@krum said:have u considered 8,27 ?
my bad...over confidence kills u... :(
but sirji...2^3 hoga...2 digit count karne hai...4^3 hoga though...
thanks :)
@Logrhythm said:my bad...over confidence kills u... but sirji...2^3 hoga...2 digit count karne hai...4^3 hoga though...thanks
sry not 8, just 27
4^3 = 2^6 nai hoga na
srry sab loag...2^6 count kar lia.. 😞
OA. 4= 2+2 or 4*1
for 2+2 cases 2*3 to 2*47 total 13 cases
3*5 to 3*31 total 9 cases
5*7 to 5*19 total 5 case
7*9 to 7*11 total 2 cases
for 4*1 we have only 3*3
so total count will be 30..:)
Find sum of digit of the least number n, such that 2n is square and 3n is a cube.
a, 9
b. 10
c. 11
d. 12
@DespicableA said:Find sum of digit of the least number n, such that 2n is square and 3n is a cube.a, 9b. 10c. 11d. 12
9....the number will be 72.
Suppose the number is 2^m * 3^n.
1st condition - 2^(m+1)*3^n is a square Basically, we need to have m as odd, and n as even.
Also 2^m*3^(n+1) is a cube. So m and (n+1) should be divisible by 3.
The smallest m and n satisfying both are 3 and 2, hence we want 2^3 * 3^2 = 72.
Check: 72 * 2 =144 = 12^2 and 72 * 3 = 216 = 6^3.
regards
scrabbler
@DespicableA said:Find sum of digit of the least number n, such that 2n is square and 3n is a cube.a, 9b. 10c. 11d. 12
A. 9 & no. is 72
@DespicableA said:Find sum of digit of the least number n, such that 2n is square and 3n is a cube.a, 9b. 10c. 11d. 12
N = 72
sum = 9 ?
@DespicableA said:Find sum of digit of the least number n, such that 2n is square and 3n is a cube.a, 9b. 10c. 11d. 12
9 for me too
how many zeroes will be there at the end of 1003*1001*999*....123?
@ishu1991 said:how many zeroes will be there at the end of 1003*1001*999*....123?
i think answer is zero because series odd ki hai
