Official Quant thread for CAT 2013

@hari_bang said:
is dis sortcut?always?
yea..

few other shortcuts:

|x| + |y| + |z| = a has total number of integral solutions = 4*a^2 + 2.
|x| + |y| = p has a total number of integral solutions = 4*p.
|X| + |Y| = a; then 2*a^2 is the area enclosed between these lines.
|x-a| + |y-b| = k has 4k integral solutions.

Guys stuck on this one:-

Que)Given that x^2+y^2=14x+6y+6 what is the largest possible value of 3x+4y?
@Enceladus said:
yea..few other shortcuts:|x| + |y| + |z| = a has total number of integral solutions = 4*a^2 + 2.|x| + |y| = p has a total number of integral solutions = 4*p.|X| + |Y| = a; then 2*a^2 is the area enclosed between these lines. |x-a| + |y-b| = k has 4k integral solutions.
:)
@bhatkushal said:
Guys stuck on this one:-Que)Given that x^2+y^2=14x+6y+6 what is the largest possible value of 3x+4y?
is it 5?
@bhatkushal said:
Guys stuck on this one:-Que)Given that x^2+y^2=14x+6y+6 what is the largest possible value of 3x+4y?
or 31?
@hari_bang said:
is it 5?
no the options are:-
1)72 2)73 3)74 4)75
Q find 3x^2.y^2 if x and y are integers such that y^2+3x^2.y^2=30x^2+517...
@bhatkushal said:
Guys stuck on this one:-Que)Given that x^2+y^2=14x+6y+6 what is the largest possible value of 3x+4y?
My take is 89.

x^2 + y^2 - 14x - 6y - 6 = 0.
=> (x - 7)^2 + (y - 3)^2 = 64.
This represents the equation of a circle with center at (7,3) and radius = 8.
Hence, max (x) = 7+8 = 15.
and max (y) = 3+8 = 11.
=> max (3x + 4y) = 3*15 + 4*11 = 45 + 44 = 89.

Q find all the number triplets (x,y,z) such that when any of these is added to the product of other two result is 2...

@Enceladus said:
My take is 89. x^2 + y^2 - 14x - 6y - 6 = 0.=> (x - 7)^2 + (y - 3)^2 = 64. This represents the equation of a circle with center at (7,3) and radius = 8. Hence, max (x) = 7+8 = 15. and max (y) = 3+8 = 11. => max (3x + 4y) = 3*15 + 4*11 = 45 + 44 = 89.
@Enceladus how can you take two diffrent points and add the values....
assuming that 3x +4y is aline it will pass through a single point
that could be (7,11) or (15,3) but in both cases the max value I can get is 65 and 67.....no where near the options

@bhatkushal said:
no the options are:-1)72 2)73 3)74 4)75
i cmpred with dis eqs--
x2+y2+2gx+2fy+c=0;
find radius.......bt i dint get any op
@hari_bang said:
i cmpred with dis eqs--x2+y2+2gx+2fy+c=0;find radius.......bt i dint get any op
try doing it this way
x2-14x+y2-6y=6;

x2-14x+49+y2-6y+9=6+49+9;
(x-7)^2+(y-3)^2=64;
hence centre ofcircle is (7,3) with radius 8.....
@bhatkushal said:
let a,b,c be positive real numbers.Determine the largest number of real roots that the following three polynomials may have among them:ax^2+bx+c,bx^2+cx+a,cx^2+ax+b...
@bhatkushal said:
Q find 3x^2.y^2 if x and y are integers such that y^2+3x^2.y^2=30x^2+517...
anybody on how to proceed on this one.....
@bhatkushal said:
Q find 3x^2.y^2 if x and y are integers such that y^2+3x^2.y^2=30x^2+517...
taking x=2

==> 13y^2=637
==> y^2=49

=> 3x^2y^2 = 3*4*49 = 588
@bhatkushal said:
try doing it this way x2-14x+y2-6y=6;x2-14x+49+y2-6y+9=6+49+9;(x-7)^2+(y-3)^2=64;hence centre ofcircle is (7,3) with radius 8.....
bt by dis we dint get any optn...
@bhatkushal said:
try doing it this way x2-14x+y2-6y=6;x2-14x+49+y2-6y+9=6+49+9;(x-7)^2+(y-3)^2=64;hence centre ofcircle is (7,3) with radius 8.....
wht is ans?

Q A tennis player computes her win ratio by dividing the number of matches she has won by the total number of matches played by her.At start of the weekend her win ratio is 500.

During weekend she plays 4 matches, winning three and loosing one.At the end of weekend her win ratio is greater than 503.What is largest number of matches she could have won before the weekend began.........
@bhatkushal said:
Q A tennis player computes her win ratio by dividing the number of matches she has won by the total number of matches played by her.At start of the weekend her win ratio is 500.During weekend she plays 4 matches, winning three and loosing one.At the end of weekend her win ratio is greater than 503.What is largest number of matches she could have won before the weekend began.........
options?

No options given that would have made life a little easy......