Official Quant thread for CAT 2013

logrhythm · January 26, 2013, 4:04pm

@Chayan_88 said:
@Logrhythm the answer is bcould you please mention the appraoch that you used for solving this one. I assume that you used AB=AC.......But my question is how does one figure out for sure that the two equal sides are AB and AC and not BC ,AC and or AB,BC?

in an isos trngl...any 2 sides are equal....

bhai meine toh options se kar dia...distance formula laga kar..

chayan_88 · January 26, 2013, 4:04pm

@Logrhythm one more way of filtering out option a. would be that the coordinates of B,C and option a. are collinear.

csk23 · January 26, 2013, 4:20pm

Q : If x and y are integers such that 5x + 3y = 84 then which of the following is not a possible value of y?

1. -222

2. 2333

3. 76321

4. 23

pratskool · January 26, 2013, 4:26pm

@CSK23 for x = 3, y = 13... all other values of y differ by 5 and its multiples... hence option 3 is not a possible value

pavimai · January 26, 2013, 4:27pm

two circles of equal radii are drawn ,without any overlap in a semi circle of diameter 6cm ,what is the radius(in cm ) of the largest possible circles that the semi circle can accommodate in such manner..

1.0.414

2.0.828

3.0.172

4.0.586

dragster · January 26, 2013, 4:29pm

@CSK23 said:
Q : If x and y are integers such that 5x + 3y = 84 then which of the following is not a possible value of y?1. -2222. 23333. 763214. 23

x | y
0 28
3 23
so we can check for -222 , 2333 , 76321
-222-28/-5 must be an integer , n similary check for 2333-28/5 , 76321-28/5;
ans.. 3

pradeep_rss · January 26, 2013, 4:31pm

A person sells 2 articles one at 10 % loss and other at 15 % profit .sum of their sp is 30000 difference in their cp is ?

dragster · January 26, 2013, 4:33pm

@pavimai said:
two circles of equal radii are drawn ,without any overlap in a semi circle of diameter 6cm ,what is the radius(in cm ) of the largest possible circles that the semi circle can accommodate in such manner..1.0.4142.0.8283.0.1724.0.586

2..?

pavimai · January 26, 2013, 4:35pm

@dragster said:
2..?

correct...can u explain..i dint get solution

dragster · January 26, 2013, 4:52pm

exact method is different that i don remember..
wat i can tell u is dat, in such a case diameter of smallest >= radius/2( of semi circle)
r/2= 1.5 , now since diameter>=1.5 ;
u can reject all options and select 2nd

dragster · January 26, 2013, 4:53pm

@Pradeep_Rss said:
A person sells 2 articles one at 10 % loss and other at 15 % profit .sum of their sp is 30000 difference in their cp is ?

options..?

pradeep_rss · January 26, 2013, 4:55pm

5000 ,6000 ,7500,none

logrhythm · January 26, 2013, 4:56pm

@Pradeep_Rss said:
A person sells 2 articles one at 10 % loss and other at 15 % profit .sum of their sp is 30000 difference in their cp is ?

(cp1-sp1)/cp1 = 0.1
sp1 = 0.9cp1
(sp2-cp2)/cp2 = 0.15
sp2 = 1.15cp2
sp1+sp2 = 30000
0.9cp1+1.15cp2 = 30000

CBD bhi hai kya options mein...

dragster · January 26, 2013, 5:00pm

@Logrhythm said:
(cp1-sp1)/cp1 = 0.1sp1 = 0.9cp1(sp2-cp2)/cp2 = 0.15sp2 = 1.15cp2sp1+sp2 = 300000.9cp1+1.15cp2 = 30000CBD bhi hai kya options mein...

haan bhai ax+by=z given hai.. how to find +-(x-y)

blowcat13 · January 26, 2013, 5:12pm

A jar full of milk contains 40% of water. a part of this milk is replaced by another containing 19%water and now the percentage of water is found to be 26%. The quantity of milk replaced is??
A)1/3 B)2/3 C)2/5 D)3/5

weak at alligations explain in detail plzzz

sagarcat · January 26, 2013, 5:17pm

@Pradeep_Rss is it 6000 ?

pradeep_rss · January 26, 2013, 5:18pm

@dragster @Logrhythm

i think the ques is incomplete.......it must be like the loss due to 1 st obj = gain due to second obj then cp1/cp2= 3/2 then we can solve the eq => cp1=18000 cp2 = 12000 then diff = 6000

dragster · January 26, 2013, 5:21pm

@blowcat13 said:
A jar full of milk contains 40% of water. a part of this milk is replaced by another containing 19%water and now the percentage of water is found to be 26%. The quantity of milk replaced is??A)1/3 B)2/3 C)2/5 D)3/5weak at alligations explain in detail plzzz

check for water..
19% , 40% resulting in 26..
ratio= 14: 7 >> 2:1 , so double of 2nd , 1 part of 1st ;
so only 33% of 1st is used , which is 1/3rd ; milk in 1st= 60% so keep 1/3rd u replaced 2/3rd..
thats 40% so answr is 2/5 w.r.t overall solution.

rahulmittal2211 · January 26, 2013, 5:22pm

There are seven children standing in line, not all of whom have the same number of cakes with them. if the forst child distributes his cakes to the remaining six children such that he doubles their respective no of cakes, then he will be left with 4 cakes. instead, if the second child takes two cakes from each of the remaining six children, then he will be left with three cakes less than the number of cakes that the first child initially had. what is the total no of cakes that are there with the third child to seventh child?

A. 11 B. 14 C. 12 D. 15

someone plz explain the solution for this...

blowcat13 · January 26, 2013, 5:28pm

@dragster OA is 2/3 bhai..