@praveen2010p said:@sails Q1: 36 ??Q2: 10 ?
dude i didnt ask the question..why u giving me the answer???..:P
@The_Loser said:Out of 100 person surveyed, 78 like Apples and 62 like Bananas.5. At least how many like apples only?6. At most how many like apples only?7. At least how many like exactly one fruit?8. At most how many like exactly two fruits?9. At least how many like at least one fruit?10. At most how many do not like any of the two fruits?
5) 16
6)38
7)16
8)62
9)78
10)22
@sirari said:@The_Loser5. At least how many like apples only?78-62=166. At most how many like apples only?387. At least how many like exactly one fruit?168. At most how many like exactly two fruits?629. At least how many like at least one fruit?8410. At most how many do not like any of the two fruits?22
consider d case when all the no of people liking banana and apple both is 62 , only banana is 0 and only apple is 16 ... then number of people liking atleast one fruit is 16 + 62 = 78
also when atmost 22 like none ==> this implies that atleast liking one is 78 .. :)
@Veknash
@Logrhythm @catahead : not necessary .. example - 4 is a factor of 48 , 24 is also a factor of 48 .. but 4*24 is not a factor of 48
@Veknash said:If 'a' is a factor of x and 'b' is also a factor of x, then is (a*b) also a factor of x? Why/ Why not?Thanks in advance for answers
@bhatkushal said:"I am seven times as old as you were when I was as old as you are". said a man to his son.Find the present age in years of man and son respectively if sum of their ages is 110.Guys please explain the eqns being created here....Having trouble to comprehend the meaning of the statement......
father son
past y x
present 7x y
7x + y = 110
and 7x - y = y-x
on solving fathers present age(7x) = 70 and
sons present age = 40
@vbhvgupta said:If the ratio of Harmonic mean to the gm of 2 nos is 12:13, find the ratio of the no.4/9 or 9/4 2/3 or 3/22/5 or 5/2 3/4 or 4/33/4 or 4/5
9/4 or 4/9
@Veknash said:If 'a' is a factor of x and 'b' is also a factor of x, then is (a*b) also a factor of x? Why/ Why not?Thanks in advance for answers
let us say x be 20 ...then factors of 20 are 1,2,4,5,10 ,
5*10=50 and similarly 2*4 is not a factor of 20...hence a*b is not necessarily factor of x
but if the question would have been a and b are prime factors of x then a*b would have been factor of x necessarily
@The_Loser said:Out of 100 person surveyed, 78 like Apples and 62 like Bananas.5. At least how many like apples only?6. At most how many like apples only?7. At least how many like exactly one fruit?8. At most how many like exactly two fruits?9. At least how many like at least one fruit?10. At most how many do not like any of the two fruits?
5. 16
6. 38
7. 16
8.62
9. 78
10. 22
@vbhvgupta said:Find the sum of all possible whole no divisors of 720??concept??
720 = 2^4 * 3^2 * 5^1 ==> sum = (2^5 -1 )/ (2-1) * ( 3^3-1)/ (3-1) * ( 5^2-1)/(5-1) = 2418
@swapnil4ever2u said:plz calculate it for 19 jan 1964 .. dnt know why i am getting it wrong ..
1600 - 0
300 - 1
63 - 15*2+48 = 78 ->1
19 - 5
5+1+1+0
sunday
how many perfect squares less than 10^6 are multiples of 24?
@The_Loser said:A = {1, 2, 3, 4, 5}, B Š† A and C Š† B. How many pairs of (B, C) are possible?
how to solve this question??? not getting it...
please help
@catahead said:U need to erase all multiples of 2,3,5 (4 is not needed as when u eliminate multiples of 2 , multiples of 4 are also elimintaed)Now, during this process , u eliminated the multiples of 6,10,15 more than once.So you need to calculate them and add. and lastly, you again added the multiples of 30 more than once.This is little iterati ve, but can be done with little patience
Ok lets say i calculated multiples of 2,3,5 and remove them.
Now i remove Multiples of 6, 15 and 10.
i dont want to go mechanical here, thats y going in the concepts..
1) N = 204*221*238*255*......*280. how many consecutive zeroes will be there at the end of this number N??
a. 8
b. 10
c. 11
d. 12
2) Find the HCF of ((2^100)-1) and ((2^120)-1).
a. (2^10)-1
b. (2^20)-1
c. 1
d. none of these
@sos2god said:how to solve this question??? not getting it...please help
It will be 3^5. Element can belong to either A or B or C.
@getupsid said:1) N = 204*221*238*255*......*280. how many consecutive zeroes will be there at the end of this number N?? a. 8b. 10c. 11d. 122) Find the HCF of ((2^100)-1) and ((2^120)-1).a. (2^10)-1b. (2^20)-1c. 1d. none of these
1) question is not clear..the first few terms follow a pattern of having difference as 17..but 280 cannot be der.
2) 2^HCF(100,120) -1 = 2^20-1
2) 2^HCF(100,120) -1 = 2^20-1
@getupsid said:1) N = 204*221*238*255*......*280. how many consecutive zeroes will be there at the end of this number N?? a. 8b. 10c. 11d. 122) Find the HCF of ((2^100)-1) and ((2^120)-1).a. (2^10)-1b. (2^20)-1c. 1d. none of these
1)N=204*221*238*255*...*850...
How many zeroes will be there at the end of this number.?
sol :- take 17 as common .. 17 ^ 38 * [ 12 * 13 *........50 ] = 17 ^ 38 * 50!/11! ...50! will hav 12 zeros and 11! will hav 2 zeros..so...total 12-2 = 10.
p.s :- for any value series with equal difference can do this way
How many zeroes will be there at the end of this number.?
sol :- take 17 as common .. 17 ^ 38 * [ 12 * 13 *........50 ] = 17 ^ 38 * 50!/11! ...50! will hav 12 zeros and 11! will hav 2 zeros..so...total 12-2 = 10.
p.s :- for any value series with equal difference can do this way