Official Quant thread for CAT 2013

MBA CAT 2024
14543
@veertamizhan said:
"To a solution having milk and water in the ration of 2:3, 15 lts of water is added and then 15 lts of the solution is drawn out. This operation is done a total of three times. If the ration of milk and water is not 25:231, find the volume of the original solution"is there an easier way to solve this question rather, than taking 2x/5 and 3x/5 as the original quantities?

Final concentration = initial concentration ( 1- voulme replaced / initial volume )^n


25 / ( 231 + 25 ) = ( 2 / ( 2 + 3 ) ) ( 1 - 15 / x )^3

x = 40
14544
@sunnychopra89 said:
Number of positive integer valued pairs(x,y) satisfying 4x - 17y = 1 and x
59
14545
@sunnychopra89 said:
Of 128 boxes of Oranges, each box contains at least 120 and at most 144 oranges. The number of boxes containing the same number of oranges is at least ?
5?

144 - 120 + 1 = 25
25 * 4 = 100
100 + 20 = 120
14546
@grkkrg said:
5?

144 - 120 + 1 = 25
25 * 4 = 100
100 + 20 = 120
OA is 6
14547
Uncle distributed 27 candies among his four nephews. The four kids started fighting over the candies and went to their grandpa. Grandpa heard the following:
“I got one less than him”.
“I got two less than him”.
“I got three less than him”.
“I got four less than him”.
“I got five less than him”.
“I got six less than him”.



How many candies did each kid get?
14548
@sunnychopra89
5
14549
@ishu1991 said:
Approach?....OA is 6....confused
14550
@ishu1991 said:
Uncle distributed 27 candies among his four nephews. The four kids started fighting over the candies and went to their grandpa. Grandpa heard the following:“I got one less than him”.“I got two less than him”. “I got three less than him”. “I got four less than him”. “I got five less than him”. “I got six less than him”. How many candies did each kid get?
a,a+1,a+4,a+6
total = 4a + 11 = 27
a = 4

So 4,5,8,10
14551
@grkkrg said:
a,a+1,a+4,a+6total = 4a + 11 = 27a = 4So 4,5,8,10
bhai koi trick lagai ya hit n trial?
14552
@sunnychopra89 said:
OA is 6
Made a mistake
25 * 5 = 125
then there are 3 more
125 + 3 = 128
So 5 + 1 = 6
14553
@TootaHuaDil said:
bhai koi trick lagai ya hit n trial?
hit and trial :D
14554
The radius of a circle with center o is root 50 cm. A and C are two points on the circle ,and B is a point inside the circle . The length of AB is 6 cm, and the length of BC is 2 cm . The angle ABC is a right angle . find the square of the distance OB
14555
@grkkrg said:
hit and trial
I can see..Math is inside you ...Original flow 😃
14556
@grkkrg said:
Made a mistake
25 * 5 = 125
then there are 3 more
125 + 3 = 128
So 5 + 1 = 6
Dude I din understand.....Can u plz explain it?
14557
@techgeek2050 said:
The radius of a circle with center o is root 50 cm. A and C are two points on the circle ,and B is a point inside the circle . The length of AB is 6 cm, and the length of BC is 2 cm . The angle ABC is a right angle . find the square of the distance OB
14/3?
14558
What is the remainder when 98^5 + 99^5 + 101^5 + 102^5 is divided by 400?
(1)0 (2) 100 (3) 200 (4) 300 (5) none of these
14559
@x2maverickc nope. this question was in xat 2013 so i dunno the answer. the options given are 1.) 26 2.)25 3.)24 4.)23 5.) 22.
14560
@TootaHuaDil
0
14561
@ishu1991 said:
@TootaHuaDil0
no try carefully....
14562
@TootaHuaDil
(100-2)5 + (100-1)5+(100+1)5 + (100+2)5
98^5 + 102^5 = 2(100^5 + 5C2 100^3 (2)^2 +5C4 100 (2)^4)
99^5 + 101^5 = 2((100^5 + 5C2 100^3 (1)^2 +5C4 100 (1)^4)
so the sum would be:
4 100^5 + 10^7(2^3+2) + 1000 (2^4+1)
finally the prob condenses to
rem(17000 /400) == 200