Official Quant thread for CAT 2013

MBA CAT 2024
12983
@sails said:
is there any method of recieveing a mail every time a new question is posted here...if yes then please tell me how..
Yes. You can surely do that.
See 'Subscribe for Emails' just below the text written as 'Official Quant thread for CAT 2013' in the upper part of this page. Click on that. You'll get subscribed for this thread.
12984
is there a chapter on Simple and Compound Interest in NCERT books? If yes, which class and which chapter? thanks.
12985
@cadmium

thanks mate..:)

12986

please tell me how can I

1. find the remainder when 2^729 is divided by 11
2. find the remainder when 21^21^21 is divided by 11

12987
@krittikau Remainder theorem..Arun sharma is good for this..

12988
@nramachandran don't u think these are obsolete now a days..whatever material i have from time and arun sharma..they have standard quant and DI..DI this year has been a menace for me be it cat or nmat..do i have any suggestion on some materials for QA and DI and even critical/verbal reasoning..suggestion puys!!
12989
@krittikau said:
please tell me how can I1. find the remainder when 2^729 is divided by 112. find the remainder when 21^21^21 is divided by 11
refer to arun sharma. the answers are as follows
1. 6
2. 10
explanation for 1.
2^5=32
2^729=32^145*2^4
write 32 as (33 - 1).since 33 is a multiple of 11 the only term that is left is -1*2^4. write -1 as 10.
10*2^4=160
160%11=6
explanation for 2
write 21 as 22-1
therefore the term becomes (22-1)^21^21
since 22 is a multiple of 11 the only term remaining is -1^21^21 =-1
-1/11=10
12990
@krittikau said:
please tell me how can I1. find the remainder when 2^729 is divided by 112. find the remainder when 21^21^21 is divided by 11
e(11) =10

729mod10=9

so 2^729mod11=2^9mod11=6

similarly 21^21mod10=1

so 21^1mod11=10

if u don't know about euler's totient, go through this article http://totalgadha.com/mod/forum/discuss.php?d=6268
12991
@nikemen thanks

12992

In how many ways 180 can be written as product of 2 coprime factors?


@krittikau Please click on like if you want to say thank you. No need of creating seperate post for that.
12993
@pirateiim478 4 i guess...
12994
@pirateiim478 said:
In how many ways 180 can be written as product of 2 coprime factors?@krittikau Please click on like if you want to say thank you. No need of creating seperate post for that.
4
1*180
45*4
36*5
20*9
12995
@veertamizhan said:
A man lends 9000 at r rate of interest for the first year. Next year he doubles it and in the third year he triples it and so on. If he gets back 15000 after a period of three years, what is the rate of interest in the first year.options - 9%, 9.09%, 10%, 11.11% 12.5%can I have a less calculation intensive method? thanks.
9000+9000(6x/100)=15000
6x/100=2/3
x=9%
12996
@pirateiim478 said:
In how many ways 180 can be written as product of 2 coprime factors?@krittikau Please click on like if you want to say thank you. No need of creating seperate post for that.
1,180
4,45
5,36
9,20
Total 4 cases
12997
@nirzone does any1 agree with me..and awaiting your valuable inputs

12998
@nirzone said:
@pirateiim478 4 i guess...
4 it is. Formula is 2^n/2 where n is number of distinct factors. Similarly find number of sets of factors of 180 where both of them are coprime
12999
@krittikau
@krittikau said:
please tell me how can I1. find the remainder when 2^729 is divided by 112. find the remainder when 21^21^21 is divided by 11
1)6
2)10
13000
@pirateiim478 or just do 2 to the power (n-1), n is number of diffrent prime factors..

13001

Find the remainder when the sum 2^100+2^200+2^300..+...+..2^10000 is divided by 7
a) 2
b) 0
c) 1
d) 6
e) None of these.

13002
@nirzone said:
@pirateiim478 or just do 2 to the power (n-1), n is number of diffrent prime factors..
😁 Both are same!! Try other question in same post.
One more question=> How many right angled triangles are there in which
1. One leg is 12
2. Hypotenuse will be 12