Yar what is the concept behind it....like for some other no's also do we have to divide those no by 25 to get the last 2 digit no????
No actually the last two digits are calculated when remainder with 100 is taken
what is 100?
100 = 4*25
since the above term is already divisible by 4, we can directly take the remainder by 25 because when you apply chinese remainder theorem, it boils down to the same
Yar what is the concept behind it....like for some other no's also do we have to divide those no by 25 to get the last 2 digit no????
find last digit ==> div by 10 then remainder is ur last digit find last two digits==> div by 100 then remainder is ur last two digits simlrly by 1000 and so on..
@Estallar12 it is a question from last year's aimcat.....just posted it to make all of us remember that even easy question appear in the exam, it is now always about the tough questions.. :)
Ye it is 49@Estallar12 it is a question from last year's aimcat.....just posted it to make all of us remember that even easy question appear in the exam, it is now always about the tough questions..
Oh. :woot:
Thanks! :)
Easy questions should be sandwitched anyway. Good.!