ways can a candidate answer the entire paper?
@TootaHuaDil said:If S=[(104+324)*(224+324)*(344+324)*(464+324)*(584+324)]/[(44+324)*(164+324) *(284+324)*(404+324)*(524+324)].Find S....any shortcut for this??
S=[344*5+324*5]/[284*5+324*5]
=(344+324)/(284+324)
=668/608
=167/152
@TootaHuaDil said:6 people share a pizza by cutting it out into 6 equal sectors . If 3 of them cut out and eat only the largest possible circle from their respective slices and leave the rest while others eat the whole slice then what is the percentage of pizza wasted?(a)11(b)15(c)17(d)22
If the radius of pizza is taken as 3r, total are wud be 9 pi r^2. Now the circle in the segment wud have a radius of r. The amount left wud be 4.5pi r^2 - (3* pi r^2)= 1.5 pi r^2. Hence the ratio of the pizza left is 1.5 pi r^2 /9 pi r^2 = 1/6 = 16.66% = 17 ??
@bs0409 said:A question paper consist of 15 'true' or 'false' questions.In how many ways can a candidate answer the entire paper?
If he can leave out any questions, it wud be 3 ^ 15 . If he attempts all the questions, it wud be 2^ 15 ??
@bs0409 said:ABCD a Convex quadrilateral . 3,4,5 and 6 points are marked on the sides AB,BC,CD,DA respectively . The No. of triangle with vertices on different side is..??
triangles with at most 1 vertex on each side of the quadrilateral = 342
triangles with 2 vertices on a side of the quadrilateral = 439
total = 781
@bs0409 said:A question paper consist of 15 'true' or 'false' questions.In how many ways can a candidate answer the entire paper?
really?
@TootaHuaDil said:6 people share a pizza by cutting it out into 6 equal sectors . If 3 of them cut out and eat only the largest possible circle from their respective slices and leave the rest while others eat the whole slice then what is the percentage of pizza wasted?(a)11(b)15(c)17(d)22
the radius of the largest circle is 1/3 times the size of pizza
@TootaHuaDil said:There are 100 players from 1 to 100 and 100 baskets from 1 to 100.1st player puts 1 ball in every basket starting from the first baskt , second puts 2 in each an so on but starting from the second basket ( in baskets 2 , 4 , 6 ..) Third player puts 3 in baskets in 3 , 6 , 9 .. .... Process continues till 100th player puts 100 balls in 100th basket ..Which basket wil have max no of balls(a)96 (b)98(c)100(d)none f thesePlease explain the approach too..
96 is composed entirely of 2's and 3's, so it gives it an advantage of maximum no. of factors to fulfill the necessary condition of having maximum sum of factors
A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:
one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry 1/2 -ve marks. Unattempted carry no marks.What is the diff between max & min he can score???
one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry 1/2 -ve marks. Unattempted carry no marks.What is the diff between max & min he can score???
@Calvin4ever said:No, it shud be the one which has the maximum sum of factors and not the number of factors . Answer wud be 96 but still . . .@bs0409
@Calvin4ever said:According to the question, the first guy puts 1 ball, the second guy puts 2 balls and so on , rite ? In case if only 1 ball was put each time, then the number of factors wud be enough!!
bhai , what exactly is the difference if we take no of factors or sum of the factors ???
@DreamBikerzz said:A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:
one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry 1/2 -ve marks. Unattempted carry no marks.What is the diff between max & min he can score???
Diefference: 140
@DreamBikerzz said:A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry 1/2 -ve marks. Unattempted carry no marks.What is the diff between max & min he can score???
(i) 1/10 * 100 = 10 ( -1/10 marks each)
(ii) 1/5 * 100 = 20 ( -1/5 marks each)
(iii) rem = 70 ( -1/2 each)
max marks - min marks = 100 (all correct ) - ( 10 *0.1 + 20 * 0.2 + 70 * 0.5 ) {all wrong}
= 100 - 40
= 60.
@CSK23 said:(i) 1/10 * 100 = 10 ( -1/10 marks each)(ii) 1/5 * 100 = 20 ( -1/5 marks each)(iii) rem = 70 ( -1/2 each)max marks - min marks = 100 (all correct ) - ( 10 *0.1 + 20 * 0.2 + 70 * 0.5 ) {all wrong}= 100 - 40= 60.
Bro, Minimum marks would be -40 (negative 40).
So, Difference is 100 - (-40) = 140
@TootaHuaDil said:There are 100 players from 1 to 100 and 100 baskets from 1 to 100.
1st player puts 1 ball in every basket starting from the first baskt , second puts 2 in each an so on but starting from the second basket ( in baskets 2 , 4 , 6 ..)
Third player puts 3 in baskets in 3 , 6 , 9 .. ....
Process continues till 100th player puts 100 balls in 100th basket ..
Which basket wil have max no of balls
(a)96
(b)98
(c)100
(d)none f these
Please explain the approach too..
.The answer would be 96.
@naveenkrs said:L.C.M: l.c.m of 2 and 3 is 6. Since 2 and 3 are recurring numbers in given numbers.so we have to take lcm of two numbers.lcm is 6.so in lcm 6 will repeat. We have to find how many times "6" will appear. now find l.c.m of powers of given numbers(so as to find the no. of times 6 will appear)l.c.m of 20 and 70 is 140.so the answer is (l.c.m) is 6666.....140 times.
bhai this is true for only even number of times, like
LCM ( 222, 33 ) = 2442 (2's 3 times repeated)
LCM ( 2222, 33 ) = 6666 (2's 4 times repeated)
LCM ( 22, 333) = 7326 (3's 3 times repeated)
LCM ( 22, 3333) = 6666 ( 3's 4 times repeated)
@CSK23 said:bhai , what exactly is the difference if we take no of factors or sum of the factors ???
Bhai, We can solve this by sum of factors formula.
i.e. N= [{a^(p-1)-1}/(a-1)] [{b^(q-1)-1}/(b-1)] [{c^(r-1)-1}/(c-1)]
Or, logically, we can compare 90,96 and 100 = max of sum of factors is of 96.
@doctoriim said:Bhai, We can solve this by sum of factors formula.i.e. N= [{a^(p-1)-1}/(a-1)] [{b^(q-1)-1}/(b-1)] [{c^(r-1)-1}/(c-1)] Or, logically, we can compare 90,96 and 100 = max of sum of factors is of 96.
yes.thanks bhai, but why not number of factors??? i didnt get that.
@CSK23 said:yes.thanks bhai, but why not number of factors??? i didnt get that.
Because, all the people put balls equal to their number means
player 1 puts 1 ball in each basket
player 2 puts 2 balls in the baskets
player 3 puts 3 balls
and so on...
@doctoriim said:Because, all the people put balls equal to their number means player 1 puts 1 ball in each basketplayer 2 puts 2 balls in the basketsplayer 3 puts 3 ballsand so on...
1st basket = 1 ball
2nd = 1 + 2 = 2 balls
3rd = 1 + 2 + 3 = 6 balls
4th = 1 + 2 + 4 = 7 balls
.....
okk got it
the one which has max no of factors has the max number of balls.
so 96 = 12 factors. (max)
@DreamBikerzz said:A candidate takes a test n attempts all 100 ques. While any correct ques fetches 1 marks, Wrong attempts have penalty as follows:one tenth of ques carry 1/10 -ve marks,1/5th carry 1/5 -ve marks & rest carry 1/2 -ve marks. Unattempted carry no marks.What is the diff between max & min he can score???
x + y/10 (-1/10) + y/5 (-1/2) + 7y/10 (-1/2) = x- 2y/5
Max wen x= 100 and min wen y = 100 ==> max = 100 ; min = -40.
Diff = 140
Max wen x= 100 and min wen y = 100 ==> max = 100 ; min = -40.
Diff = 140
@bs0409 said:A question paper consist of 15 'true' or 'false' questions.In how many ways can a candidate answer the entire paper?
2^15 if the question has to attempted complsry else 3^15?? its like every question can be answered in 3 ways.. T or F or leaving it :)