Official Quant thread for CAT 2013

@techgeek2050 said:
can sm1 plz solve dis 1. d question is in d file attached.
assuming there s no loss of volume in the breakin up process....

the exponential part of the ratio ll remain same=1/3
...so ratio after n operatoions ll be=

[no of parts]^1/3...each operation breaks the parts in to n+1 parts...

so....[(n+1)!]^1/3......!!!!!
@vbhvgupta said:
Q40 andQ4115 36 20 42
@ravi.theja can u solve Q41
@ravi.theja said:
no buddy..u are wrong..dey are only in A.P not in G.Pcheck 2b=a+c fro A.p and b^2 = a*c for g.p..the terms above jus satisfy condition for a.p but not g.p
why dont they satisfy for GP? i am sorry i am not getting it.....222 4=2x2 9=3x3...dont think it cant be counted as ap and gp
@sos2god said:
cant be ap for sure...as then d would be 0...
it is in ap..d=0
@sos2god said:
why dont they satisfy for GP? i am sorry i am not getting it.....222 4=2x2 9=3x3...dont think it cant be counted as ap and gp
sry bhai 😃 i ddnt see d question actually..i jus rplyd to his qstn..understood the r=terms as 111,222,333 and said the three terms cant be in g.p...

@vbhvgupta ll do it nw
@ravi.theja
hw u did that qstn
a+b+c+d=90
@vbhvgupta said:
it is in ap..d=0
bhai..is it 36??

@vishcat said:
guys pleASE help me out with this question-two vessels contain spirit and water mixed respectively in the ratio 1:3 and 3:5. Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2?
6:18 =spirit and water ratio
9:15 =spirit and water ratio

8:16=spirit and water ratio

6 9
8
1 2

1:2
@ishu1991 said:
@ravi.thejahw u did that qstn a+b+c+d=90
totall ways = (n+r-1)C ( r-1) here n=90 and r= 4.

i.e., 93c3..but here there is a limitation that evry elemnt can hav max of 45..

==> a' + 45 + b +c+d = 90 ==> no.of ways 47c2..similarly maximising b,c,d ..
@ravi.theja
thnks i was not getting the max vala case
@ravi.theja said:
bhai..is it 36??
ans 42
@vbhvgupta said:
it is in ap..d=0
wat is the OA ?? am getng 36 :)
@vbhvgupta said:
An ap P consist of n terms. From the progressions P1, P2 ans P3 are created such that P1 is obtained by 1st, 4th , 7th terms of P,P2 is obtained by 2, 5th , 8th terms of P and P3 is obtained by 3rd, 6th , 9th terms of P. It is found that of p1, p2 and p3two progression have the property that their average is itself a term of the original progression P. which of the following can be the value of n?20 26 36 both 20 & 26
20 and 26
A = {1, 2, 3, 4, 5}, B ⊆ A and C ⊆ B. How many pairs of (B, C) are possible?
@gnehagarg said:
20 and 26
explain kar do.
@The_Loser
3^5
@ishu1991 said:
@The_Loser3^5
Out of 100 person surveyed, 78 like Apples and 62 like Bananas.
5. At least how many like apples only?
6. At most how many like apples only?
7. At least how many like exactly one fruit?
8. At most how many like exactly two fruits?
9. At least how many like at least one fruit?
10. At most how many do not like any of the two fruits?
@vbhvgupta said:
An ap P consist of n terms. From the progressions P1, P2 ans P3 are created such that P1 is obtained by 1st, 4th , 7th terms of P, P2 is obtained by 2, 5th , 8th terms of P and P3 is obtained by 3rd, 6th , 9th terms of P. It is found that of p1, p2 and p3two progression have the property that their average is itself a term of the original progression P. which of the following can be the value of n?
20 26 36 both 20 & 26
20 and 26..........
@sirari said:
20 and 26..........
explain...