@vbhvgupta said:Q2
10
@sos2god said:@The_Loser 2+4+8+16+32....256 .. till 8 digit... for 9 digit less and than 2x10^8 ... 256 766..?
is this correct ans...766.. if wrong please explain
An ap P consist of n terms. From the progressions P1, P2 ans P3 are created such that P1 is obtained by 1st, 4th , 7th terms of P, P2 is obtained by 2, 5th , 8th terms of P and P3 is obtained by 3rd, 6th , 9th terms of P. It is found that of p1, p2 and p3two progression have the property that their average is itself a term of the original progression P. which of the following can be the value of n?
20 26 36 both 20 & 26
Q40 and
Q41
15 36 20 42
@sos2god said:@The_Loser number of ways 6!5*5*5*5*5*5how ever we will have to remove the cases with first digit as 0so 5!*5*5*5*5*5so ans 6!5*5*5*5*5*5 - 5!5*5*5*5*5what am i doin wrong here??
5^6 - in dis u have already arranged the numbers. wt we have to do is selection of places.
Like for 1st case - 6C3 * 5^6. Here out of 6 select three places for even d rest 3 places for odd. and than arrange numbers 5*5*5*5*5*5.
Similerly subtract numbers having zero at 1st place. Chose 2 out f 5 places for odd that is 5C2 and dan arrange rest in 5^5 ways
Total ways = 6c3 * 5^6 - 5c2 * 5^5 = 281250
Like for 1st case - 6C3 * 5^6. Here out of 6 select three places for even d rest 3 places for odd. and than arrange numbers 5*5*5*5*5*5.
Similerly subtract numbers having zero at 1st place. Chose 2 out f 5 places for odd that is 5C2 and dan arrange rest in 5^5 ways
Total ways = 6c3 * 5^6 - 5c2 * 5^5 = 281250
can sm1 plz solve dis 1. d question is in d file attached.
@sos2god said:@The_Loser 2+4+8+16+32....256 .. till 8 digit... for 9 digit less and than 2x10^8 ... 256766..?
Last two digits of 78^2009?
@techgeek2050 said:can sm1 plz solve dis 1. d question is in d file attached.
(n+1)!^1/3 : 1..??
edited
edited
@TootaHuaDil said:Last two digits of 78^2009?
divide your power wid 20.
u will find 78^9 --> 08 last two digits.
ya Tootahua dil.. acha ID name hai
u will find 78^9 --> 08 last two digits.
ya Tootahua dil.. acha ID name hai