@sails 22 and 5 both
@TootaHuaDil said:n1q1+13=n2q2+1n1(4q2-5q1)=60n1= all the factors of 60 such that n1>13
so u sayin answer fr this s more than 1??
Suppose, the seed of any positive integer n is defined as follows:
seed(n) = n, if n = seed(s(n)), otherwise,
where s(n) indicates the sum of digits of n.
seed(n) = n, if n = seed(s(n)), otherwise,
where s(n) indicates the sum of digits of n.
For example,
seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.
How many positive integers n, such that n
seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.
How many positive integers n, such that n
1)39 2)72 3)81 4)108 5)55
please share the approach too
@somnathbhatta said:Suppose, the seed of any positive integer n is defined as follows:seed(n) = n, if n = seed(s(n)), otherwise,where s(n) indicates the sum of digits of n. For example,seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.How many positive integers n, such that n 1)39 2)72 3)81 4)108 5)55 please share the approach too
check for all mutiples of 9 less than 500..as 9 is one of those number where if you add up the digits of its mutiple it will be a multiple of 9...ex..27=2+7=9..so 55 is the answer
@somnathbhatta said:Suppose, the seed of any positive integer n is defined as follows:seed(n) = n, if n = seed(s(n)), otherwise,where s(n) indicates the sum of digits of n. For example,seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.How many positive integers n, such that n 1)39 2)72 3)81 4)108 5)55 please share the approach too
All multiples of 9
this is nothing but digital sum
@Logrhythm said:@bs0409@somnathbhatta - No. it is 0.2 or 1/5 it can be done like this: 0.33333.... is 1/3 in base 10let this be 0.xyz.... in base 6, this can be written as x/6+y/36+z/216+.... = 1/3by observation we can see that at x = 2 and y=z=...=0 - LHS=RHShence 1/3 in base 10 is 1/5 in base 6
From what I understand, The question asks 0.333333 in base 10 to be converted to base 6.
I agree that answer is 0.2 in base 6. But how can you say 0.2 in base 6=1/5 in base 6..??
I agree that answer is 0.2 in base 6. But how can you say 0.2 in base 6=1/5 in base 6..??
@somnathbhatta said:Suppose, the seed of any positive integer n is defined as follows:seed(n) = n, if n = seed(s(n)), otherwise,where s(n) indicates the sum of digits of n. For example,seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.How many positive integers n, such that n 1)39 2)72 3)81 4)108 5)55 please share the approach too
It will be 55. All multiples of 9 have seed as 9. So count multiples of 9 under 500. (495-9/9)+1 = 55
a, b, c and d are four positive real numbers such that a^2 + b^2 + c^2 + d^2 = 100. What is the maximum possible value of the sum of a, b, c and d?
@sails said:how?? according to options given only 36 matches
option (d) Can't be determined uniquely :D
@bs0409 said:From what I understand, The question asks 0.333333 in base 10 to be converted to base 6.I agree that answer is 0.2 in base 6. But how can you say 0.2 in base 6=1/5 in base 6..??
i assumed that the options were given in base 10....because if that is not the case then it is involving double conversions, which i (very conveniently) assumed might not be the case. 😃
@bs0409 but the conversion gives .01555 in base 6 but don't u think .16666 is more closser than .2 ?
@Logrhythm said:i assumed that the options were given in base 10....because if that is not the case then it is involving double conversions, which i (very conveniently) assumed might not be the case.
OK. According to your thought process, You are right.
I assumed something different.
" Convert 0.33333333 in base 6 to a fraction in base 6 only"
It is just conversion between fraction and decimal in the same base system, Not some inter base conversion.
In that case can anybody confirm whether 3/5 is right or not?
I assumed something different.
" Convert 0.33333333 in base 6 to a fraction in base 6 only"
It is just conversion between fraction and decimal in the same base system, Not some inter base conversion.
In that case can anybody confirm whether 3/5 is right or not?
@somnathbhatta said:@bs0409 but the conversion gives .01555 in base 6 but don't u think .16666 is more closser than .2 ?
Check this: http://www.wolframalpha.com/input/?i=1%2F3+in+base+6
0.333.......... OR (1/3) in base 10 is equal to 0.2 in base 6.
Plz check your calculation again.
0.333.......... OR (1/3) in base 10 is equal to 0.2 in base 6.
Plz check your calculation again.
@bs0409 said:OK. According to your thought process, You are right.I assumed something different." Convert 0.33333333 in base 6 to a fraction in base 6 only"It is just conversion between fraction and decimal in the same base system, Not some inter base conversion.In that case can anybody confirm whether 3/5 is right or not?
yeah 3/5 in base 6 is 0.33333 in base 6
but we need to find the 0.333 (base 10) equivalent in base 6, that has to be 0.2
i guess this is a debatable question.
@somnathbhatta said:Suppose, the seed of any positive integer n is defined as follows:seed(n) = n, if n = seed(s(n)), otherwise,where s(n) indicates the sum of digits of n. For example,seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.How many positive integers n, such that n 1)39 2)72 3)81 4)108 5)55 please share the approach too
55?? Multiples of 9 ??
@bs0409 i did the conversion manually last tym with 0.3333333 (seven 3's after decimal). it gave 0.15555555535523. and goes on .. checked my calculation on ur link too .. same result as mine.. now if u increase the number of 3's there is a rounding of occuring same is the case with 1/3. u can check it too .. seven or eight 3's ..
might be my approach to the specific prob is wrong
.. but the conversion is just fine . 
might be my approach to the specific prob is wrong
.. but the conversion is just fine .
@TootaHuaDil said:4. A certain number 'C' when divided by N1 it leaves a remainder of 13 and when it is divided by N2 it leaves a remainder of 1, where N1 and N2 are the positive integers. Then the value of N1+N2 is, if N1/N2=5/4(a) 36(b) 27(c)54(d) can't be determined uniquely
went from options..is it CBD ???