Official Quant thread for CAT 2013

MBA CAT 2024
14363
@The_Loser said:
examination fr 1st 3 papers = max marks 504th exm - max marks 100find no f ways one can score 60% ?
178651 ways??
14364
@shattereddream said:
Find the sum of the remainders obtained when a number n is divided by 9 and 7 given that n is the smallest number that leaves remainders of 4,6,9 when divided by 13,11 and 151. 4 2. 5 3. 9 4. 6
4. 6

13a + 4 = 11b + 6 = 15c + 9
a = (11b + 2)/13
b = 1,14,27,40,...______(1)
a = 1,12,23,34,...

b = (15c + 3)/11
c = 2,13,24,35,...
b = 3,18,33,48,...______(2)

From (1) and (2)
1 + 13p - 13 = 3 + 15q - 15
13p = 15q
p = 15, q = 13
b = 183
11b + 6 = 2019
Remainders = 3 + 3 = 6
14365
@IIM-A2013 said:
Alphonso, on his deathbed, keeps half his property forhis wife and divides the rest equally among his threesons Ben, Carl and Dave. Some years later Ben diesleaving half his property to his widow and half to hisbrothers Carl and Dave together, shared equally. WhenCarl makes his will he keeps half his property for hiswidow and the rest he bequeaths to his younger brotherDave. When Dave dies some years later, he keeps halfhis property for his widow and the remaining for hismother. The mother now has Rs 1,575,000.74. What was the worth of the total property?a. Rs. 30 lakhb. Rs. 8 lakhc. Rs. 18 lakhd. Rs. 24 lakh75. What was Carls original share?a. Rs. 4 lakhb. Rs. 12 lakhc. Rs. 6 lakhd. Rs. 5 lakh76. What was the ratio of the property owned bythe widows of the three sons, in the end?a. 7 : 9 : 13b. 8 : 10 : 15c. 5 : 7 : 9d. 9 : 12 : 13
74. d
75. a
76. b

W = P/2
B = C = D = P/6
BW = P/12
C = D = P/6 + P/24 = 5P/24
CW = 5P/48
D = 5P/24 + 5P/48 = 5P/16
DW = 5P/32
W = P/2 + 5P/32 = 21P/32 = 1575000

P = 2400000
C = 400000
BW : CW : DW = P/12 : 5P/48 : 5P/32 = 8P/96 : 10P/96 : 15P/96 = 8 : 10 : 15
14366

Guys please post the solution...

14367
There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?(1)28 (2) 25 (3)22 (4)16 (5) 15
14368
http://snag.gy/NwyHo.jpg
HOW THIS PROBLEM WILL BE SOLVED ??

14369
@raopradeep said:
There are a certain number of consecutive natural numbers written on a black board.If one of them is erased, the average of the remaining numbers is 32 (7/24).which of the following could be the number erased?(1)28 (2) 25 (3)22 (4)16 (5) 15
(2) 25

32 7/24 = 775/24
The number of consecutive number is 24k (+ 1)
25/2 ( 2a + 25 - 1) > 775
25 ( 2a + 24) > 1550
(2a + 24) > 62
2a > 38
a > 19
a = 20
25/2 ( 40 + 24) = 800
800 - 775 = 25

14370
@bhatkushal said:
Guys please post the solution...
8400m?

A's speed = 2x
C's speed = 5x (C overtakes A in his 2nd and 4th lap)
Total distance travelled = 7x = 7 * 1200 = 8400m
14371
@dreamz007 said:
http://snag.gy/NwyHo.jpgHOW THIS PROBLEM WILL BE SOLVED ??
7?

As long as the lines are not parallel to either axes, they pass through both of them.
AC, BE and DE are parallel to x axis or y axis.
So 5C2 - 3 = 10 - 3 = 7
14372
@grkkrg answer is 7
14373
@grkkrg said:
7?As long as the lines are not parallel to either axes, they pass through both of them.AC, BE and DE are parallel to x axis or y axis.So 5C2 - 3 = 10 - 3 = 7
@dreamz007
14374
@dreamz007
AB,AE,AD,BC,BD,CE,CD
7 LINES .
14375
[X] denotes the greatest integer less than or equal to X, then [1/3] +[ 1/3+1/99 ]+ [1/3+2/99] + ‹Ż+ [1/3+98/99] =

(A) 33 (B) 34 (C) 32 (D) 67 (E) 66ďťż
14376
@Tiws said:
[X] denotes the greatest integer less than or equal to X, then [1/3] +[ 1/3+1/99 ]+ [1/3+2/99] + ‹Ż+ [1/3+98/99] =(A) 33 (B) 34 (C) 32 (D) 67 (E) 66
(A) 33
14377
@Tiws said:
[X] denotes the greatest integer less than or equal to X, then [1/3] +[ 1/3+1/99 ]+ [1/3+2/99] + ‹Ż+ [1/3+98/99] =(A) 33 (B) 34 (C) 32 (D) 67 (E) 66
(A) 33?

0 + [34/99] + [35/99] + .... + [99/99] + ... + [131/99]
= 131 - 98 = 33
14378
Rajiv is a student in a business school. After every test he calculates his cumulative average. QT and OB were his last two tests. 83 marks in QT increased his average by 2. 75 marks in OB further increased his average by 1. Reasoning is the next test, if he gets 51 in Reasoning, his average will be _____?

(A) 63 (B) 62 (C) 61 (D) 60 (E) 59
14379

hi guys plz tell me the best cat coaching in noida???

14380
@Tiws said:
[X] denotes the greatest integer less than or equal to X, then [1/3] +[ 1/3+1/99 ]+ [1/3+2/99] + ‹Ż+ [1/3+98/99] =

(A) 33 (B) 34 (C) 32 (D) 67 (E) 66ďťż
33.?
from [1/3 + 66/99] to [1/3 + 98/99]
14381
@Tiws said:
Rajiv is a student in a business school. After every test he calculates his cumulative average. QT and OB were his last two tests. 83 marks in QT increased his average by 2. 75 marks in OB further increased his average by 1. Reasoning is the next test, if he gets 51 in Reasoning, his average will be _____?(A) 63 (B) 62 (C) 61 (D) 60 (E) 59
(A) 63

nA + 83 = (n+1)(A+2)
nA + 83 = nA + 2n + A + 2
2n + A = 81

nA + 158 = (n+2)(A + 3)
nA + 158 = nA + 3n + 2A + 6
3n + 2A = 152
4n + 2A = 162
n = 10
A = 61
(610 + 158 + 51)/13 = 819/13 = 63
14382
In a cricket match, Team A scored 232 runs without losing a wicket. The score consisted of byes, wides and runs scored by two opening batsmen: Ram and Shyam. The runs scored by the two batsmen are 26 times wides. There are 8 more byes than wides. If the ratio of the runs scored by Ram and Shyam is 6:7, then the runs scored by Ram is

(A) 88 (B) 96 (C) 102 (D) 112 (E) None of the above