Remainder [24^713+26^713]/625
Number of divisors of form 4n+2 for 240 is.....
@pirateiim478 said:Number of divisors of form 4n+2 for 240 is.....
4n+2 = 2*(2n+1 )
Its nothing but finding odd divisors of 120 = 3*5*2^3 ==> odd div = 4??
so ,no.of divisors of the form 4n+2 for 240 is 4??
Its nothing but finding odd divisors of 120 = 3*5*2^3 ==> odd div = 4??
so ,no.of divisors of the form 4n+2 for 240 is 4??
@aimiift2012 said:N is the largest 3-digit number which when divided by 11 and 9 leaves 9 and 7 as the respective remainders. The sum of the digits of N is
N= 11a+9 = 9b+7 here, diff is same 😃 LCM model 1 ==> N = LCM ( 11, 9) *K - 2 = 99K-2
u need largest number less than 1000 so, k=10 ==> N=990-2=988
@nagpal9 said:dinesh is seated 7th from left and satish is seated 12 from right. when they interchange their positions, dinesh is seated at 22nd from left. how many people are there?
21+11+1=33
@nagpal9 said:one person is wearing black and white shoes as his pair.If he is having 20 white and 20 black shoes. what will be the least number of time he has try to take his correct pair of shoes??
least-2 ,max of 21 trails
@nagpal9 said:A fuel dealer mixes two brands of fuel which cost in the ratio 2:3. A solution of 30% brand A with brand B yields profit of 10% when sold at rs 297. what is the cost of brand B?
cost of A = 2x,
cost of B = 3x,
now 0.3 A+ 0.7 B = 297 ==> which yields 10% profit
==> 1.1 [ 0.3*2x+ 0.7 *3x] = 297 ==> 2.7x = 277 ===> 3x = 277*3/2.7= 300 (approx)
cost of B = 3x,
now 0.3 A+ 0.7 B = 297 ==> which yields 10% profit
==> 1.1 [ 0.3*2x+ 0.7 *3x] = 297 ==> 2.7x = 277 ===> 3x = 277*3/2.7= 300 (approx)
@getupsid
@getupsid said:any tricks to make additions fast in DI??????
Bhaai ek aur sirf ek hi trick hai DI banaane ka..
Jitna zada ho sake question banao ................
Trust me ther is no trick no shortcut........
you get screwed you do better...
@ananyboss said:@getupsid Bhaai ek aur sirf ek hi trick hai DI banaane ka..Jitnazada ho sake question banao ................Trust me ther is no trick no shortcut........you get screwed you do better...
Quality not Quantity..:)
@Budokai001 said:A and B are the two opposite ends of a swimming pool and the distance between them is420 metres. Ankur and Manu start swimming towards each other at the same time from A and B,with speeds in the ratio 5 : 9 respectively. As soon as any of them reaches an end, he turns backand starts swimming towards the other end. At what distance (in metres) from A will they meet whenManu is in his 13th round? Note: A to B is considered one round and B to A another round.(a) 405 (b) 330 (c) 240 (d) 280
Time taken Manu to complete 12 rounds = 420/ 9x * 12 = 560/ x sec [ Now he will be at the position where he started i.e., point B ]
After 560/x Ankur position of ankur = 420*n = 5x *560/x = 20/3 = 6 + 2/3 [ after 6 he ll be at initial point where he started i.e., at point A] + 2/3 is 2/3 * 420= 280 metres..
Now after 560/x sec..ankur and manu are at a distance of 420-280 = 140..now both swim in opposite direction ==> relative speed = 14x
now 140 = 14x* t ==> t = 10/x ..now to find the meeting point ..find distance travelled by manu in 10/x sec ==> d= 9x* 10/x ==> 90 metres..so they meet at a distance of 420-90 =330from point A
After 560/x Ankur position of ankur = 420*n = 5x *560/x = 20/3 = 6 + 2/3 [ after 6 he ll be at initial point where he started i.e., at point A] + 2/3 is 2/3 * 420= 280 metres..
Now after 560/x sec..ankur and manu are at a distance of 420-280 = 140..now both swim in opposite direction ==> relative speed = 14x
now 140 = 14x* t ==> t = 10/x ..now to find the meeting point ..find distance travelled by manu in 10/x sec ==> d= 9x* 10/x ==> 90 metres..so they meet at a distance of 420-90 =330from point A
@ravi.theja said:methhod bhai?? dono OA
Rem (24^713+26^713/25) is (-1)^713+(1)^713/25 = 0
So Remainder [24^713+26^713]/625 =0
So Remainder [24^713+26^713]/625 =0
@pirateiim478 said:Rem (24^713+26^713/25) is (-1)^713+(1)^713/25 = 0So Remainder [24^713+26^713]/625 =0
bhai any other method like using (25-1)^n + (25+1)^n??
@Zedai said:In a number system 12, 20,24 are in an arithmetic progression. What is the base of the number system?
(12)b = b+2 20base b = 2b , 24 base b = 4 + 2b in a.p ==? 2* 2b =b+2+2b+4 ==> 4b=3b+6 ==> b=6
@ravi.theja said:(12)b = b+2 20base b = 2b , 24 base b = 4 + 2b in a.p ==? 2* 2b =b+2+2b+4 ==> 4b=3b+6 ==> b=2
b+2 ; 2b ; 2b + 4 are in AP. i.e, 4 = b - 2. So, b = 6, I suppose. What's the OA btw.?
Grass in lawn grows equally thick and in a uniform rate. It takes 40 days for 40 cows and 60 days for 30 cows to eat the whole of the grass. How many days does it take for 20 cows to do the same?
@vbhvgupta said:Grass in lawn grows equally thick and in a uniform rate. It takes 40 days for 40 cows and 60 days for 30 cows to eat the whole of the grass. How many days does it take for 20 cows to do the same?
80.?