in triangle ABC , D and E are points on AB nd AC respectively, such that DE is parallel to BC . BE and CD intersect at M . if Area(ADE) / Area(MDE) = 7/3 , then find BC/DE ??
Options -
a) 3/2
b)5/2
c) 7/4
d)4/3
@swapnil4ever2u said:in triangle ABC , D and E are points on AB nd AC respectively, such that DE is parallel to BC . BE and CD intersect at M . if Area(ADE) / Area(MDE) = 7/3 , then find BC/DE ??Options -a) 3/2b)5/2c) 7/4d)4/3
Is it 5/2???
Has to be done by assuming the altitudes of the three triangles
Solve the eq.
(x^4)-2(x^3)+4(x^2)+6x-21=0,if two of its roots are equal in magnitude and opposite in sign.
(x^4)-2(x^3)+4(x^2)+6x-21=0,if two of its roots are equal in magnitude and opposite in sign.
QUESTION : THERE ARE 10 STUDENTS STANDING IN A LINE , NOT ALL OF WHOM HAVE THE SAME NUMBER OF CHOCOLATES WITH THEM . IF THEIR 1ST CHILD DISTRIBUTES HIS CHOCOLATES TO 9 CHILDREN SUCH THAT HE DOUBLES THEIR RESPECTIVE NUMBER OF CHOCOLATES THEN HE WILL BE LEFT WITH 1 CHOCOLATE . IF THE 10TH CHILD TAKES AWAY ONE CHOCOLATE FROM EACH OF THE REMAINING NINE THEN HE WILL HE WILL BE HAVING 4 CHOCOLATES LESS THAN THE FIRST CHILD INITIALLY HAD . WHAT IS THE TOTAL NUMBER OF CHOCOLATES THAT ARE THERE WITH THE CHILD TO THE 9TH CHILD ?
question : a test has 90 questions . Each correct answer is awarded 1 mrk each wrong answer is awarded -1/2 and an unattempted question is awareded -1/4 mark . a candidate scored 5 marks in the test . the number of wrongly answered question by him cannot be more than ?
In an exhibition, some paintings were kept for sale. On the first day, 1 painting plus 1/7 th of the remaining paintings were sold. On the second day, 2 paintings plus 1/7 th of the remaining paintings were sold. A similar pattern continued till the kth day, when 'k' paintings were sold and no painting was left after that. If the exhibition ran for exactly k days (k > 1), then what is the minimum number of paintings sold during the exhibition?
@meenu05 said:question : a test has 90 questions . Each correct answer is awarded 1 mrk each wrong answer is awarded -1/2 and an unattempted question is awareded -1/4 mark . a candidate scored 5 marks in the test . the number of wrongly answered question by him cannot be more than ?
Is it 55?????????
@ravi.theja said:a-a+b+c = 2 ===> b+c = 2 ;a* -a * b * c = -21 ==> a^2 *b *c = 1*3*7 since b+c = 2 then b= -1 c= 3 a = root7 , d= -root7 .so the roots are root 7 , -root 7 , -1 , 3
roots are +sqrt(3),-sqrt(3), 1+isqrt(6), 1-isqrt(6)
@meenu05 said:QUESTION : THERE ARE 10 STUDENTS STANDING IN A LINE , NOT ALL OF WHOM HAVE THE SAME NUMBER OF CHOCOLATES WITH THEM . IF THEIR 1ST CHILD DISTRIBUTES HIS CHOCOLATES TO 9 CHILDREN SUCH THAT HE DOUBLES THEIR RESPECTIVE NUMBER OF CHOCOLATES THEN HE WILL BE LEFT WITH 1 CHOCOLATE . IF THE 10TH CHILD TAKES AWAY ONE CHOCOLATE FROM EACH OF THE REMAINING NINE THEN HE WILL HE WILL BE HAVING 4 CHOCOLATES LESS THAN THE FIRST CHILD INITIALLY HAD . WHAT IS THE TOTAL NUMBER OF CHOCOLATES THAT ARE THERE WITH THE CHILD TO THE 9TH CHILD ?
12?
@meenu05 said:question : a test has 90 questions . Each correct answer is awarded 1 mrk each wrong answer is awarded -1/2 and an unattempted question is awareded -1/4 mark . a candidate scored 5 marks in the test . the number of wrongly answered question by him cannot be more than ?
55?
x + y + z = 90
x - y/2 - z/4 = 5 -----> x = 5 + y/2 + z/4...putting this value in first eqn
5 + y/2 + z/4 + y + z =90
6y = 350 - 5z
y = 350 - 5z/6
for y to be max z will be min
for z = 4
y = 350 - 5(4)/6 = 55@hatemonger