@TootaHuaDil said:detailed solution please
sorry..i used trial and error method....sometimes it works.....is my answer correct?
@TootaHuaDil said:Find the remainder when n^7-n is divided by 42
0??
42 = 7*6
let n = 2
(2^7 - 2)%7 = 0
(2^7 - 2)%6 = 0
hence, 0
@gupanki2 said:Ashok went on a tour. He visited a total of 8 cities. In each city he spent र2 less than half the amount he had with him. He spent र100 in the last city he visited. Find the amount he had initially (in र).
let the amount initially with him be x
then in 1st city he used: 1/2(x)-2.....a)
now he had x-[1/2(x)-2].......b)
in 2nd city , he used :1/2(b))-2
P.S:when we reach 8th city the equation would be equal to 100,and we vl find 'x'
then in 1st city he used: 1/2(x)-2.....a)
now he had x-[1/2(x)-2].......b)
in 2nd city , he used :1/2(b))-2
P.S:when we reach 8th city the equation would be equal to 100,and we vl find 'x'
q1) what is the maximum value of HCF of [n^2+17] and [(n+1)^2+17].
a)69
b)85
c)170
d)none of these
q2) how many integers N in the set of integers {1,2,3,......100} are there such that N^2+N^3 is a perfect square.
a)5
b)7
c)9
d)11
q3) the number of natural numbers n such that [(n+1)^2/n+7] is an integer is,
a)4
b)6
c)5
d)none of these
q4) a natural number satisfies the following conditions
A) NUMBER IS HAVING ALL THE 9's
B) IT IS DIVISIBLE BY 13
how many digits are there in N ?
a)5
b)6
c)7
d)8
@amresh_maverick said:A sum of money 2310 is due to be repaid at the end of two yrs. If it has to be repiad in two equal annual instalments (the instalments being paid at the beginning of the yr) at 10% p.a. compounded annually. Find the value of each instalment?1210100011001331
I am getting 1331. Please tel me where I am going wrong.
My approach:-
Initial sum = Rs 2310
Let instalment paid in each year be Rs P.
Amount after 1 year = 2310*(1+10/100) = 2541
Amount to be paid after 2 years = (2541 - P)*(1+10/100)
for both instalments to be equal::- (2541 - P)*(1+10/100) = P
which gives P = 1331.
My approach:-
Initial sum = Rs 2310
Let instalment paid in each year be Rs P.
Amount after 1 year = 2310*(1+10/100) = 2541
Amount to be paid after 2 years = (2541 - P)*(1+10/100)
for both instalments to be equal::- (2541 - P)*(1+10/100) = P
which gives P = 1331.
@amresh_maverick said:no bud
let,the first instalment be x
the other instalment=(2310-x)
rate of interest =10% p.a
so, 1.1*(2310-x)=x
or,x=1210
sorry...calculation mistake
the other instalment=(2310-x)
rate of interest =10% p.a
so, 1.1*(2310-x)=x
or,x=1210
sorry...calculation mistake
@TONYMBA said:let,the first instalment be xthe other instalment=(2310-x)rate of interest =10% p.aso, 1.1*(2310-x)=xor,x=1210sorry...calculation mistake
still not correct , if this was this simple why would I post here ? just imagine
@amresh_maverick said:still not correct , if this was this simple why would I post here ? just imagine
i dont want to live in this planet anymore....
Find the smallest number which when divided by 7,8 and 9 leaves a remainder of 5, 4 and 2. Please solve with explanation. 😃
@Logrhythm said:26620??100,204,412,828,1660,3324,6652,13308,26620or ((((((((((((((((100+2)*2)+2)*2)+2)*2)+2)*2)+2)*2)+2)*2)+2)*2)+2)*2) = 26620 i don't knw if what i did is wht the question required #toosleepy
8th city =Rs 204 (half =100+2, full =204)
7th city =Rs 404
6th city =Rs 804
.......................
.........................
the hundred's is following the sequence of 2,4,8..........
therefore,
1st city = Rs 25604
initial money with ashok was Rs 25604
I hope it's correct.
@amresh_maverick said:A sum of money 2310 is due to be repaid at the end of two yrs. If it has to be repiad in two equal annual instalments (the instalments being paid at the beginning of the yr) at 10% p.a. compounded annually. Find the value of each instalment?1210100011001331
Is 1331 the right answer? Sorry but I am weak in this topic 
...so wanted to know the answer 
...so wanted to know the answer @amresh_maverick said:A sum of money 2310 is due to be repaid at the end of two yrs. If it has to be repiad in two equal annual instalments (the instalments being paid at the beginning of the yr) at 10% p.a. compounded annually. Find the value of each instalment?1210100011001331
x+1.1x =2310 => x=1100
@DharamPaaji said:Is 1331 the right answer? Sorry but I am weak in this topic ...so wanted to know the answer
Nahi bhai , this is also not correct. M also not gud in this.
A student was given 8 two-digit numbers to add, by a teacher. If the student reversed each number and added the results, the sum of the numbers would be 36 more than the actual sum. Find the excess of the sum of the units digits over that of the tens digits.
@TootaHuaDil said:Find the remainder when n^7-n is divided by 42
(n)(n-1)(n^2+n+1)(n^3+1)
n=3,2 and 1 satisfies remainder as 0
so by mathematical induction
remainder 0