N = DA+15 10N = DB+6 10N = 10DA+150, but as the remainder is 6, divisor or multiple of divisors =144 144 = 3^2*2^4, number of factors are 15 but 1,2,3,4,6,8,9,12 cannot be the divisors, hence 15-8 = 7
There are total 6! = 720 ways of sitting around a table.
Now if a neighbor is sitting to left of a person, there will be another arrangement in which the neighbor person sits right to him. This will hold good for all the persons who could become a neighbor one by one.
Therefore the required arrangement will be 720/2 = 360..
Straight lines can intersect among themselves in 8C2 waysCircles can intersect among themselves in 2*4C2 ways Max point of intersection possible bet circles and stlies = 2*8*4 8C2 + 4*3 + 2*8*428+12+64 =104 ?
Why did you add 8c2 and 2*4c2?? I think question only intersection of circles and straight lines. Correct me if iam wrong
Why did you add 8c2 and 2*4c2?? I think question only intersection of circles and straight lines. Correct me if iam wrong
We are trying to maximize the number of intersection bro . Thats y
Here we add those 3 considering all those points are different
( Assuming that points of intersection of straight lines alone are different from point of intersection of circles alone which are different from point of intersection of straight lines&circles;t. Hope you understand..
@pirateiim478@getupsid Just googled and found its 104 indeed. So i guess 76 which was given in book is wrong buddy
