@vbhvgupta said:Q2
I am gettiing d= -3/4 , 5/4 and r=1/2, 3/2
And sum = 2.5 and 22.5
Whats the OA?
And sum = 2.5 and 22.5
Whats the OA?
@catahead said:I am gettiing d= -3/4 , 5/4 and r=1/2, 3/2And sum = 2.5 and 22.5Whats the OA?
OA is B
@Logrhythm said:if X = a*b*c*d...then ofcrs a*b also divides X...
Is it a necessary condition that all the factors of a number x can be written in a*b*c....... format?
@vbhvgupta said:OA B
a1=a2=2
a1+2d=a2*r^2
a1+d=a2*r+.25
so...1+d=r^2...i
2+d=2r+.25...ii
solving i and ii
r=1/2 or 3/2
1+d=1/4
d=-3/4
1+d=9/4
d=5/4
sum=5/2(2*2+4*(-3/4))=2.5
sum1=5/2(2*2+4*(5/4))=22.5
how 27.5 ??
@mailtoankit said:a1=a2=2a1+2d=a2*r^2a1+d=a2*r+.25so...1+d=r^2...i2+d=2r+.25...iisolving i and iir=1/2 or 3/21+d=1/4d=-3/41+d=9/4d=5/4sum=5/2(2*2+4*(-3/4))=2.5sum1=5/2(2*2+4*(5/4))=22.5how 27.5 ??
ans given is B
If the ratio of Harmonic mean to the gm of 2 nos is 12:13, find the ratio of the no.
4/9 or 9/4 2/3 or 3/2
2/5 or 5/2 3/4 or 4/3
3/4 or 4/5
@vbhvgupta said:If the ratio of Harmonic mean to the gm of 2 nos is 12:13, find the ratio of the no.4/9 or 9/4 2/3 or 3/22/5 or 5/2 3/4 or 4/33/4 or 4/5
We have [ 2ab / (a+b) ] / root(ab) = 12/13
=> 13root(ab) = 6(a+b)
=> 13root(a/b) = 6(a/b+1)
say root(a/b)=x
So 13x = 6(x^2+1)
Solve and get x=2/3 or 3/2
So a/b = x^2 = 4/9 or 9/4
=> 13root(ab) = 6(a+b)
=> 13root(a/b) = 6(a/b+1)
say root(a/b)=x
So 13x = 6(x^2+1)
Solve and get x=2/3 or 3/2
So a/b = x^2 = 4/9 or 9/4
@catahead said:We have [ 2ab / (a+b) ] / root(ab) = 12/13=> 13root(ab) = 6(a+b)=> 13root(a/b) = 6(a/b+1)say root(a/b)=xSo 13x = 6(x^2+1)Solve and get x=2/3 or 3/2So a/b = x^2 = 4/9 or 9/4
yar OA given is E 3/4 or 4/5
@vbhvgupta 1st and 2nd: for a number to be a perfect square , the digital sum should be 1, 4, 7 or 9 only