@bs0409 said:7/16???Can be solved using graphical method.......
@pirateiim478 said:@bs0409 bhai ye graphical method sikha do bahut bar suna hai!!
even i have also tried may times but couldn't get the proper approach.. whr can we apply this??
@viewpt said:Q: 47^41^37^59 div 67 R=? ?
25??...
sir aise khatarnak rem waale question kahan se laate ho..??
@viewpt said:100!/3 no. of three's are 48so for no. of nines= 48/2=24one more method was thr not able to recall...books touch kiye hue 1/2 yr ho gya
Good approach. I did it other way like for 101! has 24 zeroes. So naturally 101!-1 has 24 9's by analogy smaller numbers!!
Books touch kiya to bhi use nahi hai!! Bahut practice karna hai kidar bhi ho and vo bhi consistent,daily practice
Saying with experience!!
Books touch kiya to bhi use nahi hai!! Bahut practice karna hai kidar bhi ho and vo bhi consistent,daily practice
Saying with experience!!@ravi.theja said:root 5
Approach
@pirateiim478 said:Good approach. I did it other way like for 101! has 24 zeroes. So naturally 101!-1 has 24 9's by analogy smaller numbers!!Books touch kiya to bhi use nahi hai!! Bahut practice karna hai kidar bhi ho and vo bhi consistent,daily practice Saying with experience!! Approach
bhai centre C( 2,0 ) Q (1,2) ==> r =CQ= root 5...nw join 2 ends of chord at centre.it makes angle 60..nw draw perpndclr bisectr from centre on to PQ..and mark as R ..let PR=QR=x
now sin30 = x/root5 ==> x= root 5 /2 ==> length of chord 2x= root5
now sin30 = x/root5 ==> x= root 5 /2 ==> length of chord 2x= root5
@heenalove said:solve this: A& b are frnds nd decif to meet btwn 1 pm nd 2 pm on given day with condition whoever arrives 1st will not wait for the other mor thn 15 min what is the probablity that they vil meet that day .
@viewpt said:even i have also tried may times but couldn't get the proper approach.. whr can we apply this??
@pirateiim478 said:@bs0409 bhai ye graphical method sikha do bahut bar suna hai!!
Check the shaded part : this is the condition when they meet.
So, Area of non - shaded part = 45*45*0.5*2 = 45*45
Total Area = 60*60
So, Probability = Area of shaded / Total Area = 1 - ((45*45)/(60*60)) = 7/16
@Aizen said:Check the shaded part : this is the condition when they meet.So, Area of non - shaded part = 45*45*0.5*2 = 45*45Total Area = 60*60So, Probability = Area of shaded / Total Area = 1 - ((45*45)/(60*60)) = 7/16
agar yahan b/w 1 pm to 4 pm hota toh??
a,b,c,d are positive real numbers such that a^2+b^2+c^2+d^2=100. Find maximum value of sum a+b+c+d?
@pirateiim478 said:a,b,c,d are positive real numbers such that a^2+b^2+c^2+d^2=100. Find maximum value of sum a+b+c+d?
20.??
Thnx aizen 😃
@pirateiim478 said:a,b,c,d are positive real numbers such that a^2+b^2+c^2+d^2=100. Find maximum value of sum a+b+c+d?
it has to be 20 i guess.
@The_Loser: yes its 20. 6+4+6+4.
@sbharadwaj said:20.??
@The_Loser said:it has to be 20 i guess.
@amitgovil said:@The_Loser: yes its 20. 6+4+6+4.
It is 20. For maximum value all of them shld be equal.So, a=b=c=d=5. @amitgovil not 6,4,6,4.
In a number system 12, 20,24 are in an arithmetic progression. What is the base of the number system?
In a number system 12, 20,24 are in an arithmetic progression. What is the base of the number system?
@pirateiim478 said:a,b,c,d are positive real numbers such that a^2+b^2+c^2+d^2=100. Find maximum value of sum a+b+c+d?
a=b=c=d=5
5^2+5^2+5^2+5^2=100
5+5+5+5=20?