Ye clock wale ques ka koi formula hota h kya
Q ) what is the angle between hr hand and minute hand at 4:16 ??
Koi mod laga k formula h to plz provide link OR explain long approach se bachna h mujhe .
@AIM_IIM_2013 said:Ye clock wale ques ka koi formula hota h kyaQ ) what is the angle between hr hand and minute hand at 4:16 ??Koi mod laga k formula h to plz provide link OR explain long approach se bachna h mujhe .
|11/2m-30h|
@hedonistajay said:A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train??
97.77 miles?
In 50 miles, the train saves 45 minutes.
50/(3s/5) - 50/s = 3/4
2*50/3s = 3/4
s = 8*50/9
So initial speed = 50 * 8/9 miles per hour
Distance covered at this speed = 400/9 miles
New speed = 50 * 8/9 * 3/5 = 80/3 miles per hour
Distance covered at this speed = 160/3 miles
Total distance = 880/9 miles = 97.77 miles
In 50 miles, the train saves 45 minutes.
50/(3s/5) - 50/s = 3/4
2*50/3s = 3/4
s = 8*50/9
So initial speed = 50 * 8/9 miles per hour
Distance covered at this speed = 400/9 miles
New speed = 50 * 8/9 * 3/5 = 80/3 miles per hour
Distance covered at this speed = 160/3 miles
Total distance = 880/9 miles = 97.77 miles
@hedonistajay Let the speed of train be s
Initially train covers its journey in 3 hrs
Had the fault occured at 50miles later,it wud hav taken 45min less ==>With reduced speed train covers 50miles in 45min
= (3s/5) *(45/60)=50
=> s= 1000/9 miles/hr
total distance= 1000/9 (1+ 6/5)= 1000 * 11/5= 244.4 mles
Initially train covers its journey in 3 hrs
Had the fault occured at 50miles later,it wud hav taken 45min less ==>With reduced speed train covers 50miles in 45min
= (3s/5) *(45/60)=50
=> s= 1000/9 miles/hr
total distance= 1000/9 (1+ 6/5)= 1000 * 11/5= 244.4 mles
@hedonistajay said:A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train??
@hedonistajay said:A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train??
244.4 miles. 
@AIM_IIM_2013 said:Ye clock wale ques ka koi formula hota h kyaQ ) what is the angle between hr hand and minute hand at 4:16 ??Koi mod laga k formula h to plz provide link OR explain long approach se bachna h mujhe .
Angle at 4'o clock is = 120 degrees
Minute hand moves at 6 degree/min
Hour hand moves at 1/2 degree/min
Relative speed = 11/2 degree/min
After 16 mins,
Angle between them = 120 - 11/2*t = 120 - (11/2)*16 = 120 - 88 = 32 ?
@AIM_IIM_2013 said:Ye clock wale ques ka koi formula hota h kyaQ ) what is the angle between hr hand and minute hand at 4:16 ??Koi mod laga k formula h to plz provide link OR explain long approach se bachna h mujhe .
ANGLE = |30H - (11/2)M|
=> Angle = |30*4 - 11*16/2| = 32 degrees.
@grkkrg said:97.77 miles?In 50 miles, the train saves 45 minutes.50/(3s/5) - 50/s = 3/42*50/3s = 3/4s = 8*50/9So initial speed = 50 * 8/9 miles per hourDistance covered at this speed = 400/9 milesNew speed = 50 * 8/9 * 3/5 = 80/3 miles per hourDistance covered at this speed = 160/3 milesTotal distance = 880/9 miles = 97.77 miles
@Estallar12 said:244.4 miles.
@hedonistajay said:A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before the occurrence of fault in engine. It travels at this speed for 2 hours to reach at its destination. If the fault had occurred 50 miles later on, the train would have reached its destination 45 minutes early. Find the distance traveled by the train??
Suppose Actual Speed = X so, it will cover X distance in 1 hour.
After Fault, Reduced Speed = 3x/5.
=> Dist. travelled = (3x/5)*2 = 6x/5 ----> This is the rest of the Dist.
Thus, Total Dist. = x + 6x/5 = 11x/5 ....... ( i )
If fault had occurred at (x + 50), then -
=> (3x/5)*5/4 = 6x/5 - 50 ...... ( ii )
Subtracting ii from i -
=> 6x/5 - 3x/4 = 50
=> 9x/20 = 50
Thus, x = 1000/9
So, Total Distance = 11x/5 = 244.44 miles. :D
@anurag1701 said:@hedonistajay Let the speed of train be s Initially train covers its journey in 3 hrsHad the fault occured at 50miles later,it wud hav taken 45min less ==>With reduced speed train covers 50miles in 45min= (3s/5) *(45/60)=50 => s= 1000/9 miles/hrtotal distance= 1000/9 (1+ 6/5)= 1000 * 11/5= 244.4 mles
@hedonistajay earlier did mistake while calculating total distance 
@Estallar12 said:=> (3x/5)*5/4 = 6x/5 - 50 ...... ( ii )
This equation doesn't seem right. :|
(6x/5 - 50) at 3x/5 doesn't take 45 minutes less.
(6x/5 - 50) at 3x/5 and (x + 50) at x do.
(6x/5 - 50) at 3x/5 doesn't take 45 minutes less.
(6x/5 - 50) at 3x/5 and (x + 50) at x do.
@grkkrg said:This equation doesn't seem right. (6x/5 - 50) at 3x/5 doesn't take 45 minutes less.(6x/5 - 50) at 3x/5 and (x + 50) at x do.
@AIM_IIM_2013 said:Ye clock wale ques ka koi formula hota h kyaQ ) what is the angle between hr hand and minute hand at 4:16 ??Koi mod laga k formula h to plz provide link OR explain long approach se bachna h mujhe .
Angle covered by the hour hand
At 4 o clock, anggle = 4*30 = 120
At 4:16, additional angle covered = 120 +(16*0.5) = 128 This is because hour hand covers 0.5 degree each minute, so in 16 minutes it covers an additional 8 degrees
Angle covered by minute hand = 16*6 = 96
Angle between them = 128-96 = 32 degrees
@rkshtsurana said:left at 5:a
return at 6:bequate hour hand at 5:a to minute hand when it was 6:a
150 + a/2 = 6b
similarly
180 + b/2 = 6a
solve two equations..we ll get a and b
Bro,
I am unable to understand your approach. Can you please elaborate?
You have enough coins of 1, 5, 10, 25 paise. How many combinations are possible to make 50 paise?
a) 52
b) 49
c)44
d) 45
a) 52
b) 49
c)44
d) 45