Official Quant thread for CAT 2013

@Estallar12 said:
Nope.See, Suppose there are m Men and n Women.Now, Given 66 number can be written in a equation like this :2*mC2 = No. of Games between Men.2*mC1*nC1 = No. of Games between Men and Women.Difference = 66. Equate it. Then on factorising 33 = 11*3, we can see that m cannot be 3 else, the term in bracket will go negative. So, m = 11 and n = 2.
Got it ...................... Dimaag bund ho gaya hai mera

@Estallar12 my bad, didnt use the funda of factorising

Then on factorising 33 = 11*3, we can see that m cannot be 3 else, the term in bracket will go negative. So, m = 11 and n = 2.{missed this part}

Two friends A and B purchased an article and both of them paid for it. First A paid 50% of the money then B paid 50% of the remaining. Again A paid 50% of the remaining, then B, and this process continues until the article is fully paid for? What percentage of the total cost of the article is paid by A?
At the end of 1998, a man bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p > 0 and q > 0. If he had nine dozen goats at the end of 2002, after making the sales for that year, what is relation between p and q .is p>q ,p


help me with the approach.......thanks in advance
@Pradeep_Rss Percentage of total cost paid by A =66.67% ????
@Pradeep_Rss said:
Two friends A and B purchased an article and both of them paid for it. First A paid 50% of the money then B paid 50% of the remaining. Again A paid 50% of the remaining, then B, and this process continues until the article is fully paid for? What percentage of the total cost of the article is paid by A?
66.65%
@Pradeep_Rss said:
Two friends A and B purchased an article and both of them paid for it. First A paid 50% of the money then B paid 50% of the remaining. Again A paid 50% of the remaining, then B, and this process continues until the article is fully paid for? What percentage of the total cost of the article is paid by A?
x/2 + x/4 + x/8............. paid by A is x/2 + x/8 +.......... infinite gp series = x/2 /( 1-1/4) = 2x/3 = 66.66 %
@Pradeep_Rss said:
Two friends A and B purchased an article and both of them paid for it. First A paid 50% of the money then B paid 50% of the remaining. Again A paid 50% of the remaining, then B, and this process continues until the article is fully paid for? What percentage of the total cost of the article is paid by A?
66.66% ??
@Pradeep_Rss said:
At the end of 1998, a man bought nine dozen goats. Henceforth, every year he added p% of the goats at the beginning of the year and sold q% of the goats at the end of the year where p > 0 and q > 0. If he had nine dozen goats at the end of 2002, after making the sales for that year, what is relation between p and q .is p>q ,phelp me with the approach.......thanks in advance
say u hav 100 goats add 10% => becomes 110 now to get 100 u have to sell 110-100/110 = 1/11 = 9.9 % here p=10 and q=9.9 so.......P > Q

if the roots of the eqn cx^2 - bx +4 =0 . are in the ratio c:4 and c not equal to b-4 then c=?

a)4-b
b)-b-4
c)b+4
d)b-4
@raopradeep said:
if the roots of the eqn cx^2 - bx +4 =0 . are in the ratio c:4 and c not equal to b-4 then c=?a)4-bb)-b-4c)b+4d)b-4
-b-4


let a*c and 4*c be the two roots ===> a*c + 4*a = b/c

a*c*4*a = 4/c ==> a^2*c^2= 1 ==> ac= +- 1
a*(c+4) = b/c on substituting ac=1 we get c=b-4 on substituting ac= -1 we get c=-b-4
@Pradeep_Rss said:
Two friends A and B purchased an article and both of them paid for it. First A paid 50% of the money then B paid 50% of the remaining. Again A paid 50% of the remaining, then B, and this process continues until the article is fully paid for? What percentage of the total cost of the article is paid by A?
66.67 %?
@ravi.theja -b-4
@raopradeep said:
if the roots of the eqn cx^2 - bx +4 =0 . are in the ratio c:4 and c not equal to b-4 then c=?a)4-bb)-b-4c)b+4d)b-4
It will be -b-4.
If ratio of equation are in ration m:n for equation ax^2+bx+c then mn*b^2 =(m+n)^2*ac
So for cx^2-bx+4=0 it is 4c*b^2=(4+c)^2*4c
b=4+c or b=-4-c
given c not equal 4+c so b=-4-c
@raopradeep said:
if the roots of the eqn cx^2 - bx +4 =0 . are in the ratio c:4 and c not equal to b-4 then c=?a)4-bb)-b-4c)b+4d)b-4
option B ???
@vishwadeep2010 yes OA b
a right circular cylinder has to be made out from a metal sheet such that sum of its height and radius does not exceed 9 and it has max volume possible..?
@raopradeep said:
if the roots of the eqn cx^2 - bx +4 =0 . are in the ratio c:4 and c not equal to b-4 then c=?a)4-bb)-b-4c)b+4d)b-4
-b-4?
cx+4x=b/c
cx*4x=4/c---->x=-1/c
-c/c-4/c=b/c
c=-b-4

find maximum value of 6x - x^2 +7 if |x-4|>=2

a)14
b)15
c)16
d)17
@Pradeep_Rss said:
Two friends A and B purchased an article and both of them paid for it. First A paid 50% of the money then B paid 50% of the remaining. Again A paid 50% of the remaining, then B, and this process continues until the article is fully paid for? What percentage of the total cost of the article is paid by A?
66.66%